bhai kyoki p1 ki value 1 h means p1 ka binary code m hame aise no chahiye jiske binary representation m 1 aaya suppose 0001 =p1 , D3=0011;D4=0100 ye nhi h kykio iske binary representation m 1 nhi aa rha h ,D5=0101 so ye h kyoki last value m h1 samjha bhai
Kyonki D5 to pahle se hi 1 hai Aur D3 Aur D7 zero hai Hamen no error ke liye even parity chahie Iska matlab D3 Aur D7 MI se kisi mein bhi error ho sakta hai
Very helpful and thanks madamjii
Thanks for your words
Thanku... aapko samjhane ka tarika bahut mst hai
Thanks for your words
Mam I don't understand why P2 did not select D5 .....what's the logic behind it...
Same goes for other
🙏🙏🙏🙏
because when calculating p2, we accept the first 2 bits then skip 2 bits and so on.
Mem aap bahut acha samjhate ho. Thank you soo much..
Glad to help you
Thanks mam🙏🙏
Glad to help you
Thanks man
Glad to help you
mam ye kaise pta chalega ki transmitter ne data even parity mai send kiya hai
kya ye question mai diya hoga
Ma'am I also don't understand why for p2 not selected D5
for P2 you said there may be error either in D3 or D7 why not D6? pls explain
Madam, Hamming code it is error correcting method. It is not just detecting method
madam why P2 parity will not choose D5 data instead taken D6 data (3 :00 minute)
bhai kyoki p1 ki value 1 h means p1 ka binary code m hame aise no chahiye jiske binary representation m 1 aaya suppose 0001 =p1 , D3=0011;D4=0100 ye nhi h kykio iske binary representation m 1 nhi aa rha h ,D5=0101 so ye h kyoki last value m h1 samjha bhai
wow keep it up
according to this question error found at p4p2p1(010) =2 bit then how can error at d3. plz explain
Kyonki D5 to pahle se hi 1 hai
Aur D3 Aur D7 zero hai
Hamen no error ke liye even parity chahie
Iska matlab D3 Aur D7 MI se kisi mein bhi error ho sakta hai
Thankyou
Glad to help you
Nice maam
Thank you for your words
With regards
LEARN AND GROW
Mam ager hmare paas 11 bit haaming code ho tab p1 p2 p3 or p4 kisko chech krta h
Jo p1 k8 next data bit hoti