Tensile Test
ฝัง
- เผยแพร่เมื่อ 26 ม.ค. 2013
- Basic principle and practical procedure of the tensile test on ductile metallic materials
- Testing machine (Inspekt 200 kN, Hegewald & Peschke Meß- und Prüftechnik GmbH), specimen, extensometer
- Material with yield point phenomenon
- Elastic and plastic behaviour, uniform elongation, necking, fracture
- Yield strength, tensile strength, percentage elongation at fracture
- Material without yield point phenomenon
- Plastic behaviour, proof strength
Responsible for this video: Prof. Dr.-Ing. Rainer Schwab, Hochschule Karlsruhe (Karlsruhe University of Applied Sciences), Germany - วิทยาศาสตร์และเทคโนโลยี
It''s very interesting to see how things work practically instead of just reading it from books.
Exactly
Totally agree.
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No idea why this was in my recommendations, but I watched it and it was interesting. Props for Anneke Reinsperger for speaking English without even the hint of a German accent.
Very clear speaking.
I searched it to see with my eyes what I was studying (for an exam about polymers)
I dont work in material science just needed to learn something for work so I landed on your video. Not only the content of the video is informative but I also find how the entire process is explained is very neat! Thank you for sharing!
This proved to be very helpful in my engineering practical exams .
🙏🏻
I'm studying for the metallurgy exam at university and this video helps a lot to visualize and really understand how the complete process works.
Grande bro
Never quite understood why we always had two different graphs but thanks to this video it's very clear. Great stuff
this is the best video on tensile testing and strain on TH-cam
The best video I ever saw on this, keep it up! thank you for showing the curve as the test proceeds..
Finally some really good videos on materials testing. Thanks!!
This video is really well made, thank you for making it. Finally some really good videos on materials testing. Thanks!!.
thank you so much for this video, while my professor has excellent knowledge we learn little so these videos are a lifesaver.
Congratulations for your work, this is very helpful for beginners/students and experts. :)
This is an insteresting and informative video. I'm a Mechanical Engineering and this information clarifies some concepts.
This video is really well made, thank you for making it
Very informative and very proffesional. Thank you
Very informative without any fuzz!
Best Tensile Test video in internet.
Very neat! We just went over these concepts in Solid Mechanics.
What happy as same the company in your industry, I am a China company, good video!
Thanks for your video, it was helped me to finish my final project
This video is very informative and has good explanation. Thank you
Now thats what u call, THE BEST..!!
I’m in 6th grade and this was the first advanced thing I’ve learned like this so thx
nice video.this video is much more suitable for professionals than students. this is widely used in industries. well we had this experiment done during my engg time.
In materials of medium or low ductility, the fracture may take place anywhere along the prismatic part of the specimen, mostly at a weak point. In very ductile materials, the fracture tends to form in the middle region, because there is a certain influence of the grip regions.
thank you so much ,your voice is great ; peace from morocco
Thank you. It really helps me a lot for preparing my exam
More information about yield phenomenon, please. That was very interesting, informative and helpful
Thankyou for uploading this. It was really helpful 🙏
This video is very helpful.
Thank You.
Mechanical stress sigma is always defined as Force F divided by cross sectional area S (or area A). Or more precise: NOMINAL stress sigma equals force F divided by ORIGINAL cross sectional area S zero.
In the video TWO physical quantities are plotted on the vertical axis: Force F on the right side and stress sigma on the left side. Sorry for this, it may be confusing. You get sigma on the left side by simply taking F and dividing it by the original cross sectional area S zero.
The term "elongation" in ASTM 615 indeed is not specified clearly. To my knowledge it can only mean "percentage elongation after fracture". So one has to put the fragments together and then determine the percentage plastic deformation after fracture has occurred.
Amazing video helped me a lot with my project.
Good presentation as well as explanation.
Gajab nice work 🤗🤗❣️
This essay is great because it exemplifies that not all materials work in the same way.
It is a good video, it explains the procedure very well.
Too much helpfull practical knowledge
I'm not even sure how i ended up here but this is fascinating
wow!! thx guys. now i got the practical knowledge from your video.
It is really interesting. Good presentation.
Thank you for posting, it was useful.
Hi,thx for the video,we are a die casting company,we want to change our micro structure to increase our tensile strength from 300 to say 400,can u tell us what we have to add to A356 aluminium to get increased tensile strength
This was highly informative, thank you.
onion
Was millileter the force used or was it milipascals? On the second sample of Al did not show the yield strength. I would like to see 7068 (tennalum) test at 99,000 ksi tensil.
It is interesting to see how steel can deform under load applications in a test. Thank you for made it
very important test, thanks guys!
amazing vid, love it! thanks!
"what would be if we take off tension on the middle of experiment for example on 18mm elongation. and apply it again?" Then an elastic spring-back parallel to the elastic straight line would take place, not to the original length, but to the plastically strained length of about 17.8 mm. On reloading, after elastic behaviour the original curve will be resumed, as if nothing had happened.
Explained in a simple way
Very much informative thanks a lot !!!
"If this rod was a hollow tube or pipe how would the inner diameter be effected? Am I to assume that the point at which it would neck the inner diameter would increase roughly as much as the outer diameter decreases?" We do not have much experience on tensile tests of tubes, but as far as I know, the inner diameter at the neck will decrease, and the outer diameter as well, a bit more than the inner one. So from the side, the broken tube looks similar to the massive cylindrical specimen.
Very good. The video is brilliant
thanks you very much for you effort .....I would like to ask you about young's modulus....does its value change after heat treatment for medium carbon steel or in other carbon steel ...and is that change is wide or not... ......because i had .. that changing when i did my research for aisi1030 with hardening, tempering,annealing,and normalizing ....thank you
Answer to "I would like to ask you about young's modulus....does its value change after heat treatment for medium carbon steel or in other carbon steel...?": In the case of steels, young's modulus does not change much with a heat treatment. There probably is a small influence, but this influence is so small, that it is almost impossible to detect it.
Great video, Thank you.
AMAZING EXPLANATION
my mind just exploded. This is gonna be a fun semester
cipolla
Thank you so much for this video and for your explanation
Thanks alot ! Perfecttt!
Great video!
Excellent explanation
This is extremely fascinating. I'm super motivated to finish my remaining education. Working two full time jobs for school has been very tiresome.
well done *claps*
how old were u a year ago
@@philipranjit4586 ok
@@pan4909 wow i was a massive dick a year ago
@@philipranjit4586 lol 1 year ago m8
It’s a very helpful video. Thanks alot
Very helpful, Thanks!
I'm a sample machinist for the local steel mill and this is exactly what I machine every day.
"Why does the machine not apply any additional force in the 'luda' (Lüder) area of the curve?": This is an important question, and a research topic of mine, please see our publ. "On the nature of the yield point phenomenon" in Acta Materialia. "And why does the machine apply less and less force right before final fracture?" This is due to "material instability": Here the strain hardening effect is not strong enough to compensate the strength decrease due to the decrease in cross sectional area.
what can you conclude about the yield strength of the two specimen tested here?
Amazing experience.
Very well explained
This is very well done, it helped my studies.
ma va a cagare
So, does it pull the metal apart or push it down until it breaks?
At final stage of fracture if a straight line occurs with no elongation but drop of force and again increaseslittle bit and fractures means what can we decide from that
Excellent video really. So wonderful to see real results. Another question. Did the second material retain permanent plastic deformation near the fracture point? It seems to spring back and not retain necking after break which seems like a cleaner cut. Is this like a somewhat brittle material then?
Answer to "Did the second material retain permanent plastic deformation near the fracture point? It seems to spring back and not retain necking after break which seems like a cleaner cut. Is this like a somewhat brittle material then?": The second material (Al alloy) retains all of the plastic deformation, including the neck. However, it is not as ductile as the first material and the neck is barely noticeable.
Thank you very much for your help
Cool machine!
Question just to clarify, I had previously understood that a stress vs. strain graph, the stress was the Force DIVIDED BY THE AREA, which here seems to be the yield points... Is stress just the force measure or are these two different graphing methods?
wonderfull thanks Angela
Thank you for this
I have got good idea for this testing methods, parallel i have equation to ask tensile test for 6mm diameters of work pc what abut the length
Excellent! Thank you !!
onion
very interesting lesson ...
Hello friends!!!
Very good video
Big Laik from me.
onion
Thank You for u practical demonstration.
Where i can find the aluminium , copper , Mild steel & brass round shoulder threaded pieces?
onion
Need to make it. (far too late?)
can you do tensile strength at the through thickness direction acc to EN 10164 ?
Did the testing machine gradually increase the strain/extension in a steady controlled fashion at a pre-determined rate (and hence measure what corresponding force developed), or did it gradually steadily increase the applied force at a steady rate (and hence measure what corresponding strain was developed)? Explain
Good explanation
very good article
Love this process. Crazy how edge and screw dislocations travel in the material. To imagine metal of that thickness being able to do necking and break is so cool. Interesting how material goes from elastic deformation to plastic deformation. It was nice being able to see when the yield point occured on the monitor.
What was you factor of safety percentage?
Answer to "What was you factor of safety percentage?" There is no concept of "safety factor" in the tensile test itself. You need safety factors when you use the results of the tensile test to design a mechanically loaded component.
Great video with excellent explanation
I have a question though, is it going to make a difference when changing the rate of loading to the specimen?
Answer to "I have a question though, is it going to make a difference when changing the rate of loading to the specimen?": Yes, definitely. As a general rule, increasing the strain rate results in slightly higher stresses during the tensile test.
@@MaterialsScience2000
Oh, so when the strain rate increase we should expect a faster failure in the specimen
Thank you
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اخوي عندي سؤال ممكن تساعدني ؟
Nice! Very helpful.
(Explain the concepts used in the tensile test on the tensile diagram of st 37 steel)
Can someone help me with this question please?
This is so cool, do you have a video with temperature instead of force aswell?
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Thank you for the sharing, to get the elongation rate, how do we measure the post-test length?
Answer to "Thank you for the sharing, to get the elongation rate, how do we measure the post-test length?":
The post-test length (permanent gauge length after fracture) is commonly evaluated with two methods:
(i) By calculating the elastic spring-back after fracture, and then applying it to the elongation immediately before fracture. This is done by the software of most machine manufacturers.
(ii) By reassembling the broken test piece and then measuring the permanent gauge length.
Amazing name, inspekt 200
If this rod was a hollow tube or pipe how would the inner diameter be effected? Am I to assume that the point at which it would neck the inner diameter would increase roughly as much as the outer diameter decreases?
I want to aske about elongation, the elongation at fracture and the elongation after fracture wich one should be taken depend on astm 615
Is it possible to have the final cross sectional area? As it wasn't mentioned, it is possible to calculate from any other measure already given? Thx
Answer to "Is it possible to have the final cross sectional area? As it wasn't mentioned, it is possible to calculate from any other measure already given? Thx" We have not explained the calculation of the material properties very much and concentrated on the basics. If you wish to, you can measure the final cross sectional area yourself: Stop the video at the appropriate point (when the specimen is placed on the table) and then measure the diameter d at the point of fracture (should be around 5 mm in the case of the steel, and 9 mm in the case of the aluminum alloy). You can then calculate the reduction in area. It is not possible to calculate it from any other value.
Nice informative
Cool. I like videos like this.
It would be valuable to add to the charpy energy testing video to include %shear area determination and may be include a drop weight testing video with %shear area determination.
Great Video :)
Amazing