Thank you so much! I could do this question and even got it right before looking at the answers due to your previous videos. I was so clueless at class haha! Thanks again :)
I am trying to understand the same thing because 3/2 is basically 1.5 and if we have two of that we basically have three single O's in total. I think that is the thinking behind it.
A tricky one! I don't suppose it can get much harder than this for Born-Haber? Thanks so much for the video.
Thank you so much! I could do this question and even got it right before looking at the answers due to your previous videos. I was so clueless at class haha! Thanks again :)
Nazz Khatun Awesome! You’re welcome
Why is it 3x the enthalpy of atomization for O2. Instead of 3/2 x the enthalpy of atomization ?
I am trying to understand the same thing because 3/2 is basically 1.5 and if we have two of that we basically have three single O's in total. I think that is the thinking behind it.
s.tundeee thanks for clearing my doubt
why does the second electron affinity not have electrons in the equation like the first ?
There is
Sir, how did you get the end value of 13783? I tried to work it out myself but only got up to 13883
Thanks such a great video could you please give me other hard examples that I can try out 🙂😊
Yes 🤗
I don’t get why u go from 3/2 O2 to 3O
3/2*2 = 3 = (3/2 O2 = 3O)
Hi, how would I draw the Born Harber cycle for MgCl3 ? Would it be very similar to this ?
It's MgCl2
+Danyel Butt looooooool
this question was so difficult
THANK U VERY MUCH BRO