FE Exam - Thermodynamics - Ideal Gas Mixtures

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  • เผยแพร่เมื่อ 10 ธ.ค. 2024

ความคิดเห็น • 29

  • @will_hunt_music
    @will_hunt_music ปีที่แล้ว +1

    Great tutorials, thanks for all of them!

  • @dand7056
    @dand7056 ปีที่แล้ว +1

    Nevermind i miscalculated mw of N2. Its 28 not 48. Ooooops. Thanks man still watching these for PE Env this time. Exam is next week.

  • @zacharykubas4478
    @zacharykubas4478 2 ปีที่แล้ว +3

    Thanks for posting these! I'm trying to studying for the FE mechanical right now, and currently I'm studying mechanical design and analysis. Would it be possible for you to upload more practice problems to add to your current playlist for that subject? Thanks! :)

    • @directhubfeexam
      @directhubfeexam  2 ปีที่แล้ว +2

      Hi Zachary! You're welcome and thank you for watching. Mechanical design and analysis is definitely a highly requested topic. Unfortunately, I did not take this fully take this course in school but I do attempt to learn some of the concepts or basic ideas from lectures online and textbooks. At this time, I am mainly focused on the Civil topics or topics similar to those I teach in Civil Engineering. I recommend this book if you are trying to dig deep into some topic relevant to the FE Mechanical:
      MACHINE ELEMENTS IN MECHANICAL DESIGN by Robert L. Mott, Edward M. Vavrek, Jyhwen Wang
      My recommendation is to focus on applying the equations in the FE Handbook, especially for this section. Thank you 🙏

  • @haasalawadi591
    @haasalawadi591 หลายเดือนก่อน

    Thank you

  • @haleemaawan4175
    @haleemaawan4175 2 ปีที่แล้ว +5

    Thank you this video. I really understand these problem now. I got 20.48 for the mass of last question. Is it right??

  • @farooquenadeem5300
    @farooquenadeem5300 2 หลายเดือนก่อน

    how do i solve last question at end of video?

    • @directhubfeexam
      @directhubfeexam  2 หลายเดือนก่อน

      Here it is:
      www.directhub.net/wp-content/uploads/2022/08/ideal-gas-mixture-2-solution-1661186754.1069.png

  • @philspaseo2377
    @philspaseo2377 2 ปีที่แล้ว

    If a problem is asking for energy released as heat per unit mass of mixture between carbon monoxide and nitrogen. Between these two gasses why is carbon monoxide using mass fraction formula and nitrogen using the summation of mass fraction formula(based on carbon monoxide mass fraction answer)? Can’t these two equations be used for either gas to find the mass fraction of different forms ?

  • @josea.serrano-perez3544
    @josea.serrano-perez3544 2 ปีที่แล้ว +1

    I see that in page 169 of the Handbook, there is a table of gases properties at room temperature where one can fin the "Mol wt" directly. Is it correct to use this table?

    • @directhubfeexam
      @directhubfeexam  2 ปีที่แล้ว +2

      Oh man, yes!
      Good catch!! After 3 years of looking in this handbook, I forgot that table was even there before solving this one. I am glad you caught that since it would save us a lot of time on the actual exam.
      Well done!

  • @annakatherineparker3660
    @annakatherineparker3660 2 ปีที่แล้ว

    I am confused on the last problem. Is % by volume the same as molar fraction?

    • @directhubfeexam
      @directhubfeexam  2 ปีที่แล้ว

      Yes it is!
      So 60% = 0.60 kmol and 40% = 0.40 kmol with the total mass being 1 kg.
      Or
      60% = 60 kmol and 40% = 40 kmol with the total mass being 100 kg.

    • @carultch
      @carultch ปีที่แล้ว +1

      Molar fractions, fraction by volume, and fraction by pressure, are all the same. Dalton's law of partial pressure, and Avogadro's gas law require this.
      It is mass fractions, where you need to use substance properties to translate.

  • @dand7056
    @dand7056 ปีที่แล้ว

    I got 27.61 . I used ideal gas law changed 1.5 mpa to 14.8 atmosphere used vol of 1000L and MW of mix at 46.4 g/mol. R =.08205 T at 303k. What did i do wrong. Im close but not at 20.46. Used m=P V MW/ R T

    • @mehtam92
      @mehtam92 10 หลายเดือนก่อน

      Don't know if you will see this but, convert 1.5 MPa to KPa instead of atm. R = 8.314 because pressure is KPa and volume is m or use the gas table on page 169 to find Ri. You were correct with coverting celcius to kelvin. Keep volume in meters so then the volume is 0.6 and 0.4 m^3 respectivily. If you do these plug-ins you should get 20.46 kg.

    • @Saleem.Ahamed
      @Saleem.Ahamed 2 หลายเดือนก่อน +1

      Pi=mRT/V ----
      Nitrogen Pi(1500KPa)x (0.6m3Volume)/(R 0.2968 from Pg 169X(30+273K)= 10.00
      Carbon Dioxide Pi(1500KPa)x (0.4m3Volume)/(R 0.1889 from Pg 169X(30+273K)=10.482
      10+10.482= 20.482

  • @yashen299
    @yashen299 ปีที่แล้ว +1

    Ans B

  • @dand7056
    @dand7056 2 ปีที่แล้ว

    I just took the exam and was surprised about 2 things. How different the look and feel of the fe handbook was. The search was harder because u had to spell things perfect so no spell suggests and then all the pages show up.and u have to click each page and now it's even smaller because half the screen is the test the other half the handbook and the search pages populate and take up even more room on the left. You should do a video on how to emulate that at home. Second was the time. I.thought I would have half the time for first half and half the time on the second half buy no you can waste all your time on the first half if you're not careful. Finally the 5 minute alert should be used to guess all the un answered questions. I ran out of time and didn't get to guess on the last few. I don't even know what question I was one but it was near the end. I struggled but I hope with the curve I can scrape by. Lots of questions that I had not seen before, even after working 700 plus problems. And the school.of pe . The hydraulics for environmental was not bad but chemistry and all the conceptual questions were tough cause you can look at it multiple ways. Statistics was harder too. Hope.you can do more videos on these topics.

    • @kharlaambriz8213
      @kharlaambriz8213 2 ปีที่แล้ว

      Hi Dan. Which specification did you take, and did you pass?

    • @dand7056
      @dand7056 2 ปีที่แล้ว +6

      @@kharlaambriz8213 I took the environmental FE. I have graduated in 1994 so I've been out of school for too long. Even though I studied for 8 months took 5 tests worked hundreds of problems and still I didn't pass. NCEES gives you a scale from 0 to 15 in each subject area. My lowest was 6.2 in statistics and chemistry. I was above 10 in 3 subjects but below in 12 subjects. Lots of conceptual questions that seemed to have multiples right answers. Also things that I had never seen before. Like what is the hydraulic radius of a duct shaped liked two triangles so the fluid moved through the area bound by the two triangles. I didn't know how to do that. They give u cancer slope factor for benzene and ask who has higher risk woman or man for inhalation vs ingestion and u only have a diagram showing a spill air and water directions. So I will be studying concepts and solving more problems. If you fall 5 times get up six. This time I'm gonna keep at it till I make it. I hope 2nd time is the charm . Time management is key. And don't be too stubborn like me to skip a problem you are having difficulty with. I didn't even answer the last 4 since I ran out of time

    • @kharlaambriz8213
      @kharlaambriz8213 2 ปีที่แล้ว

      @@dand7056 thank you for responding! This is also my second time taking it. I will retake it next week and also have been doing hundreds of problems. This message is super encouraging. I hope you pass next time!
      The hardest part for me was just the time, I was also stubborn and didn’t skip the ones that I couldn’t answer at the time.

    • @kharlaambriz8213
      @kharlaambriz8213 2 ปีที่แล้ว

      @@dand7056 for the hydraulic radius question - I believe they wanted you to use mannings equation to solve for that “Rh” value.

    • @kharlaambriz8213
      @kharlaambriz8213 2 ปีที่แล้ว

      @@dand7056 also for that benzene question, if you scroll down to the safety section of the manual, page 28, they give you all the intake rates that way you plug in all your variables, multiply by the cancer slope and compare. I hope this helps!