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love from india.. this video is very useful for preparing for my sem. exams
I've been using the Coaching Actuaries site, and they didn't explain why the Var(kX) = k^2 * Var(X). Very helpful, thank you!
You are a really great lecturer. Thank you for posting these videos.
Whaaaaaaat.....u man,yo giiiiid so good.... Very understandable proof of variance. To be honest I have enjoyed the video,am gonna like, subscribe and share in a second from now. Thanks so much. What a video.
God damn it I can't believe it took me so long to understand this. Thank you!!!
i hate statistics because of my teacher.. but you are good... my teacher always insulting me.. she don't know to teach..thank you mr..
Can you make more actuarial related topics please?! your videos are so helpful !
I spent a long time figuring out a problem that your video explains. I should have just watched this video first!
I really love your simple explanations
Character In the video It's great, I like it a lot $$
awesome video ! thank you sir
Thank you a million!
Tysm sir for this video, it was really helpful.
Great video
so helpful, thank you 🙏🏼 😊
This really helps a lot.
At 12:45, the calculation of E(x^2), how come it's the integral of x^2 * 3/x^4 dx, and not x^2 * 3/x^8 dx?
First calculate mean/variance of base variable and then apply the arithmetic
this is so helpful thank you!!
Does E(aX+b) = aE(X)+b for independent and non independent?
Shouldn't the boundaries of the integral be from 2 to infinity since the it's strictly greater than 1
Continuous distributions aren't affected in regards to less than or equal or strictly less than. So (1, infinity) is fine
No cos 1.5 is greater than 1
bless your soul
Thanks sir
Lmfao watching this lecture instead of my professor's lecture because he's absolute crap
Thanks
Thank you 😊
thank you sir
Great
Tnx alot sir
Thaaaaaaaaaaaaaaaaank youuuu
love from india.. this video is very useful for preparing for my sem. exams
I've been using the Coaching Actuaries site, and they didn't explain why the Var(kX) = k^2 * Var(X). Very helpful, thank you!
You are a really great lecturer. Thank you for posting these videos.
Whaaaaaaat.....u man,yo giiiiid so good.... Very understandable proof of variance. To be honest I have enjoyed the video,am gonna like, subscribe and share in a second from now. Thanks so much. What a video.
God damn it I can't believe it took me so long to understand this. Thank you!!!
i hate statistics because of my teacher.. but you are good... my teacher always insulting me.. she don't know to teach..thank you mr..
Can you make more actuarial related topics please?! your videos are so helpful !
I spent a long time figuring out a problem that your video explains. I should have just watched this video first!
I really love your simple explanations
Character In the video It's great, I like it a lot $$
awesome video ! thank you sir
Thank you a million!
Tysm sir for this video, it was really helpful.
Great video
so helpful, thank you 🙏🏼 😊
This really helps a lot.
At 12:45, the calculation of E(x^2), how come it's the integral of x^2 * 3/x^4 dx, and not x^2 * 3/x^8 dx?
First calculate mean/variance of base variable and then apply the arithmetic
this is so helpful thank you!!
Does E(aX+b) = aE(X)+b for independent and non independent?
Shouldn't the boundaries of the integral be from 2 to infinity since the it's strictly greater than 1
Continuous distributions aren't affected in regards to less than or equal or strictly less than. So (1, infinity) is fine
No cos 1.5 is greater than 1
bless your soul
Thanks sir
Lmfao watching this lecture instead of my professor's lecture because he's absolute crap
Thanks
Thank you 😊
thank you sir
Great
Tnx alot sir
Thaaaaaaaaaaaaaaaaank youuuu
Character In the video It's great, I like it a lot $$