Problem 2 is a two-stepper in desmos. Step 1 enter the equation as is. Step 2 enter b=1 to create a slider. Set it from 1 to 100 in step 1 (step = 1 since it's an integer), and note that when b=52 one solution appears, but when b=51 the solutions disappear. So b=51 is the biggest it can be to ensure no real solutions. This took 30 seconds.
For problem 5, let b be your free variable and assign a value of 100 in desmos by entering b=100 (it creates a slider, but you'll just leave it at 100...you can actually set it to ANYTHING since it's a free variable). Next line type a=30% of b. That gives you a=30. Next line after that type c=180% of a. That will give you c = 54. Then do a regression by typing c ~ nb to solve the equation c = nb, where n is how many times c is bigger than b. Under the PARAMETERS you get n=0.54. Done. Literally took 15 seconds.
For the first problem just set up a regression in desmos to solve for p by typing in -p/3 + 3 - 3 + 8 ~ 20/3 to get p=4. The -p/3 is the solution to the first ( ), 3 and -3 for the second ( ), and 8 for the third ( ). For the third you do need to know the sum of solutions of a quadratic is -b/a = -(-16/2) = 8 to save time.
That would take a lot of work to multiply that all out and you run the risk of making an error by hand. But, yes, in theory -b/a still applies as the generalized Vieta rule.
Thank you so much! How does this "regression" work in desmos exactly, and are there many other problems on the SAT it would help to use? I've never used it before in desmos.
For problem 4, some students won't pick up on the trick that the answer has to have 7/2 in the x-coordinate. A more convincing approach with desmos is to just plot each point exactly as shown, and enter a slider for r. Only choice B will keep the point on the two lines (which happen to be the same) as you slide r.
Hey Laura ! I hope you are doing well. Just wanted to say that there was one math question in the second module of the august math SAT 2024..... I have never seen a question like that in the past 20-25 papers and also not in the practice papers in the bluebook. Can you please solve any question like that. It was really complex too.
Problem 3 is 1 minute in desmos. Create a table and enter three points: (9,-14), (9+d,0), and (9-d,0). First point is the given vertex, and the second two points are artificially created conveniently on the x-axis d units symmetrically on either side of 9. Then enter d=1 to create a slider. Next do a quadratic regression by typing y_1 ~ ax_1^2 + bx_1 + c and finally type a + b + c to check the sum of the constants as you slide d. Notice that as you slide d in the positive (or negative) direction, it does have a sum of -12, but never quite approaches -14. So the answer is D.
The last bluebook test I gave I scored 1330 and after a lont time of Studying I was hopping that will get 1450 plus, but when I gave sat 6 bluebook test I scored 1130 this kind of sadded me deeply. I don't understand why? I got 26 wrong in total. Feeling quitehelplees. I am giving sat in october start. Is there any possible way for me now to do something to get 1500 plus on my real sat test please helpAll hope lost.......
If we look at the problem mathematically, you will notice that both equations represent the same line. All points of equation 1 are also the points of equation 2. To figure out which point lies on the graph of both equations, you can substitute the value of x or y in the equation 2x+3y=7 to get the value of y or x respectively. You will notice that it is only for option B where substituting y=r yields x= -3r/2 + 7/2. The method in the video is just a quicker (and tried and tested) way of doing the problem. Hope this helps :)
@@puneetkaur5681 I just remembered this earlier!! I tried converting it into slope intercept so that r would equal x. However, one of the answers choices was so close to being right but it was a positive slope instead of a negative slope. So I tried doing x= yada yada just like you did and I figured it out! Math is so interesting
Problem 2 is a two-stepper in desmos. Step 1 enter the equation as is. Step 2 enter b=1 to create a slider. Set it from 1 to 100 in step 1 (step = 1 since it's an integer), and note that when b=52 one solution appears, but when b=51 the solutions disappear. So b=51 is the biggest it can be to ensure no real solutions. This took 30 seconds.
For problem 5, let b be your free variable and assign a value of 100 in desmos by entering b=100 (it creates a slider, but you'll just leave it at 100...you can actually set it to ANYTHING since it's a free variable). Next line type a=30% of b. That gives you a=30. Next line after that type c=180% of a. That will give you c = 54. Then do a regression by typing c ~ nb to solve the equation c = nb, where n is how many times c is bigger than b. Under the PARAMETERS you get n=0.54. Done. Literally took 15 seconds.
@@RisetotheEquation 🤩
You literally saved me, went from a 1250 to a 1430 on the recent August SAT. Love your videos!
For the first problem just set up a regression in desmos to solve for p by typing in -p/3 + 3 - 3 + 8 ~ 20/3 to get p=4. The -p/3 is the solution to the first ( ), 3 and -3 for the second ( ), and 8 for the third ( ). For the third you do need to know the sum of solutions of a quadratic is -b/a = -(-16/2) = 8 to save time.
did not we just need to make -b/a why did we do all that stuff. btw thanks for the explanation
That would take a lot of work to multiply that all out and you run the risk of making an error by hand. But, yes, in theory -b/a still applies as the generalized Vieta rule.
Thank you so much! How does this "regression" work in desmos exactly, and are there many other problems on the SAT it would help to use? I've never used it before in desmos.
For problem 4, some students won't pick up on the trick that the answer has to have 7/2 in the x-coordinate. A more convincing approach with desmos is to just plot each point exactly as shown, and enter a slider for r. Only choice B will keep the point on the two lines (which happen to be the same) as you slide r.
wdym by plotting each point ?
Can you go over tips and tricks for geometry, trigonometry, and circles thanks 😊
Hey Laura ! I hope you are doing well. Just wanted to say that there was one math question in the second module of the august math SAT 2024..... I have never seen a question like that in the past 20-25 papers and also not in the practice papers in the bluebook. Can you please solve any question like that. It was really complex too.
What was the question exactly
Problem 3 is 1 minute in desmos. Create a table and enter three points: (9,-14), (9+d,0), and (9-d,0). First point is the given vertex, and the second two points are artificially created conveniently on the x-axis d units symmetrically on either side of 9. Then enter d=1 to create a slider. Next do a quadratic regression by typing y_1 ~ ax_1^2 + bx_1 + c and finally type a + b + c to check the sum of the constants as you slide d. Notice that as you slide d in the positive (or negative) direction, it does have a sum of -12, but never quite approaches -14. So the answer is D.
why do we minus and plus d?
To keep the points the same distance on either side of the x-coordinate 9. Remember parabolas are symmetric with respect to the vertex.@yaayyayay
how does the fact that it barely approches -14 mean its correct?
I had been struggling with problems like Maria's, she helped me understand very well!!
i genuinely don’t get the third problem, can someone dumb it down??
problem solving and data analysis
thank u very very much!!! i have got a deep regard for you. Carry on making such videos .please.
W title i clicked on this video instantly
Fu ck ing pa jeet
You are a (p a j e e t)
Clickbait !! 😂 😉 jk
@@FakeSpice jeet
The last bluebook test I gave I scored 1330 and after a lont time of Studying I was hopping that will get 1450 plus, but when I gave sat 6 bluebook test I scored 1130 this kind of sadded me deeply. I don't understand why? I got 26 wrong in total. Feeling quitehelplees. I am giving sat in october start. Is there any possible way for me now to do something to get 1500 plus on my real sat test please helpAll hope lost.......
Thanks for your help!!!
What did the mister from ur live get
@@gamerzlatest937 1560
@@StrategicTestPrep wowwww
Wow the 4th one really threw me off! What's the mathematic approach to that one?
Fr she just went around the mathematics of it and left me stranded
If we look at the problem mathematically, you will notice that both equations represent the same line. All points of equation 1 are also the points of equation 2.
To figure out which point lies on the graph of both equations, you can substitute the value of x or y in the equation 2x+3y=7 to get the value of y or x respectively.
You will notice that it is only for option B where substituting y=r yields x= -3r/2 + 7/2.
The method in the video is just a quicker (and tried and tested) way of doing the problem. Hope this helps :)
@@puneetkaur5681 I just remembered this earlier!! I tried converting it into slope intercept so that r would equal x. However, one of the answers choices was so close to being right but it was a positive slope instead of a negative slope. So I tried doing x= yada yada just like you did and I figured it out! Math is so interesting
thumbnail made me click instantly 🤤🤤🤤
👏🏻👏🏻👏🏻👏🏻👏🏻
you call these tricky ?
👏👏👏👏👏👏
@@mariaduartejaraba right back atcha 😉
Just word problems
Bro I got cooked
Laura 🫡🫡🫡🫡🫡🫡