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Good
Nice way to solve that excellent 👌👌
Put 10^x = a ,the equation becomes a^2 - a -1 = 0 a = ( 1 + - √5) /2 10^x = (1+ - √5) /2 x = log(1+ - √5) /2
Why you ignore second value of y ? Over all very good method and extremely detailed appreciate you ❤
Only mathematicians believe this.
Why you take 1^x=1 in your starting
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Good
Nice way to solve that excellent 👌👌
Put 10^x = a ,the equation becomes a^2 - a -1 = 0
a = ( 1 + - √5) /2
10^x = (1+ - √5) /2
x = log(1+ - √5) /2
Why you ignore second value of y ? Over all very good method and extremely detailed appreciate you ❤
Only mathematicians believe this.
Why you take 1^x=1 in your starting