Euler-Bernoulli vs Timoshenko Beam Theory

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  • เผยแพร่เมื่อ 26 ต.ค. 2024

ความคิดเห็น • 35

  • @gamgee6044
    @gamgee6044 2 ปีที่แล้ว +40

    Yo this is pog

  • @singingtuna4786
    @singingtuna4786 5 ปีที่แล้ว +59

    watching this as a re-cap just minutes before the exam while pooping in panic.

  • @benjamincalloway
    @benjamincalloway 3 ปีที่แล้ว +7

    Very good video my friend! I was never introduced to Timoshenko theory in my mechanical design class, and this is a good starting explanation. :D

  • @NatureGod369
    @NatureGod369 4 ปีที่แล้ว +4

    Excellent. best video on difference between Euler and Timoshenko theory on youtube. plz make more videos, u can charge some fees to make it public , but, please make more videos. Good teachers are very very rare. God bless you.

  • @MobileTaskForce
    @MobileTaskForce 10 หลายเดือนก่อน

    "Alright that's all I have. Thank you so much for listening" This man is a simple man. I take my hat off for you.

  • @truth2989
    @truth2989 3 ปีที่แล้ว +4

    Fantastic break down. I read about 20 papers to try to simply figure out this difference and all it took was a sub 5 minute video

  • @elshons1576
    @elshons1576 ปีที่แล้ว

    From what I have read. The reason this theory is necesary, is because in thick and short beams the shear strain energy is greater than normal strain energy caused by bending moments. So deformation caused by shear forces will be more significant than deformations caused by bending moments.
    This makes sense because thick and short beams have a great flexural rigidity and the bending moments are small compared with shear forces.

  • @ねこのちーちゃん
    @ねこのちーちゃん 2 ปีที่แล้ว +2

    I want to know the form difference between the Timoshenko beam theory and Euler-Bernoulli so that your video was helpful for me. Thank you.

  • @nahuelg531
    @nahuelg531 ปีที่แล้ว +1

    Muy buena explicación. Muchas gracias!

  • @ryanvandermerwe5587
    @ryanvandermerwe5587 4 ปีที่แล้ว +14

    my lecturer took 3 lectures to explain this

  • @tarkesdora20
    @tarkesdora20 ปีที่แล้ว

    Short and very sweet!

  • @mbbag1980
    @mbbag1980 6 ปีที่แล้ว +4

    rather than a contradiction, i would describe that aspect of the e-b-b theory as an "inconsistency".

    • @DRAMBgo
      @DRAMBgo 4 ปีที่แล้ว

      it's neither a contradiction nor an inconsistency. it's a valid semplification if applied conscientiously.

  • @yoshibar2536
    @yoshibar2536 3 ปีที่แล้ว +1

    Do you really think, that the far right edge would stay perpendicular?

  • @alessandrobrolis239
    @alessandrobrolis239 3 ปีที่แล้ว +1

    Additionally, maybe i don't understand, but is the last picture correct? How can the end be a straight line if you have to account for compression on top and tension at the bottom?

  • @alessandrobrolis239
    @alessandrobrolis239 3 ปีที่แล้ว +1

    Maybe I got something wrong, but as far as i know the neutral axis is defined as the axis which retain perpendicularity AFTER the beam has been deformed, that's why for this particular shape is in the middle, because after the cubes are deformed, only the middle of the cube remains perpendicular. I don't understand why would you define the neutral axis before bending. And shear in a beam under deflection is always present, why would you neglect it?

    • @Rippertear
      @Rippertear 2 ปีที่แล้ว

      If I recall correctly, it can be defined before or after any elastic deformation, as the neutral axis should remain at the same place before and after deflection. And I believe the effects of shear on deflection are neglected because they are usually much smaller than the effects of normal stresses, and for most situations they aren't crucial to the integrity of a given part.

  • @deepak8057173838
    @deepak8057173838 8 ปีที่แล้ว +6

    can you show me the axis direction (x y z)

    • @Yndiax
      @Yndiax 7 ปีที่แล้ว +3

      x is horizontal, y vertical, z out of plane

  • @RahulSharma-oc2qd
    @RahulSharma-oc2qd 3 ปีที่แล้ว

    at 1:00 (Since there is no transverse loading): by that you mean there is no force parallel to axis? because if you would say otherwise, we have a load which is perpendicular to axis. (Which in my understanding, should be called as transverse loading). Am I missing something?

  • @purify4now
    @purify4now 7 หลายเดือนก่อน

    Great video

  • @mec007
    @mec007 2 ปีที่แล้ว

    mmm quizás tengo q profundizar más, estoy estudiando vigas de acoplamiento en muros. Me recomiendas algún libro? Excelente video.

  • @rohitgupta8549
    @rohitgupta8549 4 ปีที่แล้ว

    I think you should show combine diagram of shear and bending.

  • @MasterCivilEngineering
    @MasterCivilEngineering 4 ปีที่แล้ว

    Step by step video solutions of civil engineering questions

  • @heybrotelugu
    @heybrotelugu 7 ปีที่แล้ว +1

    enough info for this topic :) .
    very nice

  • @marciocamara9151
    @marciocamara9151 7 ปีที่แล้ว

    What are the backgrounds needed to understand it?

    • @Yndiax
      @Yndiax 7 ปีที่แล้ว +2

      Bachelor in mechanical engineering

    • @ArduinoKing
      @ArduinoKing 7 ปีที่แล้ว +1

      That's what I'm studying, and this stuff seems pretty tame compared to some of the stuff we are learning about.
      This explanation was excellent.

    • @ShoobiArt
      @ShoobiArt 4 ปีที่แล้ว +1

      This comments really old, but this is a good explanation of something you would learn in a strengths of materials class which is normally a second year engineering course.

    • @nicolasu3091
      @nicolasu3091 4 ปีที่แล้ว

      first to pass mechanical physics and then to take the first five classes of strenght of materials

  • @ronniewang932
    @ronniewang932 6 ปีที่แล้ว

    Timoshenko like a Russian name, every professor in univeristy with name ...+sky, is hardcore,