@@TechnoTutorials2783Hii mam ye same paper me aaraha hai par uske aage aur bola gaya hai ki implement using PLA having 3 inputs 4 product terms and two outputs to uske liye bhi ye same itna hi banana hoga na plzzz bataiye mam❤......
THank you , Thank you so much mam.... from my bottom of the heart . I was despirately searching for this differentiation . God Bless you Mam.. and Love you mam
Using the connection abbreviation, show how a PAL can be programmed to implement the following Boolean equations. D1 = A̅B̅̅C + A̅ C̅ + AB̅ C D2 = AB̅ C + B̅ C̅ D3 = A̅ BC + A̅ B + A̅ BC̅
I have an exam in 3hrs this video helped me a lot thank you mam 🙂
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@@TechnoTutorials2783Hii mam ye same paper me aaraha hai par uske aage aur bola gaya hai ki implement using PLA having 3 inputs 4 product terms and two outputs to uske liye bhi ye same itna hi banana hoga na plzzz bataiye mam❤......
Same
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Very very clear and understandable explaination of implementation using pla, pal, prom, such useful video
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अद्भुत वीडियो कांसेप्ट बिल्कुल क्लियर
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What a easy explanation i have learnt my digital circuit subject from u thanks for the best teaching hope so mera kal paper out off jaye
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VERY VERY SUPERB EXPLANATION MA"AM☺🙏 Kaash ma'am aap meri college me padhati toh attendance 100% hoti 😇 Thank you very much ma'am
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Such A Helpful Video On You Tube 💯
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THank you , Thank you so much mam.... from my bottom of the heart . I was despirately searching for this differentiation .
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Implement the following function using a PAL. a) F (A, B, C, D) = Σm (1, 9, 12, 15).
Solution link
th-cam.com/users/shortskSnyYMm8lPQ?feature=share
thanks mam
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thanks for the helping for the exam@@TechnoTutorials2783
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Hlo madam hindhi kakunda English lo cheppandi madam maku enka baga artham avuthundhi meeru chala baga explain cheastunnaru ..... English lo cheppandi madam pls
learn hindhi koncham koncham
Osm🙏
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Thankyou so much 🙏🙏😍
Thank you so much mam🔥😊
Welcome dear
Best video ❤️
Using the connection abbreviation, show how a PAL can be programmed to
implement the following Boolean equations.
D1 = A̅B̅̅C + A̅ C̅ + AB̅ C
D2 = AB̅ C + B̅ C̅
D3 = A̅ BC + A̅ B + A̅ BC̅
I will try to upload as soon as possible
@@TechnoTutorials2783 Thank you.
th-cam.com/video/xDgbZ4_KPkY/w-d-xo.html
Please check above for solution
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Nice
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❤️❤️thank you
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Mst video 3 in 1 video I understand properly Tq so much mam 🫶
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Mam please do one thing solve this question by using 4 boolean outputs that is confusing.
R u asking for 4 variable?
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