Step 1. *Free body diagram.* Step 2. *Equilibrium:* {B. Σf(x)=0; Σf(y)=0 A. Resolve inclined forces into their components along x and y axes. C. F in “→”, “↑” direction = +ve, &, F in “←”, “↓” direction = -ve D. ΣMx = 0; ΣMy = 0; i.e. sum of moments = 0. Moment = Force × ⊥ distance w.r.t a point. Also = Component of Force ⊥ to the distance from that point. Any Force F passing through that point during finding moment w.r.t that point = 0. So, always take moment w.r.t a point which makes maximum number of Forces 0.} Step 3. *Formula of Friction:* { *F = μR* , where μ is the coefficient of friction which is the ratio of the force of friction F to the normal force R, F/R. F always acts opposite to the motion of the body and along the surface. Angle of friction is the angle between the resultant R' (say) of F and R with respect to R, denoted by φ. hence *μ = tan⁻¹(φ)* } Step 4. Lami's Theorem: { *When three forces (T1, T2, T3 acting at a point P are in equilibrium, then each force is proportional to the sine of the opposite angles (A, B, C respectively) to that force in that system* The forces must be in same plane, and they all must be in same direction otherwise this theorem is not applicable. *T1/sin(A) = T2/sin(B) = T3/sin(B)* } Step 5. *Resultant of Friction:* {The resultant R' (say) is the resultant of the Frictional force F & the normal force acting ⊥ to the surface against the weight, R. It can be used to solve Wedge problems when angle of friction is given it makes it easier to solve, also Lamis theorem might be applied too, (read step 3 and step 4)}
Ur best in engineering mechanics sir I say videos ur explanation so good i in tamilnadu i don't understand ur language sir but it's clearly ur mention in ur board sir thank u lot sir.....
Sir you have good mathod of teaching . Sir please tell us that hame kase pata chala ki sabhi forces center ki taraf ja rahi ha. Jis karan sa hamne Lamis equation ka use kiya and (2) Problem solve karne ka liya Wedge ka weight use kyon nahi hua ha. Thankyou
your video is much better than my professor.
Step 1. *Free body diagram.*
Step 2. *Equilibrium:*
{B. Σf(x)=0; Σf(y)=0
A. Resolve inclined forces into their components along x and y axes.
C. F in “→”, “↑” direction = +ve,
&, F in “←”, “↓” direction = -ve
D. ΣMx = 0; ΣMy = 0; i.e. sum of moments = 0.
Moment = Force × ⊥ distance w.r.t a point.
Also = Component of Force ⊥ to the distance from that point.
Any Force F passing through that point during finding moment w.r.t that point = 0.
So, always take moment w.r.t a point which makes maximum number of Forces 0.}
Step 3. *Formula of Friction:*
{ *F = μR* , where μ is the coefficient of friction which is the ratio of the force of friction F to the normal force R, F/R. F always acts opposite to the motion of the body and along the surface. Angle of friction is the angle between the resultant R' (say) of F and R with respect to R, denoted by φ. hence *μ = tan⁻¹(φ)* }
Step 4. Lami's Theorem:
{ *When three forces (T1, T2, T3 acting at a point P are in equilibrium, then each force is proportional to the sine of the opposite angles (A, B, C respectively) to that force in that system*
The forces must be in same plane, and they all must be in same direction otherwise this theorem is not applicable. *T1/sin(A) = T2/sin(B) = T3/sin(B)* }
Step 5. *Resultant of Friction:*
{The resultant R' (say) is the resultant of the Frictional force F & the normal force acting ⊥ to the surface against the weight, R. It can be used to solve Wedge problems when angle of friction is given it makes it easier to solve, also Lamis theorem might be applied too, (read step 3 and step 4)}
Ur best in engineering mechanics sir I say videos ur explanation so good i in tamilnadu i don't understand ur language sir but it's clearly ur mention in ur board sir thank u lot sir.....
Thank you sir!
Helpful solving problems 🥰 👍❤️🙇🙇
thankyou sir ❣
Supperrbbbbb explanation with each and every doubt clear🤩🤩🤩🤩.....keep going sir🔥🔥❤❤👍👍👍
Sir ye method hard aur confusing he plz 1 problem vali method se solve karke ek ya do sums upload Karo na plz
Please share belt friction's video as soon as possible please🙏
I always like your diagrams
Love u sir❤️
Super sir
Thank you sir
Dear sir! You are always best! 😊
Sir! Ek request thi, shear force diagram & Bending moment diagram ke videos bana dijiye..
nhi sir video mat banaiye apna channel band kar dijiye
Sir why you did not consider 20 degrees.
Bro in question given 15 degree not 20 degree. And 15 degree use in FBD and in lamis diagram and calculation
👌 👍
Sir..... how to read different engineering drawing....if u please make video on this topics. It will be very helpful
Can anyone tell me why sir has not taken weight of block B
Sir you have good mathod of teaching .
Sir please tell us that hame kase pata chala ki sabhi forces center ki taraf ja rahi ha. Jis karan sa hamne Lamis equation ka use kiya and
(2) Problem solve karne ka liya Wedge ka weight use kyon nahi hua ha.
Thankyou
Thank you so much sir 🙏😊
Sir please make more videos on engineering mathematics
Sir should we take tan-1U if coefficient of friction is given
Tq sir
Thaks a lot...
Sir pl upload more wedge problems
P =19.87
By using method of equilibrium.
Thanks sir
Sir belt friction bhi bataiye please
Sir please simple stress and strain Ka topic or uske problem padayee n please sir
sir tell me plz ,why body A have not any weight, some weight will be on body a
The weight is clearly considered there, what are you talking about?
@@igxniisan6996he meant body B
Without solving resultant,
Ans = P = 17.16 kN
Is it right??
Sir how did you took 20 degree which is not mentioned in question
Kathin hai bohot
Sir aap hamare college mein aajao sikhane
Haa ata hu
@@sohaildarwajkar9979 Jaldi aa Varna Time pe payment nahi milega
Do it in English
(Do it)(^_^)