3.3 Properties of Smooth and Strongly Convex Functions

[@MrNgovanmao]

At minute 14:34 I think the gradient of the right hand side with respect to y is: Find delta f(x) + beta (y-x) = 0 (because 2/2=1). So the later step will be correct with y-x = -1/beta delta f(x).

[@constantine.caramanis]

Yes, you are completely right. Thanks.

[@sammyshi8077]

@@constantine.caramanis Same at 29:10

[@djin5395]

Thank you for your sharing ! Could you please further share the notes and referred books ？

[@mohamedppii1021]

Hello professor thank you please
Show that this function f(x) = e||x||^2 +1/2 - is quadratic
e=epsilon, À matrix SDP b vecteur