21:20 sir in the question CD=12cm but you had taken AC=12cm... Please tell how to do it if CD=12cm or there was an error in the question..... Please do the revision of all the chapters.... Thank you sir ❤❤❤❤❤
H/w question ABCD is a quadrilateral In which p is point on AB Q is point on AD R is point on DC S is point on BC Ab = 6cm BC= 9cm CD= 8cm If DR = x Rc = 8-x : BC = 8-x If Ap = x Bs = 6-x Bc = 9 Bc = Bs + Sc 9= 8-x+6-x 9=14-2x 2x=14-9 X= 5/2 AD = X+X AD = 5/2 +5/2 AD = 10/2 AD = 5cm 😅😅 I solved it different then the other guy
AB = 6 cm, BC = 9 cm, CD = 8 cm. Let P, Q, R, S be the points where the tangent touches the sides AD, AB, BC, and CD respectively. P R From a point outside of a circle, two tangents to the circle are always equal. Q Therefore, DP = DS AP = AQ BR = BQ CR = CS Thus, adding the left sides and right sides separately and equating them, we get: (DP + AP) + (BR + CR) = (DS + CS) + (AQ + BQ) ⇒ AD + BC = CD + AB ⇒ AD = CD + AB - BC = 8 + 6 - 9 = 5 ∴ AD = 5 cm. SIR PLZ DO AREA RELATED TO CRICLES
Sir last question mai ese toh AP and BP are the tangents from the same external point so they both must be equal.. So BP simply comes out to be 12 cm.... Then why we used Pythagoras theorem there???
@@shvetasood1) Tangents would have been equal if they touched the same circle 2) But the tangents from an external point are touching two different circles. So here theorem will not be applied. 👍
AP=AS BP=BQ CR=CQ DR=DS From all this equations based on tangent, Adding this all:::: AP+BP+CR+DR=AS+BQ+CQ+DS AB+CD=AD+BC So after solving, AD=5cm Sorry sir... Whole solution can't be written because it's somewhat long... 💖💖💖
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Sir 45.44 pe 18 ke jagah 27 ayega jiski wajah se answer 10.5 ayega
Yaa Exactly Broo🤔
45:34 wrong ans 😢😢
45:39 sir, 9×3=27 not 18
Ans will be 7 i guess of x
@@OFFICIAL_AKJno it’s 10.5
Sir Apne Question Easy Diye Ho Ya Hamme Easy Lag Rha Hai..
Vaise Thank You Sir Very Much..
30:33 ans 11 aana chahiye 27 mai 14 add krke 38 nhi aata
41:46 , sir the homework question's answer is 5cm.
54:05 instantly pause and watch face
Abe bhai yahi krta h kya 😂
AB+DC=AD+CB
6cm+8cm=AD+9cm
14cm=AD+9cm
14cm-9cm=AD
AD=5cm
AD=5cm
we can write this ad+bc=ab+cd directly or is there any solution for getting this?
39:57 perimeter ❤
21:20 sir in the question CD=12cm but you had taken AC=12cm...
Please tell how to do it if CD=12cm or there was an error in the question.....
Please do the revision of all the chapters....
Thank you sir ❤❤❤❤❤
Yes
It was an error as there was a triangle in the figure so it cannot have the side CD
Use pythagoras theorem and find the value of CA
Because AD=5, CD=12, CA=
BY PYTHAGORAS THEOREM
@@narsinghyadav7185 means you dumb is saying that hypotenues in smaller than parpandicular
H/w question
ABCD is a quadrilateral
In which p is point on AB
Q is point on AD
R is point on DC
S is point on BC
Ab = 6cm
BC= 9cm
CD= 8cm
If DR = x
Rc = 8-x
: BC = 8-x
If Ap = x
Bs = 6-x
Bc = 9
Bc = Bs + Sc
9= 8-x+6-x
9=14-2x
2x=14-9
X= 5/2
AD = X+X
AD = 5/2 +5/2
AD = 10/2
AD = 5cm 😅😅
I solved it different then the other guy
21:17 sir i think u r mistaken ..
CD ki length given h AC ki nhi
54:50 Ans= √160
42:10
😊
41:39 Answer: AD = 5 cm
is this for basic students?? this type of easy questions come in standard ???
Sir jii board main acche number layenge apse Vada hai 😊❤
Haaa bhai
Mee too ❤😊
Ha
❤
Me too bro
Good work sir tnx for helping
44:56
21:30
21:55 There is mistake in que AC=12 cm not CD=12 cm..... thank you 😊
AB = 6 cm, BC = 9 cm, CD = 8 cm.
Let P, Q, R, S be the points where the tangent touches the sides AD, AB, BC, and CD respectively. P R
From a point outside of a circle, two tangents to the circle are always equal. Q
Therefore, DP = DS
AP = AQ
BR = BQ
CR = CS
Thus, adding the left sides and right sides separately and equating them, we get:
(DP + AP) + (BR + CR) = (DS + CS) + (AQ + BQ)
⇒ AD + BC = CD + AB
⇒ AD = CD + AB - BC
= 8 + 6 - 9
= 5
∴ AD = 5 cm.
SIR PLZ DO AREA RELATED TO CRICLES
❤❤❤❤❤❤❤❤❤❤ 28:29
41:43 AD=5cm
Sir AD is 5cm in (homework question)
5 cm
46:33 wrong answer
Right is 10.5❤
41:43 ans 45cm
5cm hai bhai 😂
sir 21:48 question me CD 12 hai AC nahi
41:43 AD= 5CM
Sir last question mai ese toh AP and BP are the tangents from the same external point so they both must be equal.. So BP simply comes out to be 12 cm.... Then why we used Pythagoras theorem there???
There are two circles within that diagram, check once then it would be clear to you 👍
@@VaishnaviJaiswal-e8n but the thing is .. Both tangents are drawn from the same external point
@@shvetasood yes I agree, but the two tangents are intersecting the two different circles of the diagram not the same circle, analysis again..
@@shvetasood1) Tangents would have been equal if they touched the same circle
2) But the tangents from an external point are touching two different circles. So here theorem will not be applied. 👍
54:30 ans. BP=40root10
39:51 AP =1/2(TRIANGLE ABC)
Bro ye konsa question mein fully explain Kiya hai ???
41:33 5 cm
Sir A.P. ke important ques. Krado
Plss koi Biology ki revision k liye channel recommend krdo
Prefer channel "sunlike like studies"
Also u can learn biology from this channel only from Sonam mam.
@@Navika123Thanks .. It really helped a lot...😊
1
50:10 Sir AOC and BOD is not a line... So how Angle AOD And Angle BOC are vertically opp. Angles...???
Abhi Vatika protest angle Nahin Piyo Sunday
radius of circle = 11 cm
AD=5cm
AD = 5 cm
AB+CD=AD +BC
8:22 sir iss triangle ko phle right angled triangle prove karna jaruri nahi hai kya ?
5
Your best teacher
500:0
Awesome 👍
Ad =5
Hi
5 is the ans.
Sir ncert ka 12 question mere preboard exam aa gya tha maine nhi banaya😢😢
Thank you sir very much
45:44 pe galat hai
Sir chapter 11 or 12 bhi kara do please 🙏
sir you are the best teacher
your channel give free education and in also their is very cheap amount of rupee in paid batchess
thankyu sirrrr
You are the best teacher👀👀👀👀👀👀
46:03 sir 3*9 = 27 you did 18 so ans hi galat aaya.
Hello sir
4√10 cm for BP value
Length of AD be 5cm
Bp =4underroot 10
the answer is 5
AD is = 5cm
Nice lecture sir I slove all the questions and all questions are easy and important thank you ❤❤❤❤❤
5cm
Last ques....
In Triangle OAP :
By pythagoras theorem:
OP² = OA² + PA²
OP² = (5)² + (12)²
OP² = 25 + 144
OP = 13cm
In ∆OBP:
Again By pythagoras theorem:
: OP² = PB² - OB²
OP² = (13)² - (3)²
OP² = 169 - 9
OP = √160cm...
SIR PLEASE NEXT CH. ARITHMETIC PROGRESSIONS...😶😶
Sir q6 m cd = 12 cm de rakha h apne ca 12 cm kyu liya ?
5 cm = ad
57:06 Bp is ✓160 m❤❤❤
Hi sir
Sir circle ka chapter hua hai iss saal
Haa
@@shaileshsingh2173kaha hua hai
Link diya tho h
@@shaileshsingh2173 woh agla saal ka hai
AD =5555555555555555cm
❤
जय श्री राम
Class nine ka bhi lao, sir
sir nxt class 9 quadrlateral imp. questions ko video daal deve
All the best for today pre board 2 exam😅😂
Ashu sir ke bhai hain sir
Sir please quadratic equations extra questions karva dijiye
Good night sir ❤❤❤❤❤❤❤
Sir ka ta-ta-ta mst tha bhaii 😂 11:17
sir 19th November mat yaad dilaye 😢😢
Sir apa ashu sir ke brother hai
Sir you are looking like ashu sir😂
Uess
Because he is Ashu sir's brother
Hlo sir🎉🎉🎉🎉
Kal kis kis ka paper haa
sir please explain again
Sir kuch accha question karao
Sir samaj nhi aaya
41:58 = AD=5cm
AD value 5 cm
H.W = AD=5cm
AD= 5 cm...
Sir aap patle ho rahe hain 😂😂
Jim jaate hein
Sir aap 25th ko sample paper karva rahe ho aur us hi din mera pre board ka exam hai😢.
Btw love your videos❤😊
AP=AS
BP=BQ
CR=CQ
DR=DS
From all this equations based on tangent,
Adding this all::::
AP+BP+CR+DR=AS+BQ+CQ+DS
AB+CD=AD+BC
So after solving, AD=5cm
Sorry sir... Whole solution can't be written because it's somewhat long... 💖💖💖
😂
😢kisko kisko maths achha nahi lagta hai
5
ad = 5 cm
Ad=5
Hi
AD =5cm