Hello, i have a doubt Is there any problem when p and q have common factor. 2 can be written as 4/2 and it has common factor even though 2 is a rational number.
yes, that is exactly the way this proof works, if p and q have a common factor then the proof does not work. for example you cannot prove that 2 is irrational because it is in fact rational. It makes sense that you cannot prove something that is not true.
because things in mathematics need proof. if you don't have proof, you don't know it's true. if you don't know it's true, you can't go using it as an assumption indefinitely.
Because if you repeat all the steps up until 2q^2 = 4k^2 you’ll see that you actually get 4q^2 = 4k^2 ==> q^2 = k^2, and there is no contradiction there
he wanted to let the two on its own so since it was the square root of two, you do the opposite on the other side of the equal sign, which would make it squared
![Why you didn't learn tetration in school[Tetration]](http://i.ytimg.com/vi/Ea1_1aVfwl4/mqdefault.jpg)
You need to know how to do this proof for the LC, it came up last in 2019.
Nicely explained
Thanks!
Hello, i have a doubt
Is there any problem when p and q have common factor.
2 can be written as 4/2 and it has common factor even though 2 is a rational number.
yes, that is exactly the way this proof works, if p and q have a common factor then the proof does not work. for example you cannot prove that 2 is irrational because it is in fact rational. It makes sense that you cannot prove something that is not true.
Thanks pal!
why was this invented
because things in mathematics need proof. if you don't have proof, you don't know it's true. if you don't know it's true, you can't go using it as an assumption indefinitely.
Thank you
You're welcome!
why cant you prove that root 4 is also irrational using this way
You won't end with a contradiction if you do it with root 4, give it a try and see 😀
Simple Science and Maths thanks I tried and didn’t get any contradiction
@@devesh4289 great! 😎
2 would be irrational in that case
Because if you repeat all the steps up until 2q^2 = 4k^2 you’ll see that you actually get 4q^2 = 4k^2 ==> q^2 = k^2, and there is no contradiction there
Thankyou
You're welcome!
Sir why are we squaring?
he wanted to let the two on its own so since it was the square root of two, you do the opposite on the other side of the equal sign, which would make it squared
Thnk uu❤️
Ball
Wow