47:17 At point P Electric field is Positive because slope at p point is greater than 90°that means Slope has negative value and the electriic field is negative of slope therefore we get positive electric field.
47:12 At point p Electric field is positive as Φ theta is greater than 90° which means slope is negative So E=-(-Slope) therefore electric field is positive...
Sir aap se ek humble request hai ki please aap iss series ki video jaldi jaldi upload kijiye kyunki 17september ko mera first exam physics ka hai and i really need this video 😢😢😢😢😢 please sirrrrr
27:21 sir in my midterm exam, there was a question in continuation with this question on what the total capacitance will be. I know I am late by three months, but it would be really really helpful for me if you could answer this question. Thank you, sir. 27:21
Sir I really thanking you for making this series..🥺I really stressed about my preparation how will do and all ..I am not good in physics..but your this series really gonna save me thank you so much sir 🥺💗
Sir plz jldi backbncher... Series sre chpter krvado.... Mere phjk tcher n bola muje.. ki tuje 50 se uprnhi jana. Nhi hga trse.. 😢😢😢plz muje bhut feel horha h or abbh mein.. mrks lake dekungi 65++++ .. Plz yeh krdo apki help chaie 😢
@pihu_rana12 Check the calculation pihu if the answer got right is good but if doens't then use a calculator and strong the concepts. May this will help 👍🏻
sir what series is this ? just best i was struggling for 3hours and had nothing but watching this i can understand whats inside this chapter we want this series for shure
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Basi math
Sir numerical nhi ho rhe...!! Sabkuchh padne ke baad bhi
Sir oneshot book k ques k video solution chiy smjh ni atee ques kse kre
Numericals me sir😢
47:17 At point P Electric field is Positive because slope at p point is greater than 90°that means Slope has negative value and the electriic field is negative of slope therefore we get positive electric field.
BackBencher Vs Oneshot.....Jiske COmment jyada Next video vahi aayegi.
comment karke batao jaldi se.
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Oneshot
Backbencher sir chapter sequence wise hi kra do please one shot toh aapne already dal hi rkhe haib
Sir one shot
Backbencher sir chapter sequence wise hi kra do please one shot toh aapne already dal hi rkhe hai
One shot lecture
47:12 At point p Electric field is positive as Φ theta is greater than 90° which means slope is negative So E=-(-Slope) therefore electric field is positive...
Vote for 3rd chapter ❤
57:35 Value of k is -63*10^9 J
🎉🎉
-63*10^-9 this is correct
@@anmolsharma357 no bro he is correct
Achha ye Batao Next video konsi chahiye?
Waiting for your comment👇
Optics karva dijiye sir please
Sir optics krwa dijiye plsssss one shot mein
Sir 15 sept se half yearly h aur physics me part 1 Ara sir aap kuch batiye kya karu please reply Krna sir ❤❤
12 se half yearly hai sir or poori book aari hai 1st Wali.. jitna tab tak aap karwa skte h karwa dijiye
Sir sequence wise ho kra do please
Backlog finish ho gya tumhara ya reh gya h?
chαptєr 3 ☹️
Ch 4😊
Backbencher sir chapter sequence wise hi kra do please one shot toh aapne already dal hi rkhe hai
Abhi reh gya sir
Ch-7
21:00 answer is (2.1 x 10¹¹) volts
How
@UNRIVALLEDXGOD007 bhai tera kya hoga??
@@TheIslamicGamer bhai Mera 2.1x10^1 Ara ha samjha do thoda kaisa aya plz
21:25 --> 2.1x10^7
24:40 --> 1980v
47:26 --> im confused are we suppose to draw tengent ?
57:39 --> -63 x 10^9 J
21:25 21x10^10
47:17 same dude..
Sir aap se ek humble request hai ki please aap iss series ki video jaldi jaldi upload kijiye kyunki 17september ko mera first exam physics ka hai and i really need this video 😢😢😢😢😢 please sirrrrr
Kesa hua exam?
57:40 Potential Energy= -63×10⁹ J
47:17 Electric Field is +ve Because the slope is negative and the Angle Ø is greater than 90°
Series continue rakho plss syllabus kara doooo sir.. ❤❤❤
Thank you for this lecture.. ❤
Electric potential due to dipole on axial point 👉 27:0
47:17 Electric Field is +ve because slope is -ve
Backbencher series is the best series i have ever watched of physics
57:37 ans=-63×10^9
27:21 sir in my midterm exam, there was a question in continuation with this question on what the total capacitance will be. I know I am late by three months, but it would be really really helpful for me if you could answer this question. Thank you, sir. 27:21
Already answered
@ where “
@@Echosthatareepicn⅔ V
@@Echosthatareepicn⅔ v
47:22 electric field will be positive
21:23 Ans = 210 ×10^7
Sir I really thanking you for making this series..🥺I really stressed about my preparation how will do and all ..I am not good in physics..but your this series really gonna save me thank you so much sir 🥺💗
4:17 start ❤❤
❤
47:16
Electric field = +ve
21:00 [2.1×10^11]
24:50 [1980v]
Thoda samjo na 21:00 wali
@Iniy_07 21:00
Overall calculation:-9×10⁹ [ 70/3]
= 9×10⁹ [23.34]
= 2.10 × 10⁹
= 2.1 ×10² ×10⁹
= 2.1 × 10¹¹
Where,
Value of K=9×10⁹
Sir app se notes download nahi ho raha hai kya karu kal mera exam hai please🙏 sir help me😢😢😢😢😢😢❤
Sir plz jldi backbncher... Series sre chpter krvado.... Mere phjk tcher n bola muje.. ki tuje 50 se uprnhi jana. Nhi hga trse.. 😢😢😢plz muje bhut feel horha h or abbh mein.. mrks lake dekungi 65++++ ..
Plz yeh krdo apki help chaie 😢
Backbencher series sir because you have already made many chapters now Since Half yearly exms are coming , this series is must .
Bro mera parso h hak 😶
59:38 doubt- sir yaha pr V1 aaya Vr1 kyu nhi
Potential difference at general point ?
47:25 Slope is positive so electric field will be negative
bhai slope negative ho ga to ele field positive ho gye
57:30 ans -63x10⁹
57:36 Answer :- (-63×10⁹J)
Kaise aaya Yeh?? Mera -7 aa rha 😢
@pihu_rana12 Check the calculation pihu if the answer got right is good but if doens't then use a calculator and strong the concepts. May this will help 👍🏻
57:37 ans = -6.3 amstrong
Sir bohot maza aagya
It was very supportive content
This chapter was very hard for me but now it's too easy
Thank you sir ❤❤❤
1:02:29 / 1:39:18
sir iss question m mera 59.3 answer aa rha hai. kya 49.3 shi hai ya 59.3
57:40 U= -18*10^9
47:27 +ve 🎉
Sir please also provide time stamps in videos...so that it is easy for us to find a perticular topic...
my answer 21:22 25*10^(-4)v
Sir please upload the em waves lecture as soon as possible, I am waiting for the lecture.
Plz sir continue backbancher series❤
21:18 1.8*10^6
Bro Mera 2.1×10¹³ ara hai
@@Amansailor895 arre kaise
@@Jigyasaneet by taking LCM
Sir we need a dedicated series on numericals...how to approach them??
57:36 -63×10-9
How 🙂
24.34min answer is 1980
chapter starts at @4:24
24:50 1980 Volt answer
24:44 answer = 1980
Sir please backbencher series chaiya bohot backlog ho gaya hai please 21tak please 7 chapter tak 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Answer of potential enrgy for three charges -63×10^9j
Chapter 8 - electromagnetic waves🚨🚨🚨🚨🚨🚨
Sir yh electric field or potential relation ki derivation important h kya exam m aa skti h ky hmare sir ne direct formula lik waya tha
Sir har week main ek chapter ke backbenchers series nikal diya kariye
SIR aap sabse best hai🎉❤
Sir mene 10th se ab tak aaap se hi padha hai or hamesha acche marks score ki hai thank you so much sir ❤❤❤❤
sir what series is this ? just best i was struggling for 3hours and had nothing but watching this i can understand whats inside this chapter we want this series for shure
Bhai kuch nhi pdha yr mai kya is series se ache no aa jayenge ?
Reply plz
Backbenchers series pe
thanks a lot sir you made this chapter very easy to understand
Q.1. 21×10¹⁰
24:52 1980 V
Potential ki unit j/C hoti hai
@@meergamer1235uske badle usne v likha h koi newton nhi lagaya
24:40- 1980
A=abhishek sahu
B=bharat panchal
C= Cbse class videos
Achha batao tumhe Physics m sabse jyada problem kahan ho rhi hai?
Chapter 2 and 3 Pyq
Wedge and pulley constraint 😢 class 11th plz
Jac wale pdh skte h
Sir aap likhwa ke maximum cheez padhayeye pls printed notes thoda km kr dijiye
Sir derivation me😢
Backbencher series ❤❤❤❤
47:21 sir positive
57:37. -7K
24:54 V’=1980Volt
47:09 positive
1:12:21
24:52 ans - 1980V
24:52 v'=1980volt
Thank you so much sir ❤
Bhot ache se smjh aaya
thank you sir backbencher series are better for revisiion
Amazing lecture
Sir 3rd Chapter Le Aao Jaldi ❤❤
Sir chap 3 current and electricity... Pls sir
Back bencher series ❤❤
Sir ch 1,2 back log hai backbencher series dekhu ya app ka 4 hour wala one shot. Sir I am from state board I need 50 %theory
Oneshot
1st answer 2.1 × 10^11v
2nd answer 1980v
Continue backbenchers series
Mast ...maja aa gya padh ke ❤
Sir aapke padhne ka style dekh ke lgta hi nhi ki ye one shot h thank ou sir❤❤❤❤
Back bencher series 💪
Numericals and derivation 😢
Sir plz chapter 3 ki bi video dalo half yearly exam hain
Sir aapke iss class k notes telegram par show nhi ho rahe h
Is any derivation missing here??
Thank you so much sir for the proper notes❤️❤️❤️❤️
U=-1×10(9) ans
Is it enough for boards
Just practise some pyqs and then it will be enough
Thank u sir for providing such lecture❤
Sir ch 3 ka kab ayega one short
sir aap please aap derivation sath ka sath karvaya karo please sir 🙏
Backbenchers series of wave optics
physics book
part-2
Back bancher series ❤
😢😢 thanku sir....❤❤
Sir physics pe jada tar problem numericals pe ho rha hai
Sir app par printed notes upload kar dijiye please