1. It is the pressure exerted on small element by the fluid particles in the region around, not the external pressure used to move the fluid 2.since it is pressure, on both sides, the direction must be towards the element (pushing the element) 3. We have considered the fuild particles (mass) only in the small element, i.e.ds. hence it starts at zero in the left end and keep on increasing towards right hence the term, (rho (pressure)/rho(distance) × element distance, ds ) is added to the right end. Hope it clears your doubt
Why we not consider shear sir.? We consider newtons 2nd law its ok because of motion. 3rd law is there is equal and opposite reaction.. how can pressure force in cylindrical body will be negative..?
1. It is the pressure exerted on small element by the fluid particles in the region around, not the external pressure used to move the fluid 2.since it is pressure, on both sides, the direction must be towards the element (pushing the element) 3. We have considered the fuild particles (mass) only in the small element, i.e.ds. hence it starts at zero in the left end and keep on increasing towards right hence the term, (rho (pressure)/rho(distance) × element distance, ds ) is added to the right end. Hope it clears your doubt
In order to derive a concept we have to consider all possible features, so we assume that the pressure is increasing while the fluid is flowing through the control volume.
One more thing, always the external forces accelerate the objects (F=ma Newton's second law of motion) so the pressure is increased after traveling ds distance.
1. It is the pressure exerted on small element by the fluid particles in the region around, not the external pressure used to move the fluid 2.since it is pressure, on both sides, the direction must be towards the element (pushing the element) 3. We have considered the fuild particles (mass) only in the small element, i.e.ds. hence it starts at zero in the left end and keep on increasing towards right hence the term, (rho (pressure)/rho(distance) × element distance, ds ) is added to the right end. Hope it clears your doubt
1. It is the pressure exerted on small element by the fluid particles in the region around, not the external pressure used to move the fluid 2.since it is pressure, on both sides, the direction must be towards the element (pushing the element) 3. We have considered the fuild particles (mass) only in the small element, i.e.ds. hence it starts at zero in the left end and keep on increasing towards right hence the term, (rho (pressure)/rho(distance) × element distance, ds ) is added to the right end. Hope it clears your doubt
If you started this channel 6yrs ago means, i may took S grade in this subject... 100% useful sir!!!
Thanks sir very helpful sir
Thank you it is very helpful for me to understanding easily 😊
Thanks for your information and I understand sir thank you sir
Sir thankyou so much sir your teaching is in the next level
Superb class Sir thank you....❤
Sir tqqqq so much u have explained clearly tqqq
Thank you sir its very helpful
Thank you so much sir 🙏
Sir opposite pressure force how came plz explain in detail plzzzzzzzzzzzzz sir
According to Newton's Third Law of motion whenever a force acting on a body there will be a force opposite and equivalent it.
@@AUmechintamil ok sir, but how come the opposite pressure keeps increasing.. When the pressure at the bottom stays the same??
1. It is the pressure exerted on small element by the fluid particles in the region around, not the external pressure used to move the fluid
2.since it is pressure, on both sides, the direction must be towards the element (pushing the element)
3. We have considered the fuild particles (mass) only in the small element, i.e.ds. hence it starts at zero in the left end and keep on increasing towards right hence the term, (rho (pressure)/rho(distance) × element distance, ds ) is added to the right end.
Hope it clears your doubt
Tq sir very usefull🙏🏻🙏🏻
explanation is super!! but still could not figure why opposite force has addition of (+(dp/ds).ds)dA
Sir super sir..
super sir ....
Super sir
Sir , If the pressure force is more at outlet then how will liquid flow in that direction?
super sir
v useful ... ☺
Tq sir
Why we not consider shear sir.?
We consider newtons 2nd law its ok because of motion.
3rd law is there is equal and opposite reaction.. how can pressure force in cylindrical body will be negative..?
Samw doubt broo!!!!
Do you know the answer now??
1. It is the pressure exerted on small element by the fluid particles in the region around, not the external pressure used to move the fluid
2.since it is pressure, on both sides, the direction must be towards the element (pushing the element)
3. We have considered the fuild particles (mass) only in the small element, i.e.ds. hence it starts at zero in the left end and keep on increasing towards right hence the term, (rho (pressure)/rho(distance) × element distance, ds ) is added to the right end.
Hope it clears your doubt
Very clear explanation sir
Thanks sir i understand easily
Super sir
Thank you for your help sir.....
sir please teach Vibrations and design of machine elements.
Great explaination sir
Sir please explain sir why pressure increase if distance increase plzzzzzzzzzzzzz tell me sir I am eagerly waiting for your answer sir plzzzzzzzzzzzzz
In order to derive a concept we have to consider all possible features, so we assume that the pressure is increasing while the fluid is flowing through the control volume.
One more thing, always the external forces accelerate the objects (F=ma Newton's second law of motion) so the pressure is increased after traveling ds distance.
1. It is the pressure exerted on small element by the fluid particles in the region around, not the external pressure used to move the fluid
2.since it is pressure, on both sides, the direction must be towards the element (pushing the element)
3. We have considered the fuild particles (mass) only in the small element, i.e.ds. hence it starts at zero in the left end and keep on increasing towards right hence the term, (rho (pressure)/rho(distance) × element distance, ds ) is added to the right end.
Hope it clears your doubt
Semma sr
Why sir pressure force increase when it was going to section 2
Enakum same doubt bro..
Answer terinjutha ungaluku?
1. It is the pressure exerted on small element by the fluid particles in the region around, not the external pressure used to move the fluid
2.since it is pressure, on both sides, the direction must be towards the element (pushing the element)
3. We have considered the fuild particles (mass) only in the small element, i.e.ds. hence it starts at zero in the left end and keep on increasing towards right hence the term, (rho (pressure)/rho(distance) × element distance, ds ) is added to the right end.
Hope it clears your doubt