Wow! This is exactly what I was looking for. 10 loop problems in one video, perfect for practicing and mastering loop concepts in Python. Thanks for the clear explanations and concise solutions!
thankyou for this video. related to 10th question, i extender the code where we ask the user to input string and check it. the wait time increases if inputs wrong string. and in max 5th try, the code gives "blocked" statement. code below: import time wait_time = 1 max_tries = 5 attempts = 1 password = "password" while True: user_input = input("Enter password: ") if attempts < max_tries: if user_input == password: print("logged in succesfully") break else: print("wrong password")
@chaiaurcode There’s a small issue with the second solution. Instead of counting how many even numbers are present in 'n', we need to calculate the sum of even numbers up to 'n'. For example, if n = 10, the correct sum should be 2 + 4 + 6 + 8 + 10 = 30. To fix this, the code should add the even numbers themselves (e.g., i) to the total instead of just incrementing by 1 for each even number. Here’s the corrected solution for calculating the sum of even numbers up to 'n': n = 10 sum_even = 0 for i in range(1, n + 1): if i % 2 == 0: sum_even += i print("Sum of even numbers is:", sum_even)
00:02 Python loops have different internal workings and are iterable 02:32 Count the positive numbers in a list using a loop. 06:28 Solving problems using loops in Python 08:29 Loop to calculate the sum of even numbers 13:00 Using 'continue' to skip iterations in a loop 15:18 Learned reverse string using a loop. 19:22 Finding the first non-repeated character in a string using loops in Python 21:13 Optimizing Python code using break statement 25:02 Understanding factorial and implementing it using while loop 26:40 Finding factorial in Python using loops 30:48 Using while loops with user input and conditional checks in Python 32:39 Understanding the concept of prime numbers in Python. 36:46 Check for divisibility and prime numbers in Python 38:37 Check for zero remainder after division to determine if a number is prime. 42:41 Adding unique items to a set and detecting duplicates in a loop 44:31 Import time for managing wait time and attempts 48:05 Understanding the concept of wait time in loops Crafted by Merlin AI.
40:15 09_solution ko karna ka dusra tarika items = ["apple", "banana", "orange", "apple", "mango"] for i in items: if items.count(i) >1: print(i, "is a duplicate item in list.") break
Wow! This is exactly what I was looking for 10 loop problems in one video, perfect for practicing and mastering loop concepts in Python. Thanks for the clear explanations and concise solutions.
Generally while loop seems difficult to me, here is the answer to those who are trying using while loop:☺ Problem 1: # while list = [8, 5, -5 , -9, -7] n = 0 ij = 0 while n < len(list): if list[n] > 0: ij +=1 n +=1 print(ij) Problem 2 : # using while n = 0 s = 0 while n
The video covers solving 10 loops problems in Python, including understanding factorial, prime numbers, and input validation. It emphasizes the importance of wait times for system response and user experience, as well as the use of conditional checks for verifying uniqueness and avoiding duplicates in loops. 00:00 Understanding Loops and Iteration in Python 05:53 Understanding Loops and Iterations in Programming 11:48 Learning Python Programming: Looping and Reversing Strings 11:48Understanding the process of printing a table and complicated math for loops. 13:05Learning about conditional checks, detecting the fifth iteration, and using the 'continue' keyword. 15:26Exploring reverse string using loops and understanding the process of character swapping. 17:45 Optimizing String Manipulation and Looping in Python 23:41 Understanding Factorial Calculation Using While Loop in Python 29:34 Understanding Prime Numbers and Validating Solutions 35:28 Understanding Prime Numbers and Unique Items in Python 41:23 Understanding Unique Items and Conditional Checks 47:16 Understanding Sleep Time and System Response in Python Programming
def fancy_pattern(n): for i in range(n): for j in range(n): if (i + j) % 2 == 0: print("*", end=" ") else: print(" ", end=" ") print() fancy_pattern(10)
sir because of this course i have learnt many things...thank you for bringing this course for free ...... middle class families are successfull because of you
Q4. Reverse string using Loop a = "Gulab Alam" b = len(a)-1 while b >= 0: print(a[b]) b-=1 Using FOR Loop x = "Tarun" y = " " for i in x: y = i + y print(y)
Problem 3: table = int(input("Enter the table: ")) table_print = 1 for i in range(1, 10+1): if i == 5: continue table_print = table * i print(table, "*" ,i, "=", table_print)
Count Positive Number Using While Loop num = [1, -2, 3, -4, 5, 6, -7, -8, 9, 10] i = 0 postive_num = 0 while i < len(num): if num[i] > 0: postive_num+=1 i+=1 print("Final Count:",postive_num) Using For Loop num = [1, -2, 3, -4, 5, 6, -7, -8, 9, 10] postive_num1 = 0 for i in num: if i > 0: postive_num1+=1 print("Count of Positive Number:", postive_num1) Using List Comprehensive p= [i for i in num if i > 0] print("Positive Number in List:",len(p))
Multiplication Table Printer (upto 10, but skip 5th iteration) Using For Loop n = int(input("Enter the number: ")) for i in range (1,11): if i == 5: continue print(n,"*",i,"=",n*i) Using While Loop i = 1 num = 7 while i
Guys he is trying his best to teach us all the topics in a very different so we can learn all the complex and advance topics in a very easy manner, and in return all he asks just some comments, and we are not completing the goal. That's not fair, we should keep motivating him for his efforts.
for 7th problem, implemented the following solution: userIn = int(input("Enter a number: ")) while userIn not in range(1,11): print("Number out of range!") userIn = int(input("Enter a number: "))
Solution 2:- n = int(input("Enter a number: ")) sum_even = 0 for i in range(0, n, 2): sum_even += i print("The sum of all even numbers up to", n, "is", sum_even)
[Sir ,a little Correction Q_2] # number = int(input("Enter the number till you want to get sum :")) sum = 0 number = 10 for i in range(number): # if i % 2 == 0: sum = sum+i print(sum)
Even Number Question Solution . starting_range = int(input("Enter the number here: ")) ending_range = int(input("Enter the number here: ")) sum_even_num = 0 for num in range(starting_range,ending_range): if num%2==0: sum_even_num = sum_even_num + num print(sum_even_num)
For those who want to protect original number in factorial problem, create another value x then. x = number and then start loop and decrease x. Since x = x-1 will assign a new value to x, the value of number remains unaffected. But if you are still doubtful, just do x = int(number). This is initially create 2 values in memory.
Q2. Sum of Even Number Using For Loop(way-1) n = int(input("Enter the value of n:")) sum_1= 0 for i in range (0,n+1,2): sum_1+=i print("Sum of Even Number:", sum_1) Using For Loop(way-2) num = int(input("Enter the value of num:")) sum_positive_num=0 for i in range(0,num+1): if i%2==0: sum_positive_num+=i print("Sum of Even Num:", sum_positive_num) Using While Loop number = int(input("Enter Number:")) count_of_even = 0 i=0 while i < number+1: if i%2==0: count_of_even+=i i+=1 print("Sum of even number:",count_of_even)
# Problem: Calculate the sum of even numbers up to a given number n. number : int = int(input("Enter a number up to which you want to calclate sum of even numbers")) sum_of_even_numbers:int = 0 for i in range(1,number+1): if i%2 == 0: sum_of_even_numbers = sum_of_even_numbers+ i print(sum_of_even_numbers)
# Sum of Even Numbers # Problem: Calculate the sum of even numbers up to a given number n. n = int(input("Enter the number: ")) sum_of_even = 0 for item in range(1, n + 1): if item % 2 == 0: sum_of_even += item # Add the even number to sum_of_even print(sum_of_even)
10:15 Sir it's wrong... Correct Answer : 30 Correct Code : n=10 sum_even=0 for i in range(1,n+1): if(i%2==0): sum_even += i print("Sum of even numbers are :",sum_even)
Solution of the 2nd Problem: num=int(input("Enter the number here")) sum_even_num=0 for i in range(num+1): if i%2==0: sum_even_num=sum_even_num+i print("Sum of even nos. is", sum_even_num)
Abdul Wahid from Bangladesh ------------------------------------05 number = 5 factorial = 1 while number > 0: factorial = factorial * number number = number - 1 print("factorial number value is : ", factorial)
# 7. Validate Input Solution # collects user input number = int(input("Enter a number between 1 and 10: ")) # verifying user input while (number < 1) or (number > 10): print("Please enter a valid number") number = int(input("Enter a number between 1 and 10: ")) # showing the entered number print(f"You have entered {number}")
I think "f" string is more good then that like we do in javascript ``` number = 3 for i in range(1, 11): if i == 5: print(""" "5" is Detected""") continue print(f"{number} x {i}= {number * i}") ```
one more way to create the third solution: num = int(input("enter you table number: ")) for i in range(1,11): if i != 5: print(num, "X", i, "=", num*i )
2 --> num = 10 sun_even = 0 initial_num = 0 for i in range(10): initial_num +=1 if initial_num % 2 == 0: sun_even += 1 print(initial_num) num +=initial_num print("the total is :", num) print("the total is :", sun_even)
i have 2 years of experience in Python but still watch your video to get the internal working of each topic.🫡 After watching your video i have started to assign the value by giving space. before=2 after = 2 😅😅
# Problem: Print the multiplication table for a given number up to 10, but skip the fifth iteration. n = int(input("Enter a number: ")) for i in range(1,11): if(i==5): continue print("{} * {} = {}".format(n,i,(n*i)))
For Problem 2, Question is asking to sum all even numbers, Not just count. The correct solution is anyone is wondering is : - def sum_checker(n): even_list = [] for i in range(1,n+1): if i%2 == 0: even_list.append(i) final_sum = sum(even_list) return final_sum
Problem 1: numbers = [1, -2, 3, -4, 5, 6, -7, -8, 9, 10] positive_number_count = 0 for num in numbers: num = int(num) if num > 0: positive_number_count += 1 print("Final count positive number is:",positive_number_count)
It is very disheartening to see that very few people are following this amazing playlist. The habit of consuming content has made our mindset so fragile that we could scroll shorts for infinity but we can't sit back straight for an hour to solve basic problems. And then people will whine about AI taking over us on the internet. If we do not change this way of living then maybe the AI doom is inevitable. But if we start learning and developing a problem-solving mindset rather than watching endless tutorials then we could really grow professionally and personally. This playlist, and almost every other playlist made by Hitesh sir really beats any paid tutorials since this series develops a problem-solving mindset rather than making people syntax ninja.
For those who didn't understand the " reverse string code " : input_string = "Python" reverse_string = "" for char in input_string : # reverse_string = reverse_string + char reverse_string = char + reverse_string print(reverse_string) Explaination:- Iteration 1 (char = 'P'): At the beginning, reverse_string is an empty string. After the first iteration, reverse_string becomes 'P'. Iteration 2 (char = 'y'): reverse_string is currently 'P'. Concatenating 'y' with 'P', so reverse_string becomes 'yP'. Iteration 3 (char = 't'): reverse_string is currently 'yP'. Concatenating 't' with 'yP', so reverse_string becomes 'tyP'. Iteration 4 (char = 'h'): reverse_string is currently 'tyP'. Concatenating 'h' with 'tyP', so reverse_string becomes 'htyP'. Iteration 5 (char = 'o'): reverse_string is currently 'htyP'. Concatenating 'o' with 'htyP', so reverse_string becomes 'ohtyP'. Iteration 6 (char = 'n'): reverse_string is currently 'ohtyP'. Concatenating 'n' with 'ohtyP', so reverse_string becomes 'nohtyP'. After the loop completes, reverse_string contains the reversed version of the input string 'Python', which is 'nohtyP'.
def positive_count(a): count =0 negetive_count=0 for i in a: if i>=0: count+=1 else: negetive_count+=1 print("total positive count is :",count) print("total -ve count is:",count) a =[1,-2,3,4,-5,6,-7,8,-9,10] positive_count(a)
#Prime Number Checker n = int(input("Enter the number to check either it is prime or not: ")) if n > 1: for i in range (2, n): if (n % i) == 0: print(f"{n} is not a prime number") break else: print(f"{n} is the Prime Number")
q2 soln::
n = int(input("Enter a number: "))
sum=0
for num in range(0,n+1):
if(num%2==0):
sum+=num
print("Sum of even numbers from 0 to",n,"is",sum)
Wow! This is exactly what I was looking for. 10 loop problems in one video, perfect for practicing and mastering loop concepts in Python. Thanks for the clear explanations and concise solutions!
Sum of even :-
even_sum=0
N=10
for i in range(1,N+1):
If (i%2==0):
even_sum+=i
print(even_sum)
😂😂😂
wrong
thankyou for this video. related to 10th question, i extender the code where we ask the user to input string and check it. the wait time increases if inputs wrong string. and in max 5th try, the code gives "blocked" statement. code below:
import time
wait_time = 1
max_tries = 5
attempts = 1
password = "password"
while True:
user_input = input("Enter password: ")
if attempts < max_tries:
if user_input == password:
print("logged in succesfully")
break
else:
print("wrong password")
print("Attempt: ", attempts, " | wait time: ", wait_time,"seconds | max attempts: ", max_tries)
time.sleep(wait_time)
wait_time *= 2
attempts += 1
else:
print("Your are blocked. please contact branch manager")
@chaiaurcode
There’s a small issue with the second solution. Instead of counting how many even numbers are present in 'n', we need to calculate the sum of even numbers up to 'n'. For example, if n = 10, the correct sum should be 2 + 4 + 6 + 8 + 10 = 30.
To fix this, the code should add the even numbers themselves (e.g., i) to the total instead of just incrementing by 1 for each even number.
Here’s the corrected solution for calculating the sum of even numbers up to 'n':
n = 10
sum_even = 0
for i in range(1, n + 1):
if i % 2 == 0:
sum_even += i
print("Sum of even numbers is:", sum_even)
00:02 Python loops have different internal workings and are iterable
02:32 Count the positive numbers in a list using a loop.
06:28 Solving problems using loops in Python
08:29 Loop to calculate the sum of even numbers
13:00 Using 'continue' to skip iterations in a loop
15:18 Learned reverse string using a loop.
19:22 Finding the first non-repeated character in a string using loops in Python
21:13 Optimizing Python code using break statement
25:02 Understanding factorial and implementing it using while loop
26:40 Finding factorial in Python using loops
30:48 Using while loops with user input and conditional checks in Python
32:39 Understanding the concept of prime numbers in Python.
36:46 Check for divisibility and prime numbers in Python
38:37 Check for zero remainder after division to determine if a number is prime.
42:41 Adding unique items to a set and detecting duplicates in a loop
44:31 Import time for managing wait time and attempts
48:05 Understanding the concept of wait time in loops
Crafted by Merlin AI.
40:15 09_solution ko karna ka dusra tarika
items = ["apple", "banana", "orange", "apple", "mango"]
for i in items:
if items.count(i) >1:
print(i, "is a duplicate item in list.")
break
Ha bhai same Maine bhi aise hi Kiya tha 😅😅 and it worked
exactly bro. pichle wale is concept me unique value(count==1) find kar rahe the and isme duplicate (count>1) find kar rahe. using same code concept
Wow! This is exactly what I was looking for 10 loop problems in one video, perfect for practicing and mastering loop concepts in Python. Thanks for the clear explanations and concise solutions.
# 10.Exponential Backoff
import time
# definying values
wait_time = 1
max_retries = 5
attempts = 0
# calculating times and attemps
while attempts < max_retries:
attempts += 1
left_attempts = max_retries - attempts
time.sleep(wait_time)
wait_time *= 2
if left_attempts > 0:
print(f"{left_attempts} attempts left")
print(f"Wait {wait_time}s for next try")
elif left_attempts == 0:
print("No attempt left")
print("Try Tomorrow,Good Night")
Hitesh sir tons of love from Nepal you are just amazing , the effort, the content and ofCourse the quality education no one can match your level
Generally while loop seems difficult to me, here is the answer to those who are trying using while loop:☺
Problem 1:
# while
list = [8, 5, -5 , -9, -7]
n = 0
ij = 0
while n < len(list):
if list[n] > 0:
ij +=1
n +=1
print(ij)
Problem 2 :
# using while
n = 0
s = 0
while n
The video covers solving 10 loops problems in Python, including understanding factorial, prime numbers, and input validation. It emphasizes the importance of wait times for system response and user experience, as well as the use of conditional checks for verifying uniqueness and avoiding duplicates in loops.
00:00
Understanding Loops and Iteration in Python
05:53
Understanding Loops and Iterations in Programming
11:48
Learning Python Programming: Looping and Reversing Strings
11:48Understanding the process of printing a table and complicated math for loops.
13:05Learning about conditional checks, detecting the fifth iteration, and using the 'continue' keyword.
15:26Exploring reverse string using loops and understanding the process of character swapping.
17:45
Optimizing String Manipulation and Looping in Python
23:41
Understanding Factorial Calculation Using While Loop in Python
29:34
Understanding Prime Numbers and Validating Solutions
35:28
Understanding Prime Numbers and Unique Items in Python
41:23
Understanding Unique Items and Conditional Checks
47:16
Understanding Sleep Time and System Response in Python Programming
No one cares to make their students practice actual problems. Thank you sir for such a wonderful hands-on series.
def factorial(a):
mul=1
i=1
while i
3 -- >
num = 5
for i in range(1,11):
if i == 5:
continue
print(f"{num} x {i} = ",num * i)
def sums(a):
sum_ =0
i =0
while i
def fancy_pattern(n):
for i in range(n):
for j in range(n):
if (i + j) % 2 == 0:
print("*", end=" ")
else:
print(" ", end=" ")
print()
fancy_pattern(10)
33:06
a=(int(input('enter a:'))
While 0>a or a
sir because of this course i have learnt many things...thank you for bringing this course for free ...... middle class families are successfull because of you
number = int(input("enter one number:-"))
factorial = 1
for i in range(1, number + 1):
factorial *= i
print("factorial of given number is", factorial)
Q4. Reverse string using Loop
a = "Gulab Alam"
b = len(a)-1
while b >= 0:
print(a[b])
b-=1
Using FOR Loop
x = "Tarun"
y = " "
for i in x:
y = i + y
print(y)
I really appreciate your videos! The way you explain things in such depth makes it easy to understand complex concepts. Keep up the great work!
Problem 2:
n = int(input("Enter the nth number: "))
sum_even = 0
for i in range(1, n+1):
if i%n == 0:
sum_even = i + n
print(sum_even)
Multiplication Table:
n = int(input("Enter a number : "))
for i in range(1,11):
if i != 5:
print(n, "*", i, "=", n*i)
Problem 3:
table = int(input("Enter the table: "))
table_print = 1
for i in range(1, 10+1):
if i == 5:
continue
table_print = table * i
print(table, "*" ,i, "=", table_print)
i can't even fathom how simple it has become to understand the concepts with this course (and interesting too, hehe)
find tuned approach to hammer the basic of any given chapter through this 10 problem solving mechanism...thank you sir.
I am really thankful we have TH-cam , otherwise this masterpiece may have been lost
num = int(input("Enter the number :"))
sum = 0
for i in range(1, num + 1):
if i % 2 == 0:
print(i)
sum = sum + i
print("sum is ", sum)
Question 02 solution:
n = int(input("Enter no.=> "))
sum = 0
for i in range (1, n+1):
if i%2 == 0:
sum = sum + i
print ("sum=>", sum)
def keep_ask(a):
a =int(a)
while a>10:
a =int(input("enter the number again:" ))
if 1
#Validate Input
on = True
while on:
ask = input("Plese type a number (1-10) : ")
try:
if int(ask) >= 1 and int(ask)
def revers_string(a):
reverse =""
i =len(a)-1
while i>=0:
reverse+=a[i]
i-=1
print(reverse)
a =input("enter the string:")
revers_string(a)
ans--4
Count Positive Number
Using While Loop
num = [1, -2, 3, -4, 5, 6, -7, -8, 9, 10]
i = 0
postive_num = 0
while i < len(num):
if num[i] > 0:
postive_num+=1
i+=1
print("Final Count:",postive_num)
Using For Loop
num = [1, -2, 3, -4, 5, 6, -7, -8, 9, 10]
postive_num1 = 0
for i in num:
if i > 0:
postive_num1+=1
print("Count of Positive Number:", postive_num1)
Using List Comprehensive
p= [i for i in num if i > 0]
print("Positive Number in List:",len(p))
number = 10
sum = 0
for i in range(1,number+1):
if i % 2 == 0:
sum += i
print(sum)
Ans is : 30
bro sum is a method ap variable ka name change kro
Multiplication Table Printer (upto 10, but skip 5th iteration)
Using For Loop
n = int(input("Enter the number: "))
for i in range (1,11):
if i == 5:
continue
print(n,"*",i,"=",n*i)
Using While Loop
i = 1
num = 7
while i
sir ma comment nhe krte zada but sach ma apke content oop ha mujhe khe bhe smj nhe ayethe js apne smja de or ab python ma loops sir seriously hats off
#Factorial Using While Loop
n = int(input("Enter Number which to be factorial: ")) i=1
while_fact = 1
while i
list uniqueness and exponential backoff - 2 very unique problems.. Great clarity on loops
Bro is there a issue in the list uniqeness code bcz im having type eroor of list obj isnt callable
Sir love the way you explain the complex concepts easily in a simple way Hats off to you❤❤
# Sum of even numbers
n = 5
sum_even = 0
for i in range(1,n+1):
if i%2 == 0:
sum_even += i
print("Sum of even number is:" ,sum_even)
Guys he is trying his best to teach us all the topics in a very different so we can learn all the complex and advance topics in a very easy manner, and in return all he asks just some comments, and we are not completing the goal. That's not fair, we should keep motivating him for his efforts.
number = 3
for i in range(1,11):
if(i==5):
continue
print(number*i)
numb = 5
factorial = 1
# while numb > 0:
# factorial = factorial * numb
# numb = numb -1
# print(factorial)
for i in range(numb):
factorial = factorial * (i+1)
print(factorial)
def mul_n(a):
i=1
while i
for 7th problem, implemented the following solution:
userIn = int(input("Enter a number: "))
while userIn not in range(1,11):
print("Number out of range!")
userIn = int(input("Enter a number: "))
Solution 2:-
n = int(input("Enter a number: "))
sum_even = 0
for i in range(0, n, 2):
sum_even += i
print("The sum of all even numbers up to", n, "is", sum_even)
[Sir ,a little Correction Q_2]
# number = int(input("Enter the number till you want to get sum :"))
sum = 0
number = 10
for i in range(number):
# if i % 2 == 0:
sum = sum+i
print(sum)
Even Number Question Solution .
starting_range = int(input("Enter the number here: "))
ending_range = int(input("Enter the number here: "))
sum_even_num = 0
for num in range(starting_range,ending_range):
if num%2==0:
sum_even_num = sum_even_num + num
print(sum_even_num)
For those who want to protect original number in factorial problem, create another value x then.
x = number and then start loop and decrease x. Since x = x-1 will assign a new value to x, the value of number remains unaffected.
But if you are still doubtful, just do x = int(number). This is initially create 2 values in memory.
while True:
user_input = int(input("Enter a number b/w 1 to 10: "))
# if user_input >= 1 and user_input
def find_Factorial(n):
sum = 1
for i in range(1,n+1):
sum *= i
print (sum)
n = int(input("enter no: "))
find_Factorial(n)
n= 10
sum = 0
for num in range(1,n+1):
if(num%2==0):
sum+=num
print(sum)
a = 2
for i in range(1, 11):
if i == 5:
continue
else:
print(a * i)
This teaching technique is best for understanding please implement this technique in other courses, please
It's my humble request to Hitesh Sir Jii
# Calculate the sum of even numbers up to give number n
n = 10
sum = 0
for i in range(2,n+1,2):
sum += i
print(sum)
Q2. Sum of Even Number
Using For Loop(way-1)
n = int(input("Enter the value of n:"))
sum_1= 0
for i in range (0,n+1,2):
sum_1+=i
print("Sum of Even Number:", sum_1)
Using For Loop(way-2)
num = int(input("Enter the value of num:"))
sum_positive_num=0
for i in range(0,num+1):
if i%2==0:
sum_positive_num+=i
print("Sum of Even Num:", sum_positive_num)
Using While Loop
number = int(input("Enter Number:"))
count_of_even = 0
i=0
while i < number+1:
if i%2==0:
count_of_even+=i
i+=1
print("Sum of even number:",count_of_even)
# Problem: Calculate the sum of even numbers up to a given number n.
number : int = int(input("Enter a number up to which you want to calclate sum of even numbers"))
sum_of_even_numbers:int = 0
for i in range(1,number+1):
if i%2 == 0:
sum_of_even_numbers = sum_of_even_numbers+ i
print(sum_of_even_numbers)
for i in range(1,N+1):
If (i%2==0):
even_sum+=i
Correct bro
# Sum of Even Numbers
# Problem: Calculate the sum of even numbers up to a given number n.
n = int(input("Enter the number: "))
sum_of_even = 0
for item in range(1, n + 1):
if item % 2 == 0:
sum_of_even += item # Add the even number to sum_of_even
print(sum_of_even)
sir i think in 2nd problem the question would be count the even no. upto n (sum means 2+4+6+8+10)
n = 10
even = 0
for i in range(1,n+1):
if i % 2 == 0:
even += i
print(even)
that's why I thought. It should have been (sum means 2+4+6+8+10). Maybe he meant counting total number of even numbers up to 10.
@@SamraatMaharjan yes, i also came for this. it is mentioned sum of even numbers not count of even numbers
numbers = range(11)
sum = 0
for nums in numbers:
if nums % 2 == 0:
sum += nums
print(sum)
number = 15
sum = 0
for num in range(0, number+1):
if num % 2 == 0:
sum = sum + num
print("Total sum is ", sum)
Thank you Hitesh Bhai for the Great Course and Teaching Style
Question: 7-
while True:
number=int(input("please enter the number between 1 and 10 :"))
if 1
numbers=[1,-2,3,-4,5,6,-7,-8,9,10]
n=len(numbers)
count=0
for i in range(n):
if numbers[i]>0:
count=count+1
print(count)
10:15 Sir it's wrong...
Correct Answer : 30
Correct Code :
n=10
sum_even=0
for i in range(1,n+1):
if(i%2==0):
sum_even += i
print("Sum of even numbers are :",sum_even)
Solution 2:
n = 10
sum_even = 0
for i in range(1, n+1):
if(i%2==0):
sum_even = sum_even + i
print(sum_even)
n = 10
sum_even = 0
for y in range(1,n+1):
if y%2 == 0:
sum_even = y + sum_even
print(sum_even)
This is the correct code for the problem no 2
numbers = [1,-2,3,-4,5,6,-7,-8,9,10]
for num in numbers:
if(num>=0):
print(num)
Been truly amazing classes Getting valuable things for free.
Good initiative !!
Sir aap dheere dheere aage bdte ho baki you tubers ek dum se 😂😂😂😂😂😂aap bdiya ho 😊😊
Solution of the 2nd Problem:
num=int(input("Enter the number here"))
sum_even_num=0
for i in range(num+1):
if i%2==0:
sum_even_num=sum_even_num+i
print("Sum of even nos. is", sum_even_num)
Abdul Wahid
from Bangladesh
------------------------------------05
number = 5
factorial = 1
while number > 0:
factorial = factorial * number
number = number - 1
print("factorial number value is : ", factorial)
29:43 sir try kiya
fruit_color="Yellow"
if fruit_color=="Green":
status="Unripe"
elif fruit_color=="Yellow":
status="Ripe"
elif fruit_color=="Brown":
status="Overripe"
print("fruit are",status)
# 7. Validate Input Solution
# collects user input
number = int(input("Enter a number between 1 and 10: "))
# verifying user input
while (number < 1) or (number > 10):
print("Please enter a valid number")
number = int(input("Enter a number between 1 and 10: "))
# showing the entered number
print(f"You have entered {number}")
number = 5
factorial = 1
while number > 0:
factorial *= number
number = number - 1
print("factorial number value is : ", factorial)
Vote For JAVA Series also Guys. We want someone Bigger Than Abdul Bari Sir and i think Hitesh Sir can only do that.
distance = int(input("Enter Distace of your location : "))
if distance 3 and distance 15:
mode = "Car"
print(mode)
QN2//
solutions
# sum of Even numbers
even_number=int(input("enter n:"))
sum=0
for num in range(0,even_number+1):
if num%2==0:
sum=sum+num
print(sum)
Sir Question no 2 me aapne sum of even number ki jagah count of even number nikala h. Correct it
I think "f" string is more good then that like we do in javascript
```
number = 3
for i in range(1, 11):
if i == 5:
print(""" "5" is Detected""")
continue
print(f"{number} x {i}= {number * i}")
```
#string reverse using while loop
university_name = 'Riphah International University'
string_length = len(university_name)-1
while(string_length>=0):
print(university_name[string_length] , end=' ')
string_length = string_length-1
Great Examples, Simplest Explanations, Thank You
for #2 problem --> sum_even += i #30
for #4 problem another way could be --> for char in name:
rev_string = rev_string.join(char) + rev_string
one more way to create the third solution:
num = int(input("enter you table number: "))
for i in range(1,11):
if i != 5:
print(num, "X", i, "=", num*i )
2 -->
num = 10
sun_even = 0
initial_num = 0
for i in range(10):
initial_num +=1
if initial_num % 2 == 0:
sun_even += 1
print(initial_num)
num +=initial_num
print("the total is :", num)
print("the total is :", sun_even)
i have 2 years of experience in Python but still watch your video to get the internal working of each topic.🫡
After watching your video i have started to assign the value by giving space.
before=2
after = 2
😅😅
import random
Weather = ["Sunny", "Snowy","Rainy"]
all_weather = random.choice(Weather)
if all_weather == "Sunny":
print("Go for a walk")
elif all_weather == "Rainy":
print("Read a Book")
elif all_weather == "Snowy":
print("Build a snow man")
# Problem: Print the multiplication table for a given number up to 10, but skip the fifth iteration.
n = int(input("Enter a number: "))
for i in range(1,11):
if(i==5):
continue
print("{} * {} = {}".format(n,i,(n*i)))
Always waiting for your video's sir 😊
For Problem 2, Question is asking to sum all even numbers, Not just count. The correct solution is anyone is wondering is : -
def sum_checker(n):
even_list = []
for i in range(1,n+1):
if i%2 == 0:
even_list.append(i)
final_sum = sum(even_list)
return final_sum
Nope. Aapne question hamesha isi trh dekha h, isliye yahi sahi solution lagta h.
Kuch different h ye
@@chaiaurcode Sir, you did Counting of even Number i guess ?
10:16 sir sum_even +=I ayega sum of even number ke liye
Problem 1:
numbers = [1, -2, 3, -4, 5, 6, -7, -8, 9, 10]
positive_number_count = 0
for num in numbers:
num = int(num)
if num > 0:
positive_number_count += 1
print("Final count positive number is:",positive_number_count)
Thank you❤❤❤
Wow never have seen the final question before. Very nice 🤔
It is very disheartening to see that very few people are following this amazing playlist. The habit of consuming content has made our mindset so fragile that we could scroll shorts for infinity but we can't sit back straight for an hour to solve basic problems. And then people will whine about AI taking over us on the internet. If we do not change this way of living then maybe the AI doom is inevitable. But if we start learning and developing a problem-solving mindset rather than watching endless tutorials then we could really grow professionally and personally. This playlist, and almost every other playlist made by Hitesh sir really beats any paid tutorials since this series develops a problem-solving mindset rather than making people syntax ninja.
অসাধারণ একটা কোর্স I am from Bangladesh
For those who didn't understand the " reverse string code " :
input_string = "Python"
reverse_string = ""
for char in input_string :
# reverse_string = reverse_string + char
reverse_string = char + reverse_string
print(reverse_string)
Explaination:- Iteration 1 (char = 'P'):
At the beginning, reverse_string is an empty string.
After the first iteration, reverse_string becomes 'P'.
Iteration 2 (char = 'y'):
reverse_string is currently 'P'.
Concatenating 'y' with 'P', so reverse_string becomes 'yP'.
Iteration 3 (char = 't'):
reverse_string is currently 'yP'.
Concatenating 't' with 'yP', so reverse_string becomes 'tyP'.
Iteration 4 (char = 'h'):
reverse_string is currently 'tyP'.
Concatenating 'h' with 'tyP', so reverse_string becomes 'htyP'.
Iteration 5 (char = 'o'):
reverse_string is currently 'htyP'.
Concatenating 'o' with 'htyP', so reverse_string becomes 'ohtyP'.
Iteration 6 (char = 'n'):
reverse_string is currently 'ohtyP'.
Concatenating 'n' with 'ohtyP', so reverse_string becomes 'nohtyP'.
After the loop completes, reverse_string contains the reversed version of the input string 'Python', which is 'nohtyP'.
def positive_count(a):
count =0
negetive_count=0
for i in a:
if i>=0:
count+=1
else:
negetive_count+=1
print("total positive count is :",count)
print("total -ve count is:",count)
a =[1,-2,3,4,-5,6,-7,8,-9,10]
positive_count(a)
#Prime Number Checker
n = int(input("Enter the number to check either it is prime or not: "))
if n > 1:
for i in range (2, n):
if (n % i) == 0:
print(f"{n} is not a prime number")
break
else:
print(f"{n} is the Prime Number")