really sir ap itne hard topic ko bi easy bana dete ho 🙏🙏🙏❣ every student should give feedback on comment if you learn something becsuse in future someone find toc lecture for gate they watch first comment or feedback about this lecture
L1 is regular L2 is CFL bar( bar(L1) union bar(L2)) == bar(Regular union CSL) == bar(CSL) == CSL but bar( bar(L1) union bar(L2)) == L1 intersection L2 = Regular intersection CFL == CFL How is this possible ?
Yes additional closure properties ka video dekh lo.... BTW I have not skipped even a single topic you just name it and you will find it my playlist....
@@AmitKhuranaSir Sir. Ek hi dil hai. Kitni baar jeetoge aap. Shukriya sir. Aap teaching ki asli parakashtha ko saamne rakh rahe ho.. dhanya hai sab jo apse padh rahe hai.
L1 is regular L2 is CFL bar( bar(L1) union bar(L2)) == bar(Regular union CSL) == bar(CSL) == CSL but bar( bar(L1) union bar(L2)) == L1 intersection L2 = Regular intersection CFL == CFL How is this possible ?
We have to go by precidence that is outer bar will be solved first and CFL is correct option.... For more detail refer.... th-cam.com/video/vZjvHpdE7S8/w-d-xo.html Start watching above video from 50:00 BTW nice doubt...
Sir! amazing lectures🙏😭
Jo doubts ate h unhe app khud he videos m bta dete ho.😇❤
really sir ap itne hard topic ko bi easy bana dete ho 🙏🙏🙏❣ every student should give feedback on comment if you learn something becsuse in future someone find toc lecture for gate they watch first comment or feedback about this lecture
wonderful lecture sir!
L1 is regular
L2 is CFL
bar( bar(L1) union bar(L2)) == bar(Regular union CSL) == bar(CSL) == CSL
but
bar( bar(L1) union bar(L2)) == L1 intersection L2 = Regular intersection CFL == CFL
How is this possible ?
37:30
sir @37:36 u told that,if a language not closed in intersection then it will not be closed in complement also ...bt in DCFL it holds.......
yes you are right
mesmerizing lectures..
great Video 🤯
Amazing
Thankyou sir🎉🎉🎉🎉❤
Sir why CFL n CSL is not CFL. Common toh sir CFL hi niklegi doono me se
a^nb^nc^m ∩ a^nb^nc^n
Will be what?
@@AmitKhuranaSir Thank you for your reply Sir 🙏🙏🙏 I will remember this case
Sir homomorphism important hai?
Yes questions have come in GATE...
@@AmitKhuranaSir sir aapne aage playlist mein samjhaye hai?
Yes additional closure properties ka video dekh lo....
BTW I have not skipped even a single topic you just name it and you will find it my playlist....
@@AmitKhuranaSir Sir. Ek hi dil hai. Kitni baar jeetoge aap. Shukriya sir. Aap teaching ki asli parakashtha ko saamne rakh rahe ho.. dhanya hai sab jo apse padh rahe hai.
nice😊👏👍
L1 is regular
L2 is CFL
bar( bar(L1) union bar(L2)) == bar(Regular union CSL) == bar(CSL) == CSL
but
bar( bar(L1) union bar(L2)) == L1 intersection L2 = Regular intersection CFL == CFL
How is this possible ?
We have to go by precidence that is outer bar will be solved first and CFL is correct option....
For more detail refer....
th-cam.com/video/vZjvHpdE7S8/w-d-xo.html
Start watching above video from 50:00
BTW nice doubt...
nice😊👏