Hi, just here to say a BIG THANKS for all your videos. Clear, concise, entertaining, funny, no ceremony, pure know-how transfer on the fast lane. Keep it up and know that what you do and How you do it is HIGHLY appreciated.
great demonstration ,thank you! btw. do you have any plans to make a video about "how to calculate capacitor size " (for a circuit) ? it seems there is not much info about this..... maybe it's too complicated ? i'm trying to make a 5v relay to energize for only a second or so, but i can't figure it out with just the RC time constant ... only by trial and error, maybe i'm missing something.... (well, i'm sure i do....)
Honestly, I've found that trial-and-error (as in, use a trimpot/potentiometer or other sort of variable resistor) is the quickest and easiest way. Most circuits have some sort of approximate formula but none of them are exact, due to physical realities. My usual method is 1) use formula (or just R times C if no formula is available) to guesstimate an R and C that are within the "reasonable" range (so, not 2 megaohms and not 0.1 picofarad, or something else silly), 2) put capacitor in and use trimpot for resistor (because a variable resistor is easy, and a variable capacitor is much less easy), 3) alter capacitor value and re-do step 2 if necessary. It's where an oscilloscope is a lifesaver, because I can just have the circuit live in the oscilloscope and turn the trimpot knob and quickly get it right just by looking at the oscilloscope screen.
@@simplyput2796 did it a bit differently.... ,but you gave me a great idea ! to use my oscilloscope !!! i was lost in searching a formula to do it "properly" and completely forgot about it....
I know that I am a little late to the party but I would like to add some remark about your explanation of the deviation between the currents displayed on the power supply and the current meter as mentioned at 14:44. You forgot that you need the 3.6 mA (see 13:15) to drive the base of the second transistor in order to achieve an emitter current of 170 mA. This current is now drawn from the power supply. Hence the power supply shows 176.4 mA + 3.6 mA = 180 mA. So in this case this is not the reason for the "inaccuracy" of the power supply, which of course exists.
Yep, I'm just really bad at time management which makes my personal productive life incredibly sporadic. It's why I'm careful to not make promises, so I never disappoint anyone. :P
Hi, just here to say a BIG THANKS for all your videos. Clear, concise, entertaining, funny, no ceremony, pure know-how transfer on the fast lane. Keep it up and know that what you do and How you do it is HIGHLY appreciated.
Darlington is my choice in building amp
You da man!
Thanks for the video =)
thank you well done
great demonstration ,thank you!
btw.
do you have any plans to make a video about "how to calculate capacitor size " (for a circuit) ?
it seems there is not much info about this..... maybe it's too complicated ?
i'm trying to make a 5v relay to energize for only a second or so, but i can't figure it out with just the RC time constant ...
only by trial and error, maybe i'm missing something.... (well, i'm sure i do....)
Honestly, I've found that trial-and-error (as in, use a trimpot/potentiometer or other sort of variable resistor) is the quickest and easiest way. Most circuits have some sort of approximate formula but none of them are exact, due to physical realities. My usual method is 1) use formula (or just R times C if no formula is available) to guesstimate an R and C that are within the "reasonable" range (so, not 2 megaohms and not 0.1 picofarad, or something else silly), 2) put capacitor in and use trimpot for resistor (because a variable resistor is easy, and a variable capacitor is much less easy), 3) alter capacitor value and re-do step 2 if necessary. It's where an oscilloscope is a lifesaver, because I can just have the circuit live in the oscilloscope and turn the trimpot knob and quickly get it right just by looking at the oscilloscope screen.
@@simplyput2796
did it a bit differently.... ,but you gave me a great idea ! to use my oscilloscope !!! i was lost in searching a formula to do it "properly" and completely forgot about it....
I know that I am a little late to the party but I would like to add some remark about your explanation of the deviation between the currents displayed on the power supply and the current meter as mentioned at 14:44. You forgot that you need the 3.6 mA (see 13:15) to drive the base of the second transistor in order to achieve an emitter current of 170 mA. This current is now drawn from the power supply. Hence the power supply shows 176.4 mA + 3.6 mA = 180 mA. So in this case this is not the reason for the "inaccuracy" of the power supply, which of course exists.
Haven't seen you in a while, hope all is well.
Yep, I'm just really bad at time management which makes my personal productive life incredibly sporadic. It's why I'm careful to not make promises, so I never disappoint anyone. :P
I trusted the beard.
You have a trustworthy beard but I'm not tuning out before the breadboards come!
I like how this video is explained nicy
There's no such thing as a "Sziklai Darlington".
Oh ok