In case anyone is struggling with the last step of the proof of Young's Inequality, here is a hint: You got to use the definition of the conjugate exponent. We know 1/p + 1/q = 1. Therefore, p + q = pq (equation 1) and q/p = q - 1 (equation 2). I used these equations to complete the final step of Young's Inequality.
In case anyone is struggling with the last step of the proof of Young's Inequality, here is a hint: You got to use the definition of the conjugate exponent. We know 1/p + 1/q = 1. Therefore, p + q = pq (equation 1) and q/p = q - 1 (equation 2). I used these equations to complete the final step of Young's Inequality.
At 27:00, Derivative of function f'(t) is not defined for t=0.
I think f(t) is only defined for positive real numbers.
Offline class wale bhi yahi se pade😂😂
@@bdbrightdiamond lol😂
Need one clarification here, are p,q always conjugate exponents , like p+q = pq always true? We assumed 1
Excellent lectures sir❤
at 27:59 . if t
+vaibhav kumar : f'(t) is < 0 implies that f(t) is decreasing in(-inf,t) and increasing in(t,inf)
the graph is for f(t) not f'(t)
30:26 how is that [ a / b^(q/p) ] * b^q = ab
Note that 1/p + 1/q = 1. The exponent of b is q - q/p = q(1 - 1/p) = q (1/q) = 1.
gd evng sir,i want imp questions in real analysis for msc fst yr nd notes pdf can u plzzz sir
where ca i find books for more examples? help me please
said rajabu Principles of Real Analysis by Charalambos D. Aliprantis,...
Sir,you are just teaching the concept not giving any examples to clearity of concept.That's why ,we are not able to understand atleast 80 percent.
Examples are there in next lecture