Wooow. I hav been going through other explanations and has been very diffficult to understand. You made everyone travel with you through out the presentation with very simplified explanations. I undestand Series Resonance. Off course i will ask my friends to check you on TH-cam.
Very true - in fact the formula for resonant frequency is derived from the relationship XL=XC that you propose here, since: XL = XC 2*pi*f*L = 1/(2*pi*f*C) f^2 = 1 / (4*pi^2*C*L) f = 1 / (2*pi*SQRT(LC))
Isn't it interesting that the formula for resonant frequency is the same, regardless of whether it is a parallel or a series circuit. I scratched my head about that, until I realized that you are simply trying to balance the reactance, so you get 1/(2pifC)=2pifL. Isolate and simplify and you get the formula. This applies whether parallel or series, provided parallel resistance isn't very high.
we are using your lessons in South Africa. Siyabonga (thank you)
real
Wooow. I hav been going through other explanations and has been very diffficult to understand. You made everyone travel with you through out the presentation with very simplified explanations. I undestand Series Resonance. Off course i will ask my friends to check you on TH-cam.
The world's best teacher thanks sir
Studying for my Amateur Radio Extra Class exam - thanks for the instruction. Excellent content.
I can be pretty critical of some of these, but this one, is outstanding, makes it nice and simple. Excellent work
you are way better than my professor when explaining these topics
Very nice explanation
You can also use XL=XC
XL=2π(50)(56x10^-3)
XL=17.593
17.593=XC
17.593=1/((2π)(50)C)
C=1/((17.593)(2π)(50))
C=180.930microF
Very true - in fact the formula for resonant frequency is derived from the relationship XL=XC that you propose here, since:
XL = XC
2*pi*f*L = 1/(2*pi*f*C)
f^2 = 1 / (4*pi^2*C*L)
f = 1 / (2*pi*SQRT(LC))
Fantastic video. Very clear and intuitive instruction. Thank you. (I am studying for an advanced amateur radio license exam).
Isn't it interesting that the formula for resonant frequency is the same, regardless of whether it is a parallel or a series circuit. I scratched my head about that, until I realized that you are simply trying to balance the reactance, so you get 1/(2pifC)=2pifL. Isolate and simplify and you get the formula. This applies whether parallel or series, provided parallel resistance isn't very high.
Great video!! Very helpful, I was very confused before finding your videos.
I hope that this channel's views, in future, are most conveniently plotted on a logarithmic scale.
Thanks for the topical comment Niall! Have you seen our tutorials on log graphs?!
Good video
Very clear explanation. Thank you!
Great explanation ! subbed!
This was a great video thanks
You deserve more subs 👍🏻👍🏻
damn... this video is amazing! thanks man :)
Thank you sir for this, it is help me a lot.
What formulas would you use to calculate the current when the frequency value changes?
Hi Jake - this video discusses the method for series RLC circuits at a given frequency: th-cam.com/video/gq8cU1IbLeU/w-d-xo.html
Increase your volume, rest is excellent 🔥
Thanks - we have hopefully fixed the volume issue in our later videos.
Thanks
Thanks!