I don’t need this video yet and this comment is just to let you know that I really respect you for all the videos you have been posting lately. You really are an amazing person and sharing your knowledge with others just to help them out is truly fantastic. You are the smartest person and I just wanted to let you know that you are doing an amazing job. We are all thankful that we have you here. You literally helped me get 90% in my exam last year. Forget all the other maths Chanel’s, the organic maths tutor is at number one in my mind and a lot of others I’m sure. Once again thank you for being the beautiful and smart person you are.
I really have appreciated your videos throughout the years and I was fully prepared to pay for your patreon just to have full access to the few videos that I need. However I cannot afford the $10 a month currently. I hope maybe one day you add different tiers so I can afford it a little more. Thanks for all you do.
4:26 The reaction to make the kinetic product IS reversible. When bromide leaves the 1,2 product it makes the same intermediate as when the bromide leaves the 1,4 product.
9:47 The resonance with the secondary cation does NOT form faster. Both resonance structures refer to the same intermediate - there is only one intermediate, the allyl cation. The secondary resonance structure has a larger contribution to the ground state. It is NOT of lower energy, it is not more stable. "Lower energy" and "more stable" refer to two different structures where you can measure or estimate the energy of each structure. Again, there is only one intermediate - the allyl cation.
@@hazeld8016 less stable doesn't mean that they would be more reactive. Go through the reaction mechanism and you would see that in the first step alkene will give it's electron to Hydrogen of hbr to form a carbocation and the most stable carbocation would be formed from more substituted alkene isn't it
@@nikhilpundir1433 pleaseeee help im so confused about which resonance structure to use. the positive charge and double bond can just be chasing each other around the structure. im currently working with cyclic compounds and i really don’t understand how my teacher is picking which structure to use, im probably just dumb and missing something but i can’t find any good answers online
am I correct? so at 4:02. so because its low -40c its always going to be 1,2 addition and b/c its high 60c its always going to 1,4 addition? they are not going to change position ?
All of your videos were extra ordinary.there are inch by inch explanations for our doubts and these explanation are much helpful and support us. Really heartfelt thank you for sharing these clips for the children like us🫠
I don't undestand in the first part of the video why the kinetic products would be formed in low temperature. In my logic as an increase of temperature is an kinetic factor, the reaction would be faster and the product formed should be the one formed quicker. Right? If anyon ecould help I would appreciate it very much
never mind, I just got it. For anyone wondering: the increase of temperature often leads to an increase of the reaction rate constant which enables the thermodynamic equilibrum to be reached faster. which means that the longer one waits, the more we form the thermodynamic product. At the end this product will be in majority.
I dont understand how the kinetic product is mono substituted versus the thermodynamic product being disubstituted. I can't visual the two versus one R groups
I may be wrong, but because the thermodynamic reaction is the slower product formation, it has time to select for the more stable product (the di-substituted alkene). In the kinetic reaction, it happens so quickly that the Br- reacts with whatever reactant is closest and more immediately stable.
@@eobardrush2112 I was wondering why many of his videos (I made a playlist last semester for ochem 1) appeared as non existent. I thought I was imagining it.
Access The Full 40 Minute Video: www.patreon.com/MathScienceTutor
Direct Link to The Full Video: bit.ly/3mwEi8R
I don’t need this video yet and this comment is just to let you know that I really respect you for all the videos you have been posting lately. You really are an amazing person and sharing your knowledge with others just to help them out is truly fantastic. You are the smartest person and I just wanted to let you know that you are doing an amazing job. We are all thankful that we have you here. You literally helped me get 90% in my exam last year. Forget all the other maths Chanel’s, the organic maths tutor is at number one in my mind and a lot of others I’m sure. Once again thank you for being the beautiful and smart person you are.
Absolutely this.
If professor X says this, shiieet gotta be true
glazer
Ur amazingly intelligent! TH-cam is lucky to have your content!!!!
It’s so helpful when I don’t understand as I am reading books I would search your videos. Thanks
I really have appreciated your videos throughout the years and I was fully prepared to pay for your patreon just to have full access to the few videos that I need. However I cannot afford the $10 a month currently. I hope maybe one day you add different tiers so I can afford it a little more. Thanks for all you do.
How can you not afford ten dollars but willing to pay 10-40k a year to college when they can’t even help you learn
@@torresthemonster fafsa exists
I am from India but Hindi isn't my first language... So you are a gem for me 💝
Your amazing!!! Every video watch, you make chemistry so easy to under stand. Thank you
4:26 The reaction to make the kinetic product IS reversible. When bromide leaves the 1,2 product it makes the same intermediate as when the bromide leaves the 1,4 product.
you're saving millions of lives
9:47 The resonance with the secondary cation does NOT form faster. Both resonance structures refer to the same intermediate - there is only one intermediate, the allyl cation. The secondary resonance structure has a larger contribution to the ground state. It is NOT of lower energy, it is not more stable. "Lower energy" and "more stable" refer to two different structures where you can measure or estimate the energy of each structure. Again, there is only one intermediate - the allyl cation.
I love you. Thank you for explaining this so clearly!
Found this of Great Help
Thank you, this is extremely helpful :)
Helpful for my Exam :))
When you have a diene that isn't symmetrical how do you know which double bond is going to undergo the reaction?
One which is more substituted would react
Think this problem like this: which is more stable for example a tertiary or a secondary carbonation
@@nikhilpundir1433 wouldn’t the less substituted double bond react because less substituted double bonds are less stable?
@@hazeld8016 less stable doesn't mean that they would be more reactive. Go through the reaction mechanism and you would see that in the first step alkene will give it's electron to Hydrogen of hbr to form a carbocation and the most stable carbocation would be formed from more substituted alkene isn't it
@@nikhilpundir1433 pleaseeee help im so confused about which resonance structure to use. the positive charge and double bond can just be chasing each other around the structure. im currently working with cyclic compounds and i really don’t understand how my teacher is picking which structure to use, im probably just dumb and missing something but i can’t find any good answers online
Thankyou from India preparing for neet up bijnor
Leap
am I correct? so at 4:02. so because its low -40c its always going to be 1,2 addition and b/c its high 60c its always going to 1,4 addition? they are not going to change position ?
All of your videos were extra ordinary.there are inch by inch explanations for our doubts and these explanation are much helpful and support us. Really heartfelt thank you for sharing these clips for the children like us🫠
I don't undestand in the first part of the video why the kinetic products would be formed in low temperature. In my logic as an increase of temperature is an kinetic factor, the reaction would be faster and the product formed should be the one formed quicker. Right? If anyon ecould help I would appreciate it very much
never mind, I just got it. For anyone wondering: the increase of temperature often leads to an increase of the reaction rate constant which enables the thermodynamic equilibrum to be reached faster. which means that the longer one waits, the more we form the thermodynamic product. At the end this product will be in majority.
Thank you brother
Thank you so much Sir
Very helpful video 👍
yo all my JEE/NEET homies mark your attendance.
🥲🙋🏻♀️
how do we know whre to put the alkene
Resonance structures
I dont understand how the kinetic product is mono substituted versus the thermodynamic product being disubstituted. I can't visual the two versus one R groups
Thank you
Helpful who found it helpful ?👇👇👇
Ooooh i was studying that part suddenly you shock me with that video!
What about isolated diene reaction ??
Why is the primary halogenalkane the more stable product thermodinamically?
More no. of alpha hydrogens that causes it to form more hyperconj structures
Smart human
Okkkkkk
Carry-on
Often to upload sirrr :)))
is it normal to study this in high school? here in india we do study it :/
But why is the second product the thermodynamic stable product?? The video did just end very abrupt
I may be wrong, but because the thermodynamic reaction is the slower product formation, it has time to select for the more stable product (the di-substituted alkene). In the kinetic reaction, it happens so quickly that the Br- reacts with whatever reactant is closest and more immediately stable.
Because it is a more substituted alkene. Hence it is more stable
Bro plz get me a heart
this video doesnt make sense at the end, primary cation simply do not exist and cannot be synthesised so the mechanism has to be different
I love
Nice profile pic , I have the poster on my wall
@@isaacmonarrez3617 thanks brother! Animals isn't just an album, it's a life-changing experience.
But your vids were helpful !
This makes me so happy I’m not in chemistry anymore.
This shit is cool tho, not like maths🤢
@@cowgang7395 I was super bad at chemistry 😭
How do you feel about him not uploading full tutorial vids now, these are all only half videos. I dont see many mentioning this
@@eobardrush2112 I was wondering why many of his videos (I made a playlist last semester for ochem 1) appeared as non existent. I thought I was imagining it.
I'm still diene
SAME
@@bayleekennedy505 i'm actually sitting over my Murry and triene to learn about diene
First comment
PRAYERS 4 ALL OF GODS CHILDREN
You're absolutely great, but can you please stop saying "produc-" and throw that last 't' in there. Drives me crazy. You're very helpful though!
It’s product, not produck
Do you know a term called "accent"?
@@ananyapal14_11 yes, and completely omitting a letter is not the same thing as an accent
@@ananyapal14_11 not an accent I think he’s got a speech impediment
Thanks that shit was pissing me off
@@erikverhelst5694
Just like " A bou o wa " ?