you are my god! I really wanna cry, I worded on the same question last night for hours! There was some logical error I didn't make it clear, so I was really don't know where I was wrong. After went through the question you provided, I finally did it this morning. I even dreamed about myself still working on the problem last night. Such a relief now. THANK YOU
that is because the value of [c-coo-] happen equals to the value of [c-cooh] . if some don't understand how it works out, when the values change, it will need some changes too
you are my god! I really wanna cry, I worded on the same question last night for hours! There was some logical error I didn't make it clear, so I was really don't know where I was wrong. After went through the question you provided, I finally did it this morning. I even dreamed about myself still working on the problem last night. Such a relief now. THANK YOU
Good breakdown. Simple and clear. Thanks for the review.
Thank you so much for the video! So helpful!
What about just using Henderson Hasselbalch equation..coz the resulting soln will be a buffer??
a buffer needs both to be weak, so the HH equation wont work (it's really inaccurate for anything that isnt weak-weak)
Why not just use HH equation after the first step to calculate pH directly?
couldn't you say the same thing with the Ch3COOH in terms of a loss of 0.20 moles instead of 0.10 within the ICF table
This reminds me, I start organic Chemistry next week
Man, AP Chem was a while ago.
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WHERE DO YOU GET THE KA VALUE???????????????? MAGIC???
its given in the question
You really did all that calculations just to tell us that pH = -log the ka which is the pKa? 😂😂😂
that is because the value of [c-coo-] happen equals to the value of [c-cooh] . if some don't understand how it works out, when the values change, it will need some changes too
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