thank you, this is really useful. Revising for my maths final and this is one area I've always struggled with, but after you explained it makes so much more sense!
I'm late but 2x^3-4x-8 = 2(x^3-2x-4) x^2-x = x(x-1) Take the 2 out 2 × integral of (x^3-2x-4)/x(x-1)(x^2+4) 2 Is is a root of x^3-2x-4, when dividing x^3-2x-4 by x-2 we have the factorization (x-2)(x^2+2x+2) So, 2 × integral of (x-2)(x^2+2x+2)/x(x-1)(x^2+4) Well, I tried to simplify to eliminate some term but I didn't see a way, so lets to partial fractions (x-2)(x^2+2x+2)/x(x-1)(x^2+4) = A/x + B/(x-1) + (Cx+D)/(x^2+4) Well, this is the way
Thank you for the video. A plus C is needed after the integration is performed. For example, when you integrate d theta, you have theta, this is incorrect. The correct solution is theta plus a Constant. Please correct these errors in the video.
I don't know how well you know how to teach other aspect of math..but when it comes to math.. i give it to you🎉🎉😊😊
Man the way you explain this stuff is insane thanks its really helpful !!!
thank you, this is really useful. Revising for my maths final and this is one area I've always struggled with, but after you explained it makes so much more sense!
18:50 that moment of realization when u accidentally erased it was too funny
just joined your new channel ......
quality and free calculus for all....
u almost forgot the "+ c!" you ARE human 😂
8:10 damn i was lost there i was like how can csc^2 become cot but i forgot this was integration not derivative
You are the best ever i saw in math world .i wish can met you one day
It's so helpfull
I'm a burnt out cal 2 student and it is wholly disturbing how you simplify this!
doing three problems like this is helpful for me having attention span issues
wow your videos are very great nice well explained thank u sir🙂
I love your videos
in problem 3 shouldnt you have multiplied the x= asinx by 2 to get what 2x is equal to? thank you'
Just wondering, where did you get your "ultimate calc 2 integrals" poster?
It’s my merch. You can check it out in the description 😃
I can’t buy your merch because it says me that my email address is not valid.😕
Keep your good work!
Pls can u help me this question?
The integration of 2x cube minus 4x minus 8 over (x square minus x)(x square plus 4) dx or
2x³-4x-8/(x²-x)(x²+4)dx
I'm late but
2x^3-4x-8 = 2(x^3-2x-4)
x^2-x = x(x-1)
Take the 2 out
2 × integral of (x^3-2x-4)/x(x-1)(x^2+4)
2 Is is a root of x^3-2x-4, when dividing x^3-2x-4 by x-2 we have the factorization
(x-2)(x^2+2x+2)
So, 2 × integral of (x-2)(x^2+2x+2)/x(x-1)(x^2+4)
Well, I tried to simplify to eliminate some term but I didn't see a way, so lets to partial fractions
(x-2)(x^2+2x+2)/x(x-1)(x^2+4) = A/x + B/(x-1) + (Cx+D)/(x^2+4)
Well, this is the way
That intro is so funny
Quick question. If I was in your class and used x = acos(theta) and no errors would you be mad or give full points
Full points.
These are good, thanks.
Thank you for the video. A plus C is needed after the integration is performed. For example, when you integrate d theta, you have theta, this is incorrect. The correct solution is theta plus a Constant. Please correct these errors in the video.
Thank you sir
my calc 2 professor took the whole hour and 40 minutes to explain this lmao
Wow, super nice
0:00 i⁴
Good
🤩🤩🤩😍😍😍
Did anyone else notice the ambulance at around 17 minutes?
How do you upload videos on your so many channels regularly? I know you are a math wizard because you use teleportation spell at start of your videos.
Can u solve this if solve you are real mathmatician integration 0 to ∞ [ u^(s-1) ]/[ e^(u) + y ] ^(2) du 🥺
If u solve my problem then I coolbe with u I am also mathmatician I have a theroy to solve Riemann hypothesis 😑
Nice job
Good one
Can u solve this if solve you are real mathmatician integration 0 to ∞ [ u^(s-1) ]/[ e^(u) + y ] ^(2) du 🥺
fhuuuuaaaaaghk
Respected sir what's your religion pls reply me. I am mostly watching your video which is very helpful for us may Allah long live you.❤❤❤