thank u very much for these brilliant videos sir. You really do not know how helpful you are to me right now. I don't know what I would've done without them. And I'm planning to watch every single one of them. Thanks Michel
Sir How can i go about this question . A car travels due east with a speed of 50.0 km/h. Raindrops are falling at a constant speed vertically with respect to the Earth. The traces of the rain on the side windows of the car make an angle of 60.0° with the vertical. Find the velocity of the rain with respect to (a) the car and (b) the Earth
If we set x of the plane and x of the wind equal to each other, why would the displacement be to the right of the path? Shouldn't it not veer from the path at all?
It depends on what x represents. (x = distance?) Note that the wind and the plane travel at different speeds so they cover distances at a different rate.
Isnt the Vwx 10m/s as 20cos(60)=10m/s as its a component of Vw?, and would make it the opposite for sin(phi) thus sin (phi) would be 10/120 no? btw thanks for all the vids, subbed
The 20deg angle is wrong, it calculates to 25.22. A simple way to solve the problem is using law of sines to calculate φ =4.78 and using law of cosines to calculate Vrel. First you need to calculate angle between Vrel and wind trigonometrically.
There seems to be an error in the calculation. Why would you calculate the Vy relative with out calculating the Vx relative. You need to calculate the Vrelative for the entire equation using the Pythagorean theorem. This would get you the total Vrelative. In which you can then plug in to get time. The Vx is missing and can mess up the equation based on the previous videos I have watched
these horizontal and vertical components are respect to what........the aeroplane,The point LA or the ground.I f it is with respect to ground how do you resolve it when you don't have any reference point.Can you pls tell me this
Sir, I want to ask if the construction of my problem is right. this is just related to your example above. A pilot wants to fly from South Korea to North Korea, with the distance of 120 km, with a plane that flies at 30 m/s but the wind is blowing at 25 m/s in angle of 55 degrees South of East. Find the velocity of the plane relative to the y axis and the time it takes the plane to arrive at North Korea. it will greatly help me sir. asap
Marielle, You need to draw vectors. (one with the net velocity in the desired dircection) The length equals the magnitude. The directions are given in the problem. Then you add the vectors and you will have the net velocity of the plane, relative to the ground.
I'm confused about the angle of the wind formed. It says 60degrees south of east means the angle below x-axis, but why 60 degrees east of north is the angle between y-axis and hypotenuse? and do we have 60degrees north of east? then it would be the angle formed by x-axis and hypotenuse.
Khai, It is a matter of language and convention. The compass directions are given in such a way that you start at an initial direction and then you move the number of degrees given in the direction of the given compass direction. 20 degrees east of north. Start at north. Then move 20 degrees in the direction of east.
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thank u very much for these brilliant videos sir. You really do not know how helpful you are to me right now. I don't know what I would've done without them. And I'm planning to watch every single one of them. Thanks Michel
one thing I definitely know that this video cleared my whole doubt on this kind of problem . thank u
Brilliant. I love these videos. Its awesome that they are so short and concise
Thank you! Your videos are so clear and concise, they're extremely helpful for studying for my physics test
You're the man Mike
Starting to understand relative motion thanks to you!!
Great! Glad you found our videos. 🙂
Thank you for taking the time to make this video and explaining the problem so well! :)
Sir How can i go about this question
. A car travels due east with a speed of 50.0 km/h. Raindrops are falling at a constant speed vertically with respect to the Earth. The traces of the rain on the side windows of the car make an angle of 60.0° with the vertical. Find the velocity of the rain with respect to
(a) the car and
(b) the Earth
Tan (60) = OPP/ADJ = Vcar / Vrain
If we set x of the plane and x of the wind equal to each other, why would the displacement be to the right of the path? Shouldn't it not veer from the path at all?
It depends on what x represents. (x = distance?) Note that the wind and the plane travel at different speeds so they cover distances at a different rate.
Isnt the Vwx 10m/s as 20cos(60)=10m/s as its a component of Vw?, and would make it the opposite for sin(phi) thus sin (phi) would be 10/120 no? btw thanks for all the vids, subbed
That is the way it is shown in the video.
@@MichelvanBiezen all good sorry my mistake, It's clear now
instead of sin60,shouldn't we need a cos60 when you substituted
Vwx is adjacent to the angle, so we need the cos
Sir,
If we use vectors it will be Vpx = -Vwx, i just want to know if you used the magnitudes or vectors?
Because in vectors Vpx + Vwx = Vrelativex = 0
You are a life saver 🥺👏🙂
Glad the videos are helping.
The 20deg angle is wrong, it calculates to 25.22. A simple way to solve the problem is using law of sines to calculate φ =4.78 and using law of cosines to calculate Vrel. First you need to calculate angle between Vrel and wind trigonometrically.
Its a best explanation sir it was amazing😊😊😊
Thank the Lord for you Sir.
There seems to be an error in the calculation. Why would you calculate the Vy relative with out calculating the Vx relative. You need to calculate the Vrelative for the entire equation using the Pythagorean theorem. This would get you the total Vrelative. In which you can then plug in to get time. The Vx is missing and can mess up the equation based on the previous videos I have watched
can we use sine rule???
There are often multiple ways in which you can solve a problem. Try it and see if you get the same answer.
these horizontal and vertical components are respect to what........the aeroplane,The point LA or the ground.I f it is with respect to ground how do you resolve it when you don't have any reference point.Can you pls tell me this
The angles are referenced to the compass directions, which means they are referenced to the ground and the directions N, S, E, W
Michel van Biezen thanks helps a lot also great vid
Sir, I want to ask if the construction of my problem is right. this is just related to your example above.
A pilot wants to fly from South Korea to North Korea, with the distance of 120 km, with a plane that flies at 30 m/s but the wind is blowing at 25 m/s in angle of 55 degrees South of East. Find the velocity of the plane relative to the y axis and the time it takes the plane to arrive at North Korea.
it will greatly help me sir. asap
Marielle,
You need to draw vectors. (one with the net velocity in the desired dircection)
The length equals the magnitude.
The directions are given in the problem.
Then you add the vectors and you will have the net velocity of the plane, relative to the ground.
ok thanks sir
This man looks like physics
🙂
thank u sir
i like his accent
This video is a little confusing.
thank
thank you!!!!!!!
You're welcome!
I'm confused about the angle of the wind formed. It says 60degrees south of east means the angle below x-axis, but why 60 degrees east of north is the angle between y-axis and hypotenuse? and do we have 60degrees north of east? then it would be the angle formed by x-axis and hypotenuse.
Khai,
It is a matter of language and convention.
The compass directions are given in such a way that you start at an initial direction and then you move the number of degrees given in the direction of the given compass direction.
20 degrees east of north. Start at north. Then move 20 degrees in the direction of east.
wait ..where is the 200 km coming from
That would be a "given" in the problem.
That doesnt make any sense, why would someone want to fly from LA to Bakersfield?
If the Grapevine is closed, it makes a lot of sense.
Michel van Bill Nye
Sehr gut video :)
Thank you.
Thankyou sir