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  • เผยแพร่เมื่อ 26 ก.ย. 2024
  • Dave grabs a few junkbox parts and builds a useful constant current load for switch mode power supply, battery testing, and other applications.

ความคิดเห็น • 226

  • @Networkengie
    @Networkengie 7 ปีที่แล้ว +14

    That dave CAD sure is some piece of sophisticated software you got. :)

  • @elye3701
    @elye3701 9 ปีที่แล้ว +8

    I am blown away. A really great exposition. Simple, practical and I like the verification bits. I learnt more about thermal resistance of heatsinks here than all the books and articles and datasheets I have been reading.

  • @testep02
    @testep02 9 ปีที่แล้ว +27

    You know, I really wish I had found Dave's videos last. After watching these vids, it makes it really really hard to watch the videos from other people, even though they contain good information as well. His teaching style is just so in tune with how I learn and his explanations are in depth, but don't treat the listener like an idiot. This series is just brilliant.

    • @mmiller867
      @mmiller867 8 ปีที่แล้ว

      +Joseph Nicholas You're equating age with knowledge of electronics? Odd. So an 82 year old retired CEO of a Fortune 500 company with no experience in electronics is a better candidate for this channel, and a 26 year old with a master's in EE is better for Lorton? Hmmm - how's your logic circuit doing? Swinging toward the arrogant side a bit maybe?

    • @RWoody1995
      @RWoody1995 8 ปีที่แล้ว +2

      +M Miller I think you are reading wayyyy too much into what Joseph said come on lol

    • @testep02
      @testep02 8 ปีที่แล้ว +4

      M Miller Let's be honest. Electronics and computers in general are not the most exciting topics. I thoroughly enjoy Dave's ability to turn a mundane subject into something pleasant to watch. His personality is what brings me back again and again to his videos.

  • @clifffiftytwo
    @clifffiftytwo 6 ปีที่แล้ว +3

    Had a vision of factories full of engineers waiting impatiently for Dave's latest video to come out, designing away as he talks, then quick into production, the first on eBay wins!!!

  • @ForViewingOnly
    @ForViewingOnly 14 ปีที่แล้ว +1

    Excellent video. So good to see electronics theory applied in a practical way. I studied electronics 20 years ago at college as part of my apprenticeship at a telecoms company, and although I came away with useful qualifications I didn't really learn much that I could apply: the course was 95% theory and 5% practical!

  • @exallievididonbosconcrgrou7544
    @exallievididonbosconcrgrou7544 6 ปีที่แล้ว +2

    Dave, you're GOOD! Keep the video's coming. This video is already 7 years old when I saw it this Dec 2917. So you are now 7 years a little bit older since you made this video. But keep up the good work.I LEARNED A LOT FROM IT AND SO DO OTHERS. ATTABOY! Thanks.

    • @hypercoffeedude
      @hypercoffeedude 6 ปีที่แล้ว +1

      2917!? You're from the future!? What's it like there? lol

  • @douggale5962
    @douggale5962 8 ปีที่แล้ว +2

    Excellent video. I love these little design projects.

  • @arminag3827
    @arminag3827 2 หลายเดือนก่อน

    You are better than most of university professors

  • @proyectosledar
    @proyectosledar 11 ปีที่แล้ว +6

    excellent dave, I love your videos

  • @jeremiahgeo
    @jeremiahgeo 7 ปีที่แล้ว

    Excellent tutorial Dave , Hats off to you .Like your Dave CAD .tells almost everything on this CKT

  • @exgenica
    @exgenica 4 ปีที่แล้ว +1

    Very well explained and executed.
    ...If you'd only gone one step more and shown how to relate the allowable maximum temperature of the MOSFET to the power dissipation of the heatsink to verify that the heatsink would adequately protect the MOSFET for the maximum current you were allowing the device to draw.

  • @mjlorton
    @mjlorton 12 ปีที่แล้ว +1

    Excellent...might have to put one of these together.

  • @Schwuuuuup
    @Schwuuuuup 11 ปีที่แล้ว +1

    Absolute fantastic... every question I had was answered :-)
    I really like your stuff
    Greetings from Germany
    TOM

  • @enriquecourtade
    @enriquecourtade 4 ปีที่แล้ว +2

    5:19 absolutely important thing no explained at all. This is a video for truly advanced people. I suggest to search Rail to Rail Op amp to understand what wasn't said here.

  • @ChrisRid
    @ChrisRid 7 ปีที่แล้ว

    Awesome little circuit! I had thought about trying to make a constant-current load before but wasn't sure which route to take. New project I think!

  • @RexxSchneider
    @RexxSchneider 3 ปีที่แล้ว +1

    The other part of the heat dissipation calculation is that the MTP3055 has a thermal resistance between junction and case of 3.13 degrees C per Watt. That means with your 11 W example, that the mosfet junction will be another 3 x 11 = 33 degrees above the case/heatsink - a little over 100 degC with a 20 degC ambient. That's within the maximum operating temperature of 175 degC for the device, but a little toastier than I like.
    The corollary is that your heatsink/mosfet combination has an absolute maximum power dissipation of around (175-25)/(4.5+3) = 150/7.5 = 20 W with a 25 degC ambient. You might want a better cooling solution if you start looking at higher voltages and currents - 12 V and 2 A would well exceed the capabilities of that heatsink. And to get past 50 W, you'll need a mosfet in a different package.

  • @joshstube
    @joshstube 13 ปีที่แล้ว +2

    Great Idea Dave!
    I want to build one!
    A request:
    Please add 17:17 to the next "how to entertain a geek Highlights!
    Especially the part about doing it with "intelligent control"
    ;)

  • @prakashveereswar5747
    @prakashveereswar5747 7 ปีที่แล้ว +1

    Thanks for the video Dave..very useful...Please give some tips on building higher currents sources like 7 Amps constant current source.
    Thanks Regards.

  • @bob4analog
    @bob4analog 7 ปีที่แล้ว

    Nice explain on the load. One bloke made one of these, but his oscillates.. and he thinks it's supposed to do that! Aaah! I knew that's not right.. your circuit verified that. His has no bypass caps.. thus oscillation. Also, excellent hack on the meter! I had done the same hack to my LED panel meter. Cheerz

  • @tabbletbuijs8366
    @tabbletbuijs8366 3 ปีที่แล้ว

    Thanx for sharing you knowledge, you're amazing!

  • @EEVblog
    @EEVblog  14 ปีที่แล้ว

    @cborrero2000 The opamp output gives whatever Gate voltage is required to keep the constant voltage across the load resistor. It's a standard building block circuit.

  • @DanielsGameVault
    @DanielsGameVault 8 ปีที่แล้ว

    Can this also work as an adjustable current circuit for a power supply ? Say you drop that MOSFET before the Constant Voltage (CV) side of the power supply, what would happen ?

  • @l3p3
    @l3p3 7 ปีที่แล้ว

    I like those analog teaching videos you made back then.

  • @ernestuz
    @ernestuz 11 ปีที่แล้ว

    Dale, doing it in that way creates a constant resistance load, so the current will change when the power supply voltage under test changes. Wicth Dave's circuit the current sucked from the power supply is constant.

  • @Laogeodritt
    @Laogeodritt 11 ปีที่แล้ว +1

    Notice that the op-amp feedback controls the DC current depending on the PWM input (because the voltage across the 1R is proportional to the current), NOT resistance. For power, P=V*I, which is the same as CC iff the supply voltage is constant (not necessarily true! Think batteries as they discharge). Constant-resistance would be to vary current according to supply voltage according to Ohm's law, i.e. you have to actively maintain the constant resistance since the OPA/NMOS system is CC.

  • @Gzalo
    @Gzalo 14 ปีที่แล้ว

    Interesting. Keep up the good work Dave!

  • @Debraj1978
    @Debraj1978 11 ปีที่แล้ว

    Opamp is required to maintain the constant current. With a pot + manual intervention, you could vary the current, but the current will vary the moment supply voltage varies. Using opamp in closed loop will make sure that the current is same irrespective of any input voltage.

  • @arminag3827
    @arminag3827 2 หลายเดือนก่อน

    Btw if you change the shunt resistor value to 0.5 ohms, you will have a wider current range up to 2.6 amps.

  • @JuanjoAparicio
    @JuanjoAparicio 9 ปีที่แล้ว +54

    "from a couple of junk box parts". Like CX101 meters. My junk doesn't resemble that at all :-(

    • @SomerledDesign
      @SomerledDesign 9 ปีที่แล้ว

      +Juanjo Aparicio Perhaps a 0-1 volt analog panel meter is in your junkbox? It doesn't have to be Digital.

    • @JulieanGalak
      @JulieanGalak 6 ปีที่แล้ว +1

      Finding a voltmeter in the right range that works in a grounded configuration has proven very tough. The cx101 appears to unobtanium these days.
      And I want a digital meter, don't care for analog for this application.

    • @exgenica
      @exgenica 4 ปีที่แล้ว +1

      One doesn't have to keep the voltmeter connected all the time, so set the test unit using a regular DMM and then do the testing. It may be more convenient to have the meter built-in...but it isn't required.
      Or...one could set up fixed resistance value points using carbon or precision resistors as desired with a rotary switch to then set the current to some common values one might want (e.g. 100mA, 250mA, 500mA, 1000mA etc). I find in most cases I don't need an infinitely variable current load to test things.

  • @EEVblog
    @EEVblog  14 ปีที่แล้ว +1

    @Nermash Yeah, the Gossen is a damn fine meter!

  • @robertanderson8613
    @robertanderson8613 5 ปีที่แล้ว +1

    Awesome as always I would like to see a circuit for constant current and voltage both adjustable to hook to a server power supply or two supplies for 24v up too say 100a DC thanks keep them coming

    • @lukahierl9857
      @lukahierl9857 5 ปีที่แล้ว

      24v at 100a is 2.4kw thats a lot of poer to be dissapaiting in semiconductors and a heatsink. I woud use some enameld copper wire in a tub of water, not so convinient but a lot cheaper

  • @Nermash
    @Nermash 14 ปีที่แล้ว

    Admit it, you just love that Gossen Metrawat and german craftmanship:)

  • @EEVblog
    @EEVblog  12 ปีที่แล้ว

    @thenaimis Correct, that's what the original board does. Micro with constant current/resistance/power and logging capability.

  • @Darkfuturee
    @Darkfuturee 2 ปีที่แล้ว

    HEY DEAVE, WHAT A BOUT A NEW VIDEO LIKE THIS, WHAT'S NEW IN POWER SUPLY TESTING!

  • @johanvandebelt
    @johanvandebelt 6 ปีที่แล้ว +1

    I have a remark about the diagram at 16:40. In constant resistance mode, to justify Ohms law, you'll need to know the input voltage and adjust the current accordingly. Since the microprocessor sets the FET current with PWM, it also needs to monitor this input voltage. The inputvoltage (=Voltage across FET and current shunt resistor) can be monitored using a resistive divider over the input connectors. The divided voltage is then connected to a second channel of the microprocessor ADC (or use an analog multiplexer). For constant power, same story.

    • @kevinwalters5160
      @kevinwalters5160 ปีที่แล้ว

      Agreed, the battery voltage is useful for data logging and as you note required if you want to do constant resistance (or constant power) actively controlled discharging.

  • @EEVblog
    @EEVblog  14 ปีที่แล้ว +2

    @Films4You Sanyo Xacti HD1010,

  • @mnovo
    @mnovo 9 ปีที่แล้ว

    @SuperRnine PSU positive voltage is connected to the MOSFET gate and the negative voltage to the ground.

  • @azbukaChisel
    @azbukaChisel 4 ปีที่แล้ว

    thank you so much. you are the best!

  • @tronixstuff
    @tronixstuff 14 ปีที่แล้ว

    Your junk box must be a lot larger than mine!
    Thanks for the very interesting vlog. :)

  • @CraigTalon
    @CraigTalon 7 ปีที่แล้ว

    Great video as always. Several years old now but... hoping someone can point me to the video he mentions at the end about doing the power supply curves using the load.

  • @AintBigAintClever
    @AintBigAintClever 12 ปีที่แล้ว

    Useful, I think I'll build one of these.
    I'm surprised not to find anything like this on eBay.

  • @RobertGallop
    @RobertGallop 14 ปีที่แล้ว

    Love it Dave, good post, more like this!!!

  • @Sam-hj5ok
    @Sam-hj5ok 3 ปีที่แล้ว

    The intro is so 2009 😅
    Nice on tho, exactly what i was looking for

  • @joe72205
    @joe72205 14 ปีที่แล้ว

    Excellent video, and with the knowledge gained I am going to build a project I have been putting off: an intelligent battery charger!
    I have some I2C DACs from Microchip which should be very suitable for setting the opamp input voltage.

  • @thenaimis
    @thenaimis 12 ปีที่แล้ว

    Pretty awesome little project. I want to make one but I think I'd like to "crank it up a notch" and have a microcontroller involved that varies the current, takes measurements and spits them out back to a computer. Press a button, capture data and graph :-). The original use of your board seems to do something along those lines where the uC controls the current, unless I misunderstood.

  • @luisalbertoparada5757
    @luisalbertoparada5757 3 ปีที่แล้ว

    excelente video.... aca un nuevo suscriptor.... saludos desde Yaritagua Venezuela

  • @VolksTrieb
    @VolksTrieb 14 ปีที่แล้ว

    @eeadata Why not? The Opamp will adjust the gatevoltage as well. You need to know the Thresholdvoltage, the amp, the max DS-Voltage and P-dead.

  • @elye3701
    @elye3701 9 ปีที่แล้ว

    I always look at the worst case scenario whenever I re-design a circuit to suit my needs and in this case I would have soldered a 1M resistor from the wiper to ground. Similar to input conditioning when I do programming. It avoid unforeseen bugs and aids troubleshooting. I also make a point of establishing and highlighting test-points within the circuit since nobody I know troubleshoots at a leisurely pace.

  • @Laogeodritt
    @Laogeodritt 11 ปีที่แล้ว

    It occurs to me that what I said earlier on transient is not strictly true. The op-amp isn't purely a proportional controller (ideally it is, in reality it has an s-dependent transfer function). You could probably add a capacitor somewhere to move a pole and increase the damping. I'd have to sit down and look at it. (Also, that's assuming you mean transient response to a control voltage change, not a change of the supply voltage-that's a different problem I've been thinking about.)

  • @ubuntututorials
    @ubuntututorials 14 ปีที่แล้ว

    I was going to build me one of these, but I was going to use a 2N3055 power transistor as the sink element.

  • @AintBigAintClever
    @AintBigAintClever 12 ปีที่แล้ว

    Something like this should be easy to scale up by increasing the number of MOSFETs fitted and by using fan-cooled heatsinks. I use a CPU heatsink from an Xbox 360, although it's not fan-cooled, but I don't need to dissipate 150W like you do! You may have to get creative when clamping a CPU heatsink, though. Mounting back-to-back might make it easier (I have a spare, unused MOSFET under mine, so each TO220 epoxy block faces the other one's metal tab, with legs sticking out opposite ends).

  • @Matthias051
    @Matthias051 7 ปีที่แล้ว

    thank you so much again for the video

  • @DaleBarnard
    @DaleBarnard 11 ปีที่แล้ว +1

    Great video, quick question though, with the 1 ohm resistor in place can you not just connect the pot to the mosfet and change the gate voltage to increase/decrease the current? This works in my simulations so I'm struggling to understand why the Op-Amp is required. Cheers!

  • @richfiles
    @richfiles 8 ปีที่แล้ว +8

    It goes all the way up to 1337. Gnarly!

  • @diverfede
    @diverfede 7 ปีที่แล้ว

    great one

  • @billysgeo
    @billysgeo 11 ปีที่แล้ว +1

    Why did you calculate a max of 2.5A (given the 1/2 voltage divider between the opamps) and then you got only 1.3A in the actual circuit???

    • @volodymyrzakolodyazhny7740
      @volodymyrzakolodyazhny7740 6 ปีที่แล้ว

      BIll Geo I think it's because of wire resistance. (They were thin).

    • @catalinvasile9081
      @catalinvasile9081 5 ปีที่แล้ว

      It would be 2.5A with a rail-to-rail opamp. The lm324 goes up to max VCC - 1.5V so the full swing for a VCC of 5V is 0 to 3.5V, divided by 2 results in the ~1.75V. Why 1.3A instead of 1.75A? I'm sure the answer is buried in the datasheet of the opamp or the tolerance of the resistors, etc

    • @RexxSchneider
      @RexxSchneider 3 ปีที่แล้ว

      @@catalinvasile9081 You have the right idea. The LM324 isn't going to swing above about 3.5V with a 5V supply. Since the gate threshold voltage for an MTP3055 is specified as somewhere between 2V and 4V, it's pot luck whether the circuit can actually turn on the mosfet.
      In the worst case scenario needed to sink 2.5A, there will be 2.5V across the current sense resistor, so the source will be at 2.5V and the gate could need as much as 4V above that just to turn on. Then as the mosfet has a minimum forward transconductance of 4A/V, it may require an additional gate voltage of 2.5/4 = 625 mV to supply 2.5 A.
      That means you have to design for a voltage of at least 2.5 + 4.0 + 0.625 = 7.125 V at the gate. Finally, the LM324 needs another 1.5V "headroom" which shows that you need a 9V power supply for the opamp to accommodate the worst case with that mosfet if you want to sink 2.5A.
      If the actual circuit limits to 1.3A, that would mean that the LM324 output and the mosfet gate are at about 3.5V and the mosfet source is at about 1.3V, leaving 2.2V as gate-source voltage, which is a bit better than what you might expect as it has a typical gate threshold voltage of 2.7 V according to the data sheet.

  • @mesolsot
    @mesolsot 11 ปีที่แล้ว

    I dunno if this will help but when i use pc power supply as a voltage source i noticed you dont get much out of it unless you have a load on the 5v side(maybe 12v side, it's been a while) so just hit up radio shack and grab a 5w load resistor, strap it to some old cpu heatsink w/fan and load that puppy up. =D hope that helps you get your supply into the optimal range your lookin for.

  • @PocketBrain
    @PocketBrain 7 ปีที่แล้ว

    Looks like R35 needs a touch more solder on the top side.
    Don't you just love the versatility of Op Amps?

  • @enilenis
    @enilenis 10 ปีที่แล้ว

    Will this circuit work as a chopper for a stepper motor driver that pulls too much current through its h-bridge or do I have to go with something more complex? Adding a heatsink to the h-bridge is not an option.

  • @johnromberg
    @johnromberg 9 ปีที่แล้ว

    If I understand this correctly most of the power is dissipated by the mosfet? Is there a design where the power would be dissipated by resistors? I'm thinking a big ass cap, a pwm controlled mosfet and big ass power resistors. I feel something like that would be easier to make programmable with a uC and scaled up in terms of maximum load.

  • @AK-ov2kx
    @AK-ov2kx 3 ปีที่แล้ว

    Great video. Can you suggest equivalent of cx101?

  • @alexeyveseliev106
    @alexeyveseliev106 7 ปีที่แล้ว +1

    It is interesting. what will happen if connect two constant current load in series. Will they go crazy?

    • @volodymyrzakolodyazhny7740
      @volodymyrzakolodyazhny7740 6 ปีที่แล้ว

      Аляксей Вясельеў One of them will win, and control the situation.

  • @Michael-w8v
    @Michael-w8v 9 ปีที่แล้ว

    I have been wonder if it is possible to using 1000 watt MOSFET with MIC1337 timer (the perfect 50% cylce) while testing power supply at 12V 60A?

  • @renekohli7675
    @renekohli7675 3 ปีที่แล้ว

    Hi Dave,
    Thanks a lot for this video.
    Do you think that we also could develop an AC version of an electronic load. I know this would be a complete new design. Please let me know your opinion. Best regards from Switzerland, Rene

  • @ErikOdinsvej
    @ErikOdinsvej 2 ปีที่แล้ว

    Regarding testing 18650 cell : Who is right ? - the people that set the cutoff at 2.5V. or 3.0V. - I see on youtube that some test 18650 battery with different cutoff - then the result will also be different !

    • @K2teknik.
      @K2teknik. ปีที่แล้ว

      Look at the datasheet for the cells you want to test, the answer about cut-off voltage is there.
      And, yes, different manufacturers can have different cut-off voltages, and there can also be a difference from one series of cells to another within the same manufacturer. Some cells may even have different cut-off voltages depending on usage, , it shouldn't be easy.

  • @gabiruman
    @gabiruman 7 ปีที่แล้ว

    I need to test an IPSU with 9 different power rails ranging from 1.25V to 5V and current less than 1A would this design be recommend for my case? Thanks.

  • @davorst699
    @davorst699 9 ปีที่แล้ว

    Hello, since i have stumbled upon your blog i found very useful stuff here and learned something. I'm trying to build a small test rig for testing vacuum tubes and transistors under working conditions. So far i have used resistors are constant current load but as usual resistor stack is never big enough and you need to use some high power ones. So i thought why not to use variable current source instead of resistor so i'm wondering with some modifications could this circuit work in a way i imagined it should.
    Ofc limiting current for supply voltage is only one part of that test rig, other is how to drive gate/grid/base but that's another story and not connected to this video.

  • @dubnitsky
    @dubnitsky 9 ปีที่แล้ว

    i'm gonna quit killing LEDs in series in case of faults and shorts with that)), beauty!!!

  • @mattaikay925
    @mattaikay925 2 ปีที่แล้ว

    Hello - can you suggest how I may use this to test multiple outlets on an industrial PDU.

  • @BHR477
    @BHR477 14 ปีที่แล้ว

    thanx ,, good job ,,

  • @Laogeodritt
    @Laogeodritt 11 ปีที่แล้ว

    Steady-state error is probably due to a low op-amp open-loop gain (or your current sense resistor isn't precise enough). For transient, do you know any control theory? This is a pretty simple proportional controller with very high gain, so depending on the opamp/NMOS transient can be horrid; you could try a PD controller or a PI controller with a smaller proportional gain (the integral eliminates steady-state error, smaller gain improves transient). It requires several circuit changes, though.

  • @mendebil
    @mendebil 6 ปีที่แล้ว

    Luckily in 2018 you can get a 250W boost converter for $4 and limit 100W leds without heatsink

  • @ElvisAviator
    @ElvisAviator 12 ปีที่แล้ว

    @ElvisAviator I've found out on how to get the LCD cx101b to work reading millivolts even though it's one millivolt offset, I think is due to the lcd +-1%.

  • @diulaylomochohai
    @diulaylomochohai 13 ปีที่แล้ว

    dave,
    did you get a new 87V in this video? it looks newer than the one you had before...
    did your previous 87V broke if it is indeed different?
    thanks

  • @xmed0
    @xmed0 10 ปีที่แล้ว

    brilliant !

  • @parammukku
    @parammukku 7 ปีที่แล้ว

    Hi , I would like to test the discharge procedure of a 24vdc (7 days autonomy )Nicad battery bank . Please advice, which is the best device to use for that application? and how can i buy the same?

  • @ocayaro
    @ocayaro 4 ปีที่แล้ว

    You are drawing that mosfet wrong. Is it an enhancement mode or a depletion mode device?

  • @ergindemir7366
    @ergindemir7366 3 ปีที่แล้ว

    9:30 if you put 10 resistors in parallel your tolerance goes down to 0.3%.

  • @leeYT321987
    @leeYT321987 13 ปีที่แล้ว

    Thanks a lot Dave.
    What is the use of the extra op-amp?
    Why does the MOSFET need to be logic-level?

  • @brikotube
    @brikotube 14 ปีที่แล้ว

    Hello Dave. Excuse my ignorance but, why you used a mosfet for the sink element instead of a BJT?. Thanks

  • @Beirdo1
    @Beirdo1 7 ปีที่แล้ว

    Question for ya Dave... The MTP3055 you use here... is the tab of the TO-220 electrically connected to any of the pins, or is it floating? I'm hoping to be able to solder it down to a copper shim as part of my heat sinking, but I kinda need to know if that's possible or if I need an insulator which would change the strategy. The datasheet doesn't say, so I figure you might know.

    • @kylec410
      @kylec410 5 ปีที่แล้ว

      drain connected

  • @dariusssss85
    @dariusssss85 7 ปีที่แล้ว

    is it going to work if i power the op-amp from a different supply. did the gate of the mosfit will work. I was thinking to combine the two grounds? Help pls

  • @guayabitopeludo
    @guayabitopeludo 11 ปีที่แล้ว

    I HAVE A QUESTION... How can I know what kohm potentiometer value should I choose to fully take advantage of the 10 turns???? I have seen videos where people buy the expensive 10 turn pot and only with a few turn they reach the max voltage.

  • @bradleyberthold4606
    @bradleyberthold4606 7 ปีที่แล้ว

    Dave I'm having trouble with "drift" with the OpAmp voltage follower. I used a 1ohm, 10% power resistor, an LM324, and a IRF540 Power Mosfet.
    I am using a 9V power supply for the LM324 (measuring it, it actually shows about 10V)
    I notice that if I use this to test battery discharging I get "drift". I'll start out at say, a setting for 500ma, and as the battery voltage drops, the current *increases* , and i'm not sure why. I thought perhaps its something to do with the MOSFET changing its conductance or something? I always end up having to adjust the input pot setting over time to lower the current back to 500ma
    It doesn't make sense to me becasue the OpAmp should technically keep the voltage /current constant even if the resistor drifts, wouldn't it? It almost seems like my OpAmp is drifting.
    Also, my MOSFET doesn't get hot at all, granted I'm only running 1.5 V at 500ma , and the resistor is .5V of that (I set the OpAmp + input to .5V so I get .5A on the 1ohm resistor), so ya it's only having to handle what, 500mw, not that much I guess.

  • @foresaken5000
    @foresaken5000 4 ปีที่แล้ว

    Will something like this work for testing amperage and voltage at same time on a solar panel with a watt meter? If not could you please make a video of one that would do so for A47 volt panel or higher?

  • @SuperRnine
    @SuperRnine 11 ปีที่แล้ว

    If this would be used in lab power supply as a adjustable current source where should the load be connected ?

  • @tabarin
    @tabarin 14 ปีที่แล้ว

    Thanks for this video I thought it was really informative to see these parts working together! I've been reading about opamp and linear regulator circuits lately. I was wondering about the heatsink calculation, were you adding in the junction to case thermal resistance of of 3.13 C/W from the chip? I'm wondering how that factors in thanks

  • @tonysfun
    @tonysfun 4 ปีที่แล้ว

    Thanks for your videos! I'm trying to learn Constant Current Dummy Load, but I need little more info, so I can make one based on your design and try to make my own - that is how I learn. Anyway, is there a video that shows the exact schema and the parts list? Or did you make one that is more sophisticated with a better LCD display? Or anyone else who knows, can you just post it here or send me a reply. Thanks in an advance to you all.

  • @brantwinter
    @brantwinter 11 ปีที่แล้ว

    Hi - thanks for the video, I actually learnt a lot from this ! Can you give some pointers for research into scaling this up to, say, 60A ? Is the approach to parallel a few of these circuits or use a bigger MOSFET ? Any help would be appreciated.

  • @mahmoudgaber5347
    @mahmoudgaber5347 3 ปีที่แล้ว

    Can I get the PCB design and BOM to implement it in a holiday DIY project?, Thank you.

  • @cborrero2000
    @cborrero2000 14 ปีที่แล้ว

    @EEVblog Hi Dave and brikotube. Excuse my ignorance please but, I want to know why do we need a transistor, either Mosfet or BJT, at the output of this circuit Is it just working as a switch?; so it won't let current through when the voltage in the first OP-AMP follower has a input of 0 volts? or Is it to handle the voltage difference = Voltage of PSU minus Voltage on the 1R resistor? If, so why is not appropiate to use this second opan as a second follower and put a second resistance ontop THX

  • @johnconrad5487
    @johnconrad5487 6 ปีที่แล้ว

    why did u not measure the temp on the transistor tab?

  • @edgarricci
    @edgarricci 8 ปีที่แล้ว

    What's the meaning of Logical Level MOSFET? I don't understand that. I cannot find the MTP3055 in my city. There's a replacement or equivalent transistor?

    • @edgarricci
      @edgarricci 8 ปีที่แล้ว

      +Claudius Thanks a lot! The information s very helpful.

  • @kalhana_photography
    @kalhana_photography 12 ปีที่แล้ว

    Hi Dave, I put together one of these on a breadboard using similar components, but the transient response seems to be pretty bad. Also, there is steady state error. Any ideas why?

  • @kildas
    @kildas 13 ปีที่แล้ว +2

    DaveCAD :D Where can i download it?

  • @gundogforge8625
    @gundogforge8625 13 ปีที่แล้ว

    Hi! I need to build a dummy load for a PC power supply that can draw up to 100A and another unit that can draw up to 30A that are adjustable in steps of 10A and 5A respectively. I know my basic electronics but I would have absolutely no idea on where to start with this. I have heard MOSFETs are very scalable and can achieve this with adequate cooling, but I need a circuit diagram or something so I can make it. Please help!

  • @ElvisAviator
    @ElvisAviator 12 ปีที่แล้ว

    Hi Dave I'm trying to use the CX101b LCD but it's a pain in the ass to configure, can you tell me what resistor values you use to get it to read 1999???? I know that your schematic values are not the same as what you use.
    Thanks.

  • @celesticahome
    @celesticahome 10 ปีที่แล้ว

    paul i was wondering about the 10 turn variable resistor if taken to ov then would that not short the supply ...?

    • @geoden1645
      @geoden1645 9 ปีที่แล้ว

      No. The 50K pot is wired as a potentiometer not a variable resistor. The current through the pot will be only 100uA no matter where the wiper is.

  • @joseveliz6979
    @joseveliz6979 9 ปีที่แล้ว +9

    Nice shirt! (thumbs up)

    • @CE113378
      @CE113378 9 ปีที่แล้ว

      The fool says in his heart, "There is no God."

    • @joseveliz6979
      @joseveliz6979 9 ปีที่แล้ว +6

      Dan Hillman
      This is not the correct venue for such a discussion and I'm not versed enough to debate the subject. I'll attach the below as a response to your reply and leave it at that.
      atheism.about.com/od/knowledgeofreligiongod/a/FoolHeartGod.htm
      Do Christians Want Dialog, Or to Express Superiority?
      Calling someone a fool simply because they don't agree about the existence of a God is no way to initiate a conversation with a stranger; it is, however, a great way to communicate the fact that one isn't interested in real dialogue and only wrote in order to feel better about oneself through attacking others. This can be demonstrated most dramatically by asking if the writer agrees with the second part of the verse, which declares that "They are corrupt, they do abominable deeds, there is none that does good." Although few Christians who quote the first portion of the verse rarely go so far as to include the second sentence, no atheist should ever fail to keep in mind that it is always there, hanging unspoken but nevertheless assumed, in the background.
      If the Christian doesn't agree with the second part of the verse, then they admit that it's possible to not agree with something in the Bible. If that's the case, then they can't claim that they are required to agree with the first part - but if they do agree with it, then they must admit that they can be held responsible for saying it and can be expected to defend it. If they do agree with that second part of the verse, on the other hand, then they should can be expected to defend that and demonstrate that none of the atheists they are talking about "does good." They can't get out of this by saying that it's in the Bible and therefore must be accepted as true.
      Christians who cite this verse are implicitly stating that atheists are corrupt, do abominable things, and don't do any good in the world. This is a pretty serious accusation and not one which can or should be allowed to pass by unchallenged. Despite numerous attempts, no theist has ever conclusively demonstrated that belief in their god is required for morality - and in fact there are many good reasons to think that such a claim is simply false.
      It's easy to call someone a "fool" for not accepting your beliefs, but it's much harder to demonstrate that their rejection is mistaken and/or ill-founded. That may be why some Christians focus so much on the former and not at all on the latter. They prattle on about how it's "foolish" not to see that there must be "something more" out there, but don't look to them for anything like an argument about how or why we should see this. They can't even read and interpret their own religious scripture reasonably, so how can they be expected to read nature reasonably?

    • @Psycho4Ever666
      @Psycho4Ever666 9 ปีที่แล้ว +8

      Dan Hillman
      Leave the heart alone for fuck's sake, it just pumps blood!

    • @ExtantFrodo2
      @ExtantFrodo2 9 ปีที่แล้ว +2

      Dan Hillman The wise man shouts it from the mountaintops.

    • @CE113378
      @CE113378 9 ปีที่แล้ว

      Jose Veliz Late response here - mostly because I am busy with life. But I stand by the entire verse - as well as the entire Bible. But in doing so, let me just explain that I believe that all men (believers and unbelievers) are sinful, corrupt, and depraved. See Romans 1. Even our good deeds amount to filthy rags when we compare our "goodness" to the glory of God.
      I'd argue further that there is plenty of evidence in nature that the universe did not just spontaneously happen. The ordered-complexity of nature is strong evidence for a Creator. Finally, I would suggest that it is hypocritical to criticize Christians for "expressing superiority" (i.e. affirming Scripture) while praising an individual who is smugly and rudely not only expressing superiority, but also ridiculing Christians (by wearing an FSM shirt).

  • @letrung9199
    @letrung9199 5 ปีที่แล้ว

    Hi Dave, can I change logic fet with power one (24n60) and using 9V or event higher instead of 5v power supply, because I can't find logic fet

    • @-bru-NO
      @-bru-NO 5 ปีที่แล้ว

      Yes you can. You will have to adjust the voltage divider.