In general, if a matrix M is larger than 3 by 3 and nonsingular, which means an inverse exists, it is more efficient to factor it into the product of a lower-triangular matrix L with ones on the diagonal, and an upper-triangular matrix U with nonzero "pivotal elements" on the diagonal. That is, M = L*U. Inverses of L and U are generally not computed, but products of their inverses with other matrices are efficiently evaluated recursively using the existing entries in L and U. Check the internet for more detail if interested.
Wonderful thank you. For clarity, could please explain whether augmented matrix approach doesn't work for a 2 by 2 matrix, or whether the 2 by 2 approach is preferred for simplicity?
Mr. Jayson, how am I supposed to know what to multiply and subtract with? I mean, I would simply subtract with a constant, instead of multiplying with a row then add or subtract. Please help me!
THANK YOU... SIR...!!! You are right... It is tedious...!!! Very hard for a broken and tortured brain to memorize all of it...even though its concept is understandable...!!!
3,3 of inverse matrix should be 6. Nice job anyway
Only video that actually made sense, thanks
At 33:18. Do you multiply or divide the entries as to get the new row for row one?
In general, if a matrix M is larger than 3 by 3 and nonsingular, which means an inverse exists, it is more efficient to factor it into the product of a lower-triangular matrix L with ones on the diagonal, and an upper-triangular matrix U with nonzero "pivotal elements" on the diagonal. That is, M = L*U. Inverses of L and U are generally not computed, but products of their inverses with other matrices are efficiently evaluated recursively using the existing entries in L and U. Check the internet for more detail if interested.
You are the one all along 🙏💕
Thanks teacher; you are father. ኣመሠግናለሁኝ from Ethiopia 🇪🇹.
Wonderful thank you. For clarity, could please explain whether augmented matrix approach doesn't work for a 2 by 2 matrix, or whether the 2 by 2 approach is preferred for simplicity?
Mr. Jayson, how am I supposed to know what to multiply and subtract with? I mean, I would simply subtract with a constant, instead of multiplying with a row then add or subtract. Please help me!
Thank you so much Sir
THANK YOU... SIR...!!!
You are right... It is tedious...!!!
Very hard for a broken and tortured brain to memorize all of it...even though its concept is understandable...!!!
Inverse functions 🔥🔥🔥
Nice 👍
"i'm not gonna give you that proof"🤣🤣
A3.3 equals 6 not 2.
Beauty ful new look mr