Thanks for your comment here. As I have explained (didn't do the steps explicitly) that Euler's formula has been used here as e^(ix)=cos(x)+isin(x). That is, cos(x)=[e^(ix)+e^(-ix)]/2 and sin(x)=[e^(ix)-e^(-ix)]/2i. Thanks
I did not stop dear Talal. I was having too many engagements and also my throat was not good. Today, when I will share the new lecture, my throat isn't yet fully recovered. Thanks
In case you're able to do it yourself, you're at a wrong place. These lectures are not for you. Thanks BTW you're writing copying as copping constantly. Thanks 👍
Sir how tan inverse is introduced. I didn't understand that step
Thanks for your comment here. As I have explained (didn't do the steps explicitly) that Euler's formula has been used here as e^(ix)=cos(x)+isin(x). That is, cos(x)=[e^(ix)+e^(-ix)]/2 and sin(x)=[e^(ix)-e^(-ix)]/2i. Thanks
thank you
Welcome dear 😊
Ain't no Fun in Cartesian 😎😎😎
You're are right. But it's good to have a different taste. Thanks
Why did you stop ?
I did not stop dear Talal. I was having too many engagements and also my throat was not good. Today, when I will share the new lecture, my throat isn't yet fully recovered. Thanks
Sir why you copping the whole things by seeing the solution
In case you're able to do it yourself, you're at a wrong place. These lectures are not for you. Thanks
BTW you're writing copying as copping constantly. Thanks 👍
At last!
At last, what?
@@SAYPhysics at last you returned to Griffiths... I hope we will find the first comprehensive explanation of this textbook on TH-cam.
@@SAYPhysics I consider your work superb
Good to know dear 😊