ขนาดวิดีโอ: 1280 X 720853 X 480640 X 360
แสดงแผงควบคุมโปรแกรมเล่น
เล่นอัตโนมัติ
เล่นใหม่
Always a pleasure to view your informative videos.
👍🙏
Thanks Sir for educating us.All your lectures are loaded with lot of wisdom.Thanks
So nice of you. Thanks.
Your efforts are highly appreciated Prof Yaakov, thanks a lot.
Thanks.
21 more to go to reach 500 milestone!!!!
Working on it. Stay tuned.
another question:in 17:53, why Vcin slightly decreases at Vg>4V(miller plateau)? you mentioned small signal but i am still confused.
If Q(V) is sort of exponential and you divide Q/V to get Ct at points along the curve, the value decreases at high voltages.
Thanks Professor Yaakov
Thank you 👍
🙏
Hi professor, can we do such calculation:For Qgs, we do Qgs=15V*Cgs (normally Cgs is constant in this voltage range).For Qgd, we do Qgd=Cgd(er)*Vb+∫Cgd*Vgs(0-15V)er=energy relatedThank you in advance for your education.
Yes indeed. Good thinking.
👍🙏❤️
😊👍🙏
Always a pleasure to view your informative videos.
👍🙏
Thanks Sir for educating us.
All your lectures are loaded with lot of wisdom.
Thanks
So nice of you. Thanks.
Your efforts are highly appreciated Prof Yaakov, thanks a lot.
Thanks.
21 more to go to reach 500 milestone!!!!
Working on it. Stay tuned.
another question:
in 17:53, why Vcin slightly decreases at Vg>4V(miller plateau)? you mentioned small signal but i am still confused.
If Q(V) is sort of exponential and you divide Q/V to get Ct at points along the curve, the value decreases at high voltages.
Thanks Professor Yaakov
👍🙏
Thank you 👍
🙏
Hi professor, can we do such calculation:
For Qgs, we do Qgs=15V*Cgs (normally Cgs is constant in this voltage range).
For Qgd, we do Qgd=Cgd(er)*Vb+∫Cgd*Vgs(0-15V)
er=energy related
Thank you in advance for your education.
Yes indeed. Good thinking.
👍🙏❤️
😊👍🙏