i remember the day s when youtube videos couldn't be longer than 10 minutes... really good set of videos. OG since 2009, if they ain't broke, don't fix them! this is finally making sense to me. good work, thanks man.
I Swear to god I am the worst at understanding, even when I work with this in school I still don't get ieven after i have been having private lessons with my teacher... But I found these Subnetting Magic Number Videos and everything went the other way Now I understand Thsnk You So Much :)
@chessie459 adding the ones in the binary 111111111.11111111.11111111.11110000 the last octet is 11110000 with the ones in the following place values 128+64+32+16 = 240
I like the way to you teach .Thank you for such a nice tutorial..but in the third octet there are only 7 bits ...same was the case in tutorial number 37 also.....
Thank you very much sir, I thought on the start you were unreliable becoz of the mistake but you corrected it AHAHAHAHA I was nearly confused, but you are very helpful. Thanks
Because he was doing a classfull and he made an error with his last part of the video. The classfull means 8/16/24 and every class has 1111 1111,what is equal to 255 so your 'last' network number is 255 and thus equal to the broadcast
12 ปีที่แล้ว
Oh god.. Thats what I was looking for. Thank you man. Even though you voice irritates me so much ^:) I'm so grateful! Thanks again!
He lost me at around 3:00. So just to make sure... is 192.168.3.48 the network number because 192.168.3.0 - .47 were already in use or something? He also lost me on the "borrowing bits" part. Could someone please explain that to me? Thanks in advance!
borrowing bits is a reference to changing the /24 clid to /27. He had to add three bits to the subnet mask, they had to come from somewhere. They came from the host ip bits. The "last bit" borrowed is number 27, which resides in the 16 place, therefore the bit had a value of 16. If he had borrowed only two bits, it would have made the clid /26, and the last borrowed bit would have a value of 32.
just a quick question so i understand correctly. but if the next network number was going to be a 255 wouldnt the broadcast have to be a 254 and the valid host range be from 1--253? or is the application different because you cant use a host above 255 if the network number was to be 255. Hope this isnt years to late to be answered. Thanks!
Thank you for your awesome tutorial. While I'm still watching your video, I have a question. Does it matter where we arrange the ones to make a combination of 28 1s or does it have to be in sequence like you have shown on example. Hope you will reply fast, coz I have my final a day after tomorrow.
+purplehaze The chart reads from left to right (128, 64, 32, 16, 8, 4, 2, 1), so if you then put in 28 "1s" from right to left, you will then have them in the wrong spots.
128 + 64 + 32 + 16 = 240 :) the Table goes as follows. 128 64 32 16 8 4 2 1 You half and then you simply add up to whatever you have. The /24 means that everything except the last octet is being used :) Binary = 11111111.11111111.11111111.00000000 You follow the table and add up :)
from converting the new difficult mask of /28 to binary. 240 comes from the 4 bits in the interesting octet(last octet with 1s), the bits each represent 128 + 64 + 32 + 16 = 240.
+Illyrian Shqyptar To my understanding, a classful subnet is when the /# occupies a full octet, like /8, /16/ or /24, and since he did not give a classful subnet (he gave /28), that means there is now 28 "1's" that are on for the subnet. (11111111.11111111.11111111.11110000), which he then took the last "1" from the last octet (which is in the 16s spot), giving a magic number of 16.
well basically what's he's saying is: the .0 you cannot use because it identifies your Network number :) ( Network ID) so if you wanted to make a network it needs a name, that would be your name. The .255 is the broadcast meaning that it is the message used to send to all in case a packet needs to be sent :) Therefore that one cannot be used either :) what's left? everything in between :)
Me (Scouring the internet to figure out how the binary representation of the subnet mask made any sense): Why the hell does 11111111 11111111 11111111 11100000 equal 28? Dan: 25 ones, 26 ones, 27 ones, 28 ones Me: 🤯
I've been study for the CCNA for a while now and your videos are the only ones that has made sense so far to me..
im taking a class at a community college but i was completely lost til i saw your videos. thank you very much.
My professor loses me in class and in his videos too but your videos help me understand it better. Your videos make sense.
Keep up the good work.
best I seen ever.... I was tired of the complicated stuff you find on youtube claiming that it is the 'easy' method
i remember the day s when youtube videos couldn't be longer than 10 minutes... really good set of videos. OG since 2009, if they ain't broke, don't fix them! this is finally making sense to me. good work, thanks man.
Thank you for doing these videos. I have watched many TH-cam videos on subnetting and yours really helped me the most.
Holly banana, I can't believe this is 10 years ago. And still very helpful
You don't stall, "aah" every 5 seconds. Beautiful knowledge, voice, dexterity, language and accent.
WoW. i didn't get it in the class but your "magic number" trick it's really works and it's so easy to remember!! Thank you very much=)
Thank you so very much, even a dummy like myself can understand this lesson, you are the best.
No one is a dummy, is just that your previous teachers couldn't explain well somethings as simple as this.
Magic number (255+1 = 256) take 256 subtract subnet mask (240) left with 16.
Wow, 2024, and this video is still extremely relevant and apropos. Thank you so much.
I Swear to god I am the worst at understanding, even when I work with this in school I still don't get ieven after i have been having private lessons with my teacher...
But I found these Subnetting Magic Number Videos and everything went the other way
Now I understand
Thsnk You So Much :)
between you and Jeremy from CBT Nuggets I'm almost prepared for the test Thanks!
@chessie459 adding the ones in the binary 111111111.11111111.11111111.11110000
the last octet is 11110000 with the ones in the following place values 128+64+32+16 = 240
Thanks for this. I was so confused on how you got 16 lol.
the best i have seen on subnetting.
This tutorial is so good thanks for doing this.
@danscourses thanks! video is really helpful for networking newbies.
hi, how do you convert the "28" in 192.168.3.55/28 TO 255.255.255.240?
One more fan here! Thanks for the great tutorials.
Thanks for great presentation .Would you please explain how did you get 240 ?
I like the way to you teach .Thank you for such a nice tutorial..but in the third octet there are only 7 bits ...same was the case in tutorial number 37 also.....
3:00 time Where did u get the 48? In net???
00110000 = 48
Thank you very much sir, I thought on the start you were unreliable becoz of the mistake but you corrected it AHAHAHAHA I was nearly confused, but you are very helpful. Thanks
I'm still a bit fuzzy on how you were able to obtain the broadcast IP.
Because he was doing a classfull and he made an error with his last part of the video. The classfull means 8/16/24 and every class has 1111 1111,what is equal to 255 so your 'last' network number is 255 and thus equal to the broadcast
Oh god.. Thats what I was looking for. Thank you man. Even though you voice irritates me so much ^:) I'm so grateful! Thanks again!
Right on. Appreciate that.
This is all new to me, so I'd like to ask where you got 44, you wrote 48; but when you wrote it below, you wrote 44 ???
WHAT application are you using to do the tutorial?
nice explanation sir
Awesome Tutorial! Small error in third octet : zero is missing in ip address and 1 in subnet mask.
He lost me at around 3:00. So just to make sure... is 192.168.3.48 the network number because 192.168.3.0 - .47 were already in use or something? He also lost me on the "borrowing bits" part. Could someone please explain that to me? Thanks in advance!
borrowing bits is a reference to changing the /24 clid to /27. He had to add three bits to the subnet mask, they had to come from somewhere. They came from the host ip bits. The "last bit" borrowed is number 27, which resides in the 16 place, therefore the bit had a value of 16. If he had borrowed only two bits, it would have made the clid /26, and the last borrowed bit would have a value of 32.
@@errolmcinnes7938 A bit late, but thanks for the reply! I understand it now!
just a quick question so i understand correctly. but if the next network number was going to be a 255 wouldnt the broadcast have to be a 254 and the valid host range be from 1--253? or is the application different because you cant use a host above 255 if the network number was to be 255. Hope this isnt years to late to be answered. Thanks!
Wait, how did he get from cidr/28 to subnet mask.240?
11110000 in binary = 240 in decimal
how to get that 240?
Please, how did you get 48? 192. 168.3 . (48) I'll be very happy if you can break it down
Why usually ip address starts 192. Thats some kind of agreement or what?
where is the next part of this tutorial
Why does 3rd octet have only 7 bits?
You are the best...
there is a 1 value missing in 3rd octate of every ip
Thank you for your awesome tutorial. While I'm still watching your video, I have a question.
Does it matter where we arrange the ones to make a combination of 28 1s or does it have to be in sequence like you have shown on example.
Hope you will reply fast, coz I have my final a day after tomorrow.
purplehaze The ones are all contiguous from left to right
purplehaze Assuming you are talking about a /28 subnet mask
+purplehaze The chart reads from left to right (128, 64, 32, 16, 8, 4, 2, 1), so if you then put in 28 "1s" from right to left, you will then have them in the wrong spots.
Great tutorial!
How do you derive .240 from /28?
128 + 64 + 32 + 16 = 240 :)
the Table goes as follows. 128 64 32 16 8 4 2 1
You half and then you simply add up to whatever you have.
The /24 means that everything except the last octet is being used :) Binary = 11111111.11111111.11111111.00000000
You follow the table and add up :)
Thanks! :)
255 means 8 ones right?? y did the 3rd octet contains only 7 ones?? it should be 8 to make it 255
yeah he fcked up :p
@c7i6abc He was just showing us a different example
Amazing! thanks
how did you get 240? Does anyone know?
from converting the new difficult mask of /28 to binary. 240 comes from the 4 bits in the interesting octet(last octet with 1s), the bits each represent 128 + 64 + 32 + 16 = 240.
Oh, ok that clears stuff up, i was getting confused. Thanks man!
geez, thanks! very nice tut.
Thanks for you Great tutorial!
thank you soo much .2020
Very helpful!
using the magic number 192.168.1.0 /24 , i always have hard time to solve /24 network using the magic number thank you
Multiplication in boolean logic is the same thing as a logical and, the students assumption is fine.
just thought i'd point out (not too important) that you only have seven numbers in the third octets.
I dont understand how you "borrowed 4 bits".
+Illyrian Shqyptar To my understanding, a classful subnet is when the /# occupies a full octet, like /8, /16/ or /24, and since he did not give a classful subnet (he gave /28), that means there is now 28 "1's" that are on for the subnet. (11111111.11111111.11111111.11110000), which he then took the last "1" from the last octet (which is in the 16s spot), giving a magic number of 16.
Cox Ucker 2^4=16
Yeah, it's so logical that no one can give it a reasonable explanation.
Last few seconds of your video you lose sound and it seems as if the video ended rather abruptly....
How Binary Come from 110000000.10101000.0000011.00110111
Can anyone reply details............?
still you wait someone to reply ?
Thank
4:12, i did not understand
well basically what's he's saying is:
the .0 you cannot use because it identifies your Network number :) ( Network ID) so if you wanted to make a network it needs a name, that would be your name. The .255 is the broadcast meaning that it is the message used to send to all in case a packet needs to be sent :) Therefore that one cannot be used either :) what's left?
everything in between :)
u missed a 1 but great vid lol even i nthe last vid lol
It's not THAT hard to learn.... first off, watch his Binary how-to videos before you even touch Subnetting.
Me (Scouring the internet to figure out how the binary representation of the subnet mask made any sense): Why the hell does 11111111 11111111 11111111 11100000 equal 28?
Dan: 25 ones, 26 ones, 27 ones, 28 ones
Me: 🤯
aaaand you lost me... :/
Look dude. You get an points for trying. But new people do not understand a thing your saying.
To much smacking in the mic