I found the same answer, but differently. I kept moving over to the right, substracting from right to left in pairs of two. 12-3=9 etc. Then, 9 is 3 at the 2nd power, plus the first number in the pair. 120 = 3 at 5th power + 120 = 363
I got mine as 1 saw that the coefficients of 3 are 1, 4, 13, 40 respectively, and are increasing 3, 9, 27... which are powers of 3. 3¹, 3², 3³, then 3⁴ which is 81. 81 + 40 is 121. If 121 is the coefficient of 3, then the next number in the sequence is 3 × 121 = 363
If you needed to count to infinity,you count forever and if you count fast and another counts slow then the numbers will never be the same.only more different.And If the keep being bigger than each other,then infinity can be different sizes. I just solved an huge debate and I’m only fricking 10...
9:18 6+8+3 does not equal 15; neither will 7+2+4. Swapping 6 and 4 improves the logic only marginally, as not all vertical lines add up to 15. A better approach to this problem is to note that the number in the middle square (5) is equidistant from the numbers on either side of it in any given row; you still get 2 as your answer for the missing entry, but the logic is now made sound.
He could have created a "magic square" where all rows, columns and diagonals add up to the same number by having 8, 1, 6 on the top row, 3, 5, 7 in the middle, and 4, 9, 2 on the bottom. That is a much better problem esthetically, but he did say he wasn't good as math. :)
TIMESTAMPS Riddle #1. What is the missing number? 0:37 Riddle #2. Take a look at these four rhombuses. what's the missing number? 1:18 Riddle #3. Can you determine the pattern and figure out what the missing number is in the last circle? 2:18 Riddle #4. One triangle has all its number in place, but other two miss the numbers on top. Can you guess them? 3:25 Riddle #5. Study the figure below. What number, in your opinion, is missing here? 4:23 Riddle #6. One of the numbers in the bottom “arrow” is missing. What's the missing number? 5:20 Riddle #7. Four lines of numbers. What number should be in the place of the question mark? 6:24 Riddle #8. What number is missing here? Test your skills once again! 7:35 Riddle #9. Look carefully at this picture, Sherlock. Your task is simple - try to find the missing number. 8:40 Riddle #10. 3, 12, 39, 120, and...? What is the next number in this line? 9:47
More often than not there are two or more solutions to the same problem all you have to do is find the other. You found the second correct solution to the problem as did I. Good job on finding the solution all of you.
I solved #04 with "3+4=7" and "7-1=6" so the other ones were "5+4=9-1=8" and "2+2=4-1=3". #08 I solved way easier(to me!) than described and still got the same result. 34-4:6=5, so 4+1=5. 53-5=48:8=6, so 5+1=6 again and 47-3=44:11=4, again 3+1=4. Therefore 9*3=27+2=29 (reverse way from what I did before, means 29-2=27:9=3, so 2+1=3). #09 seems to be a only half true assumption. 7+4+2=13 and not 15. This solution of 2 only works if you think about the "1,2,3,4,.." or if you say that only the connected numbers always give 15. Not like what you did with the red circles and saying "each line" in that sense.
I got them all (a couple took more than 15 seconds, I admit) but the weird thing is that in about half of them, I arrived at the number in a completely different way. For example, on #9, I followed the lines from the outside through 5 in the middle to arrive at a number figured on the right-hand side. The "pattern" went 6-5=1, 8-5=3, 9-5=4 then all that was left that wasn't used by subtracting 5 was 7 (even though the answer would be at the bottom rather than on the right), so 7-5=2. 2 turned out to be the correct answer, but that is NOT how I got it. The others were similar. I guess I just think in a unique way.
On #9 the top row doesn’t add up to 15. The bottom row also doesn’t add up to 15.The left vertical row doesn’t add up to 15. The right vertical row doesn’t add up to 15.
For the last one, let's take U0=3 for all positive integers n we have Un+1=3*Un+3. We have : U1=3*Uo+3=3*3+3=9+3=12 U2=3*U1+3=3*12+3=36+3=39 U3=3*U2+3=3*39+3=117+3=120 So : U4=3*U3+3=3*120+3=360+3=363
9:43 You cm also identify the answer is 2 by the patterns of the numbers. Look closely at the lines: Line 1. 6, 5, 4 (repeated decrementing) Line 2. 9, 5, 1 (repeated subtracting by 4) Line 3. 7, 5, 3 (repeated subtracting by 2) So line 4 must be 8, 5, 2 (repeated subtracting by 3)
I GOT ALL OF THEM RIGHT!! I guess I really am very good at math! 😂😂😂😂😂😂😂😂 Edit:(I did some of them a different way but still got the same answer like #3 you can just double it)
Nope #09 is not correct: Because "6+8+3=15" is not correct and "7+2+4=15" is also incorrect!! We all guessed 2 because it was the only number missing so it must be something like the first riddle
For 9, I also realize that 6 and 4 had the same difference with 5, as did 3 and 7. So I guess the secret number must be three less than 5, since 8 is equal to three more. 5-3=2 Can we talk about the fact that these riddle have nothing to do with math? It's luck;you just have to find the right pattern.
do the fist and last values of each line divided by 2 they must always equal 5 and also im pretty sure he didnt bother to make up his own problems , he clearly just went backwards from the answer to find the solution and also its applicable to the numbers in a line
I used different methods but still got the correct answer on #8 and #4. On #8, this is what I saw and used, initially, for the steps: A) Multiply first by whatever the the sum of second+1 is B) Add the original second to the result and you get the third. Went back afterwards and figured that In algebra, with X, Y, and Z to represent the first, second, and third numbers, respectively. So in all three given cases you have: x y z Now, using my method of multiplying x by y+1, then adding y, we get: x(y+1) + y = z This works for all of them, try it. 6(4+1) + 4 = 34 (because 6x5 = 30, then add 4 for 34) 8(5+1) + 5 = 53 (8x6 is 48, add 5 for 53) 11(3+1) + 3 =47 (11x4 is 44, add 3 for 47) 9(2+1) + 2 = 29 (9x3 is 27, 27+2 is 29) I was shocked when their method was different at first, but then I realized, funnily enough, this formula of mine is merely the simplified form of the formula they have given you in the video. They say multiply first and second, then add the sum of the first and the second to the product to get the third. Using X for first, Y for second, and Z for third again, you get: xy + x + y = z For instance, as they said, 6x4 + 6 + 4 = 34. (Since 6x4 is 24, 6+4 is 10, and 24+10 = 34) Of course, xy+x is the same thing as x(y+1). Which is why both formulas work. Furthermore, now that I look at it I realize that you could also solve this problem a third way, by creating the formula y(x+1) + x = z. Since y(x+1) gives you xy+y it's easy to see where this comes from. That would mean you'd multiply the second number by the sum of the first and 1, and then add the first. So to use the example number sequence of 6, 4, and 34, we get: 4(6+1) + 6 = 34 Which holds true since 4x7 is 28, and 28+6 is 34. Pretty cool how that all works out the same! (if you're a math geek like me). Try it with the other two sets yourself if you don't believe me. Now for #4. There are at least five ways to do this, I found. Initially, I actually started with the largest number (the one in the lower right hand corner of the triangle), subtracted the number on the lower left, then added the top number. It worked on all of them too and got me to 10 and 4 for the missing numbers. In Algebra, that would go like this, using x for the number outside the triangle, a for the top number, b for the lower left hand corner, and c for the lower right hand corner. Or: x a b c So: c-b+a=x Remember you have to go left to right with addition and subtraction for this one to work. Again, this formula works for all of them. Try it. 7-4+3 = 6 (7-4 is 3, 3+3 is 6) 9- 4+5 = 10 (9-4 is 5, 5+5 is 10) 4-2+2= 4 (4-2 is 2, 2+2 is 4) Hm. That's not what they said to do to get the answer, though. They said to take the top number (a), add the lower right hand number (c), and subtract the lower left hand number (b), For instance, 3+7-4=6. So their formula would be: a+c-b=x Let's see if you can get this formula from mine. If you take my formula of c-b+a=x and subtract a from both sides, we have c-b=x-a. Now let's simply add a back to both sides and viola! You get their formula. a+c-b=x. Easy peasy. I promised there were three other ways to solve #4. One is very complicated and I doubt if anyone would see it just by looking at the numbers since it involves negative integers. The other two - especially the last - were so easy I was kicking myself for having gone to all this trouble, after finding it. So, first up, the complex solution. If we do another rearranging of the letters we can get them in alphabetical order and have a-b+c=x. This will work for all three groups as well but it involves negatives in the first of the three cases. Again, always go left to right to make it work. Examples: 3-4+7 =6 (3-4 is (-1), 7+(-1) is 7-1, 7-1 is 6) 5-4+9=10 (5-4 is 1, 9+1 is 10) 2-2+4=4 (2-2 is 0, 0+4 is 4) Now wait a minute. Something sneaky is hidden here. Because it's human nature to want to use all three given numbers, we miss two hidden solutions that don't use all the numbers but are much easier than what we've been running around trying to do. And they also can be explained algebraically. Let's take my formula of c-b+a = x again and look hard at the numbers involved in it. 7-4+3 = 6 (7-4 is 3, 3+3 is 6) 9- 4+5 = 10 (9-4 is 5, 5+5 is 10) 4-2+2= 4 (4-2 is 2, 2+2 is 4) Did you catch it? C-b and a are the same number! 7-4 is 3, but a is also 3. 9-4 is 5, but a is also 5. And so on. Therefore: c-b=a So inserting this into our original formula, we can look at this two ways. The first involves getting rid of A altogether and replacing it with the (c-b) it's equal to: (c-b) + (c-b)=x 2(c-b) =x Or, basically, subtract b from c and double the difference. This works in all three cases. 2(7-4) =6 2(9-4) = 10 2 (4-2) = 4 That's a LOT easier, but the fifth method will make you kick yourself, as I did myself, when you realized all of this could have been bypassed by noting on the first triangle that twice 3 is 6. Or, algebraically: 2a=x That's right, you don't have to use b or c at all. You can simply get the correct answers by knowing your 2 times table. 2x3=6 2x5=10 2x2=4 How do you get that from our original formula of c-b+a=x? Easy peasy. Remember I said c-b = a? I just do this: c-b=a, (c-b)+a=x, a+a=x, 2a=x If you read all the way to the end of this you're probably kicking yourself right now, and also you're probably a math geek/pattern lover like me. God Bless! :-)
#10- the difference between 3 and 12 is 9. Multiply that with original 3 and get 27. Add that to 12 and you get 39. Take previous difference 27 x 3= 81 then add 39=120. Take 81x3+120=363. I'm terrible at math but can see patterns.
For the last riddle you could have done the nth term which would be the difference between 3 and 12 which is 9 and the difference between 12 and 39 which is 27 and the difference between 39 and 130 is 81 and the numbers are 9,27 and 81 and if you, x 9 by 3 it gives 27 and if you x 27 by 3 it gives 81 so you have to do 81 x 3 which gives 243 and you just have to add 243 to 120 and it gives 363
well, that was easy. The only one I personally had some problems with was the one with the triangles as there wasn't enough information to validate a possible answer. In the end I simply went with doubling the inner top number - which is effectively the same as the answer provided in the video.
#8 (alternative solution) It could also be 6x5 + 4 = 34 8x6 + 5 = 48 11x4 + 3 = 47 9x3 + 2 = 29 For #10 (alternative solution) Simply add 1 then multiply it by 3 (3+1) x 3= 12 (12+1) x 3 = 39 (39+1) x 3 = 120 (120+1) x 3= 363
#04 it also could be multiply all the numbers each triangule and divide the add of all of them For example: (3*4*7)÷(3+4+7)= 6 And the others will be: (2*2*4)÷(2+2+4)= 2 And (5*4*9)÷(5+4+9)= 10
1 solved 8 except 1 and 2 and i used my own trick in last 10 ques of 3,12,39,120 my trick is 3×4=12,after 12 next no. is 13 so 13×3=39,after 39 next no is 40, 40×3=120,after 120 its 121 121×3=363
Riddle 9: 8 hits 5 and 3 is the out put that can can be seen on the top right (8-5=3), 6-5=1 (the answer cam be seen on the right), 9-5=4 (bottom right), and Finally 7-5=2 (buttom)
For number 10, I thought this: 3+1=4, 4*3=12. Adding 1 to the number and then multiplying it by 3. 12+1=13; 13*3=39. 39+1=40; 40*3=120. 120+1=121; 121*3=363
For riddle no. 4, other logical answer could be 2 on the vortex of 2nd triangle and 6 on the vortex of 3rd triangle. First multiply the three digits in each triangle and then find their sum. Divide the product with the sum. The result is the number on the vortex of that triangle
9/10 In riddle 6 we can apply another logic.. 2,6,8 36,45,54 18,15,12 So 12 should also be accepted. If it was multiple choice the if option 12 was missing understandable but its not multiple choice so every answer with a reasonable logic should be accepted
I did not count how many I got right - but it was most of them. However, I discovered one thing - I almost always arrived at the right answer by a method other than the one given. Therefore, it means that there is definitely more than one way of arriving at the correct answer.
Number 10: 39(3rd number)devided by 3(1st number)=13;120:12=10;with this logic the missing number is 39x7(why 7?because 13-10=3 and to keep this difference between the factors we have to do 10-3,that's equal to 7),and 39x7=273. And with this I'm not saying that I think correctly and who made this video does not, I'm just saying that I think you should consider this way to solve it. If you got to this point thank you for your attention and tell me what you think
Puzzle 4 can be solved with numerous other answers because there is only one completed series. The question in puzzle 4 does not limit the answer in any way. In puzzle 2, you needn't use the word "rhombus" because the figures are squares. They are set on point, but still are squares.
In Riddle 9, @ 9:05, First Diagonally, 6 -5 =1, and 5-4 = 1. Again, diagonally, 3+2 = 5, and 5+2 = 7. In middle, 9-4 = 5, 5-4 = 1. This way, 8-5 = 3. So, 5-3 = 2. Thus, 2 should be the answer.
For 8, I multiplied the first number (top left) by the right number (top right) added by 1 then added the right number again to get the solution. So basically L x (R+1) + R, an example is 6 x (4 + 1) + 4 = 34, or 8 x (5 + 1) + 5 = 53.
Number 9 was pretty easy, you can either look at it and tell 2 is missing, or add the top and bottom numbers, then divided by 2 to get 5. This can be done for the other directions like diagonal or horizontal.
I got number 4 correct, although for the wrong reason. I saw that 7 - 3 = 4 , 4 - 2 = 2 , 9 - 4 = 5 , so basically the bottom numbers always equaled the top numbers. And since there was a 6 over the 3 I came to the conclusion that the top numbers of each triangle double every time.
Answer this: You have 10 boxes with rabbits inside. The number of rabbits inside each box depends on the number of their box. They also give birth to the same number each as the box number. The boxes are numbered 1-10. How many rabbits are there in total? The equation could either be:n+(n×n) or n+(n^2). So,1+(1*1)+2+(2*2)+3+(3*3)+4+(4*4)+5+(5*5)+6+(6*6)+7+(7*7)+8+(8*8)+9+(9*9)+10+(10*10). Also,try n+(n^2) or n×(n+1)
#1 has a pattern. Column 2 = one's digit from columns 3 & 4 added together. Missing info doesn't mean not a duplicate. #2 didn't follow that logic. And I was never told I had to use the first column. The missing number is 3.
I got 6 from 10. Number 10 is wrong. 2 scenarios. One is that you added one the multiplied 3(which I did to get 363). That scenario suggests keeping 363 as the correct answer. The second one which uses your pattern would end up as 369 not 363. 123 multiplied by 3 is 369
This is just for people who want to say they are good at maths through puzzles that are only vaguely related. For you geniuses then, whats n^x^y only one exponent, or ax+by relative to c
Last one 10:30: 3 times 4*3=12, then 3*13=39,3*40=120, there's a hidden pattern as well all these answers (3,4,39) if you add 1 to all of them gives us the exact multiplying numbers (12+1=13, 39+1=40...) as you can see they all gets added by 1 therefore back to first scenario 3(3+1), 3(12+1)=36, 3(120+1)=363
wow in #09 6+8+3=15 and also 7+2+4=15 what a great addition👏 The correct logic is that 5is the arithmetic mean of any row, column or diagonal and still the answer is 2 .
I was very close on the thumbnail question 3 12 39 120 my guess was 390 my logic was that 3 is 1 + 2 so 12 12 is 3 + 9 so 39 although I guess that's where my logic fell apart I was just assuming it would continue to scale like that basically however I was still pretty close because 363 is 3 + 6 + 3 which is 12
I think in #10 there’s another answer calculating the differences between numbers: 12-3=9 39-12=27 120-39=81 If you see is the same if you write: 3^2=9 3^3=27 3^4=81 3^5=243 3^6=729 . . . 3^x=to infinite So if we return to the original formula with the differences it’s supposed... 3 , 12 , 39 , 120 , x \/. \/. \/. \/ 9. 27. 81. 243 So, x = 120 + difference = 120 + 243 = 363 And this is another way to solve it
09) 9 is left and 1 is right and 9+1=10.And 3 and 7 are opposite and they both make 10.Same goes to 6 and 4. 5 is in the middle (5+5=10) and 8 is on top and the bottom is......2!
1. In the grid 2. Rhombuses 3. Doubles 4. The Three Triangles 5. 90 In The Middle 6. Arrows 7. Where is the question mark? 8. Hopstotch pieces 9. Sum is 15 10. Neeeeeeeeeeeeeext!
For #06 number 11 can be the answer for another reason: Multiply the number on the top and number on the bottom and you get the doubled middle number. It works for every given example
riddle #9 another solution Numbers 1-9 ( 2 was missing) or use the line 6-5-4 ( 1 interval) 3-5-7 (2 interval) 8-5- ? (3 interval) so answer is 2 9-5-1 (4 interval)
Hey guys! What is your favorite school subject?
Math!!!
and also English
BRIGHT SIDE math and Science
Maths
Math And One Like On This Comment??
maths and physics
In #10 I got thought that
3+1=4 ;4×3=12
12+1=13 ;13×3=39
39+1=40 ;40×3=120
120+1=121 ;121×3=363!!!!
And Yes This Is My Age!!!!
👇
I think ur mpc Student
I found the same answer, but differently. I kept moving over to the right, substracting from right to left in pairs of two. 12-3=9 etc. Then, 9 is 3 at the 2nd power, plus the first number in the pair. 120 = 3 at 5th power + 120 = 363
Bright side also told the same thing.... He just added 3 which ultimately gave rise to 121
120(3)+3=121(3)
I got mine as 1 saw that the coefficients of 3 are 1, 4, 13, 40 respectively, and are increasing 3, 9, 27... which are powers of 3. 3¹, 3², 3³, then 3⁴ which is 81. 81 + 40 is 121. If 121 is the coefficient of 3, then the next number in the sequence is 3 × 121 = 363
I solved same like you
Usually real good at math, but this one was kind of tough. Some were not completely math related
They were more logic puzzles than maths puzzles.
watch my maths videos to learn ,.,,,,...,.,.,.
supit
Bruh, even with my confirmed 145+ IQ I got some wrong.
If you needed to count to infinity,you count forever and if you count fast and another counts slow then the numbers will never be the same.only more different.And If the keep being bigger than each other,then infinity can be different sizes.
I just solved an huge debate and I’m only fricking 10...
9:18 6+8+3 does not equal 15; neither will 7+2+4. Swapping 6 and 4 improves the logic only marginally, as not all vertical lines add up to 15.
A better approach to this problem is to note that the number in the middle square (5) is equidistant from the numbers on either side of it in any given row; you still get 2 as your answer for the missing entry, but the logic is now made sound.
Yep. He should have said all the numbers connected by the lines (which all go through the 5).
Another way to look to look at that riddle is when you add the top and the bottom together, then divide by 2 you will always get 5
Yep, that’s how I solved as well.
He could have created a "magic square" where all rows, columns and diagonals add up to the same number by having 8, 1, 6 on the top row, 3, 5, 7 in the middle, and 4, 9, 2 on the bottom. That is a much better problem esthetically, but he did say he wasn't good as math. :)
Buddy Mack only the diagonal ones in that question add up to 15 not the horizontal ones. They made a mistake.
TIMESTAMPS
Riddle #1. What is the missing number? 0:37
Riddle #2. Take a look at these four rhombuses. what's the missing number? 1:18
Riddle #3. Can you determine the pattern and figure out what the missing number is in the last circle? 2:18
Riddle #4. One triangle has all its number in place, but other two miss the numbers on top. Can you guess them? 3:25
Riddle #5. Study the figure below. What number, in your opinion, is missing here? 4:23
Riddle #6. One of the numbers in the bottom “arrow” is missing. What's the missing number? 5:20
Riddle #7. Four lines of numbers. What number should be in the place of the question mark? 6:24
Riddle #8. What number is missing here? Test your skills once again! 7:35
Riddle #9. Look carefully at this picture, Sherlock. Your task is simple - try to find the missing number. 8:40
Riddle #10. 3, 12, 39, 120, and...? What is the next number in this line? 9:47
A Strange thing! In 2 questions, my answer was correct but my logic and the answer's logic wasn't same.
still true if the logic was true an no mistakes
Same for most of them
yeah me too in question number 4 4:20
mistake : 3 x 2 = 6 , 5 x 2 = 10. 2 x 2 = 4
Whaaat, on question #09. I thought 2 because the numbers were: 1, ?, 3, 4, 5, 6, 7, 8, 9.
It was correct answer but wrong solution!
Kristoffer Vassbø I did that too lol 😂
lol i didnt i found out the correct way
More often than not there are two or more solutions to the same problem all you have to do is find the other. You found the second correct solution to the problem as did I. Good job on finding the solution all of you.
oh wow your right didnt notice that
Fina Romero. There is no line connecting 7, 2, and 4, so you don't add them. Don't know why they circled them though.
I got all correct except for the one with the "rhombuses" (those weren't rhombuses; they were just squares oriented diagonally).
Well square is a rhombus.
@@laurato9517 According to the site "Difference Between Square & Rhombus - Vedantu", that is not true.
This actually taught me new math lessons because I never saw them before, so thanks!
Question five could have a lot of answers because it doesn’t have enough triangles to ensure what the pattern is
3:24 you can do 26 times 2 it more easy
That’s what I did :-)
I solved #04 with "3+4=7" and "7-1=6" so the other ones were "5+4=9-1=8" and "2+2=4-1=3".
#08 I solved way easier(to me!) than described and still got the same result. 34-4:6=5, so 4+1=5. 53-5=48:8=6, so 5+1=6 again and 47-3=44:11=4, again 3+1=4. Therefore 9*3=27+2=29 (reverse way from what I did before, means 29-2=27:9=3, so 2+1=3).
#09 seems to be a only half true assumption. 7+4+2=13 and not 15. This solution of 2 only works if you think about the "1,2,3,4,.." or if you say that only the connected numbers always give 15. Not like what you did with the red circles and saying "each line" in that sense.
I got 9/10
Me too
liar
Me 2 but i paused it hehe
2. Answer 2 is correct
Because 7x6. 42 ,, 9x9..81,,then 6x2..12
I got them all (a couple took more than 15 seconds, I admit) but the weird thing is that in about half of them, I arrived at the number in a completely different way. For example, on #9, I followed the lines from the outside through 5 in the middle to arrive at a number figured on the right-hand side. The "pattern" went 6-5=1, 8-5=3, 9-5=4 then all that was left that wasn't used by subtracting 5 was 7 (even though the answer would be at the bottom rather than on the right), so 7-5=2. 2 turned out to be the correct answer, but that is NOT how I got it. The others were similar. I guess I just think in a unique way.
Same thing with me!
You got them all, dynamite! How old are you? I think the younger minds do better on these kinds of tests. My 67-year-old fossilized brain got 7 right.
@@nelsonx5326 Same age as you, but I took this "test" 4 years ago.
On #9 the top row doesn’t add up to 15.
The bottom row also doesn’t add up to 15.The left vertical row doesn’t add up to 15. The right vertical row doesn’t add up to 15.
Javido That’s why there is no white line drawn through those rows.
QQ33 Oops I didn’t realise that.
I'm good at Maths 😁
I got 8/10 correct 😊
For the last one, let's take U0=3 for all positive integers n we have Un+1=3*Un+3. We have :
U1=3*Uo+3=3*3+3=9+3=12
U2=3*U1+3=3*12+3=36+3=39
U3=3*U2+3=3*39+3=117+3=120
So : U4=3*U3+3=3*120+3=360+3=363
you can learn multiply and square from my maths videos.
Riddle #10 can also be solved by another method
3+3² = 3 + 9 = 12
12+3³ = 12+27 = 39
39 + 3⁴ = 39 + 81 = 120
120 + 3^5 = 120 + 243 = 363
Exactly! I thought I was the only one😁
its actually 383
I solved the all problems, except 2nd and 7th
I got the answer in #10
3x3=9 9+3=12
12x3=36 36+3=39
39x3=117 117+3=120
120x3=360 360+3=363
I got 6 questions more than you did.
9:43 You cm also identify the answer is 2 by the patterns of the numbers.
Look closely at the lines:
Line 1. 6, 5, 4 (repeated decrementing)
Line 2. 9, 5, 1 (repeated subtracting by 4)
Line 3. 7, 5, 3 (repeated subtracting by 2)
So line 4 must be 8, 5, 2 (repeated subtracting by 3)
8 out 10
Darius Barnard I got 9 😁
Thats good congrats you are real smart
Darius Barnard I got 7
Missed #5 got the rest
10/10 ezzzz
I Am able to solve all of the puzzle easily
I GOT ALL OF THEM RIGHT!!
I guess I really am very good at math! 😂😂😂😂😂😂😂😂
Edit:(I did some of them a different way but still got the same answer like #3 you can just double it)
Nope #09 is not correct:
Because "6+8+3=15" is not correct and "7+2+4=15" is also incorrect!!
We all guessed 2 because it was the only number missing so it must be something like the first riddle
10:20 I did (3+1)*3=12. Same thing works for the other numbers. (120+1)*3=363.
For 9, I also realize that 6 and 4 had the same difference with 5, as did 3 and 7. So I guess the secret number must be three less than 5, since 8 is equal to three more. 5-3=2
Can we talk about the fact that these riddle have nothing to do with math? It's luck;you just have to find the right pattern.
5 was the average in all directions which is a simpler interpretation of what you were saying and what he said.
Ikr
For number 4 I did it different. I subtracted the bottle numbers and then multiplied the answer by 2.
#09 6+8+3 and 7+2+4 do not equal 15, so do not mark them.
9/10 solved
They weren't connected with a line. Only those that were connected needed to be equal to 15.
do the fist and last values of each line divided by 2 they must always equal 5 and also im pretty sure he didnt bother to make up his own problems , he clearly just went backwards from the answer to find the solution and also its applicable to the numbers in a line
If he would have made a magic square then it would be better
I used different methods but still got the correct answer on #8 and #4. On #8, this is what I saw and used, initially, for the steps:
A) Multiply first by whatever the the sum of second+1 is
B) Add the original second to the result and you get the third.
Went back afterwards and figured that In algebra, with X, Y, and Z to represent the first, second, and third numbers, respectively. So in all three given cases you have:
x y
z
Now, using my method of multiplying x by y+1, then adding y, we get:
x(y+1) + y = z
This works for all of them, try it.
6(4+1) + 4 = 34 (because 6x5 = 30, then add 4 for 34)
8(5+1) + 5 = 53 (8x6 is 48, add 5 for 53)
11(3+1) + 3 =47 (11x4 is 44, add 3 for 47)
9(2+1) + 2 = 29 (9x3 is 27, 27+2 is 29)
I was shocked when their method was different at first, but then I realized, funnily enough, this formula of mine is merely the simplified form of the formula they have given you in the video. They say multiply first and second, then add the sum of the first and the second to the product to get the third. Using X for first, Y for second, and Z for third again, you get:
xy + x + y = z
For instance, as they said, 6x4 + 6 + 4 = 34. (Since 6x4 is 24, 6+4 is 10, and 24+10 = 34)
Of course, xy+x is the same thing as x(y+1). Which is why both formulas work.
Furthermore, now that I look at it I realize that you could also solve this problem a third way, by creating the formula y(x+1) + x = z. Since y(x+1) gives you xy+y it's easy to see where this comes from. That would mean you'd multiply the second number by the sum of the first and 1, and then add the first. So to use the example number sequence of 6, 4, and 34, we get:
4(6+1) + 6 = 34
Which holds true since 4x7 is 28, and 28+6 is 34. Pretty cool how that all works out the same! (if you're a math geek like me). Try it with the other two sets yourself if you don't believe me.
Now for #4. There are at least five ways to do this, I found. Initially, I actually started with the largest number (the one in the lower right hand corner of the triangle), subtracted the number on the lower left, then added the top number. It worked on all of them too and got me to 10 and 4 for the missing numbers. In Algebra, that would go like this, using x for the number outside the triangle, a for the top number, b for the lower left hand corner, and c for the lower right hand corner. Or:
x
a
b c
So:
c-b+a=x
Remember you have to go left to right with addition and subtraction for this one to work. Again, this formula works for all of them. Try it.
7-4+3 = 6 (7-4 is 3, 3+3 is 6)
9- 4+5 = 10 (9-4 is 5, 5+5 is 10)
4-2+2= 4 (4-2 is 2, 2+2 is 4)
Hm. That's not what they said to do to get the answer, though. They said to take the top number (a), add the lower right hand number (c), and subtract the lower left hand number (b), For instance, 3+7-4=6. So their formula would be:
a+c-b=x
Let's see if you can get this formula from mine. If you take my formula of c-b+a=x and subtract a from both sides, we have c-b=x-a. Now let's simply add a back to both sides and viola! You get their formula. a+c-b=x. Easy peasy.
I promised there were three other ways to solve #4. One is very complicated and I doubt if anyone would see it just by looking at the numbers since it involves negative integers. The other two - especially the last - were so easy I was kicking myself for having gone to all this trouble, after finding it. So, first up, the complex solution.
If we do another rearranging of the letters we can get them in alphabetical order and have a-b+c=x. This will work for all three groups as well but it involves negatives in the first of the three cases. Again, always go left to right to make it work. Examples:
3-4+7 =6 (3-4 is (-1), 7+(-1) is 7-1, 7-1 is 6)
5-4+9=10 (5-4 is 1, 9+1 is 10)
2-2+4=4 (2-2 is 0, 0+4 is 4)
Now wait a minute. Something sneaky is hidden here. Because it's human nature to want to use all three given numbers, we miss two hidden solutions that don't use all the numbers but are much easier than what we've been running around trying to do. And they also can be explained algebraically. Let's take my formula of c-b+a = x again and look hard at the numbers involved in it.
7-4+3 = 6 (7-4 is 3, 3+3 is 6)
9- 4+5 = 10 (9-4 is 5, 5+5 is 10)
4-2+2= 4 (4-2 is 2, 2+2 is 4)
Did you catch it? C-b and a are the same number! 7-4 is 3, but a is also 3. 9-4 is 5, but a is also 5. And so on. Therefore:
c-b=a
So inserting this into our original formula, we can look at this two ways. The first involves getting rid of A altogether and replacing it with the (c-b) it's equal to:
(c-b) + (c-b)=x
2(c-b) =x
Or, basically, subtract b from c and double the difference. This works in all three cases.
2(7-4) =6
2(9-4) = 10
2 (4-2) = 4
That's a LOT easier, but the fifth method will make you kick yourself, as I did myself, when you realized all of this could have been bypassed by noting on the first triangle that twice 3 is 6. Or, algebraically:
2a=x
That's right, you don't have to use b or c at all. You can simply get the correct answers by knowing your 2 times table.
2x3=6
2x5=10
2x2=4
How do you get that from our original formula of c-b+a=x? Easy peasy. Remember I said c-b = a? I just do this:
c-b=a, (c-b)+a=x, a+a=x, 2a=x
If you read all the way to the end of this you're probably kicking yourself right now, and also you're probably a math geek/pattern lover like me. God Bless! :-)
in riddle#9 i just counted 1-9 and 2 is literally the missing number, i got it all correctly and timely though
#10- the difference between 3 and 12 is 9. Multiply that with original 3 and get 27. Add that to 12 and you get 39. Take previous difference 27 x 3= 81 then add 39=120. Take 81x3+120=363. I'm terrible at math but can see patterns.
For the last riddle you could have done the nth term which would be the difference between 3 and 12 which is 9 and the difference between 12 and 39 which is 27 and the difference between 39 and 130 is 81 and the numbers are 9,27 and 81 and if you, x 9 by 3 it gives 27 and if you x 27 by 3 it gives 81 so you have to do 81 x 3 which gives 243 and you just have to add 243 to 120 and it gives 363
This is how I got to the answer.
For the last puzzle just add powers of 3 to the numbers 3+3^2=12 , 12+3^3=39 , 39+3^4=120 , 120+3^5=363
I’m terrible at maths
#05)50 +40=90 therefore 20 +30+10=60+30=90
well, that was easy. The only one I personally had some problems with was the one with the triangles as there wasn't enough information to validate a possible answer. In the end I simply went with doubling the inner top number - which is effectively the same as the answer provided in the video.
#8 (alternative solution)
It could also be
6x5 + 4 = 34
8x6 + 5 = 48
11x4 + 3 = 47
9x3 + 2 = 29
For #10 (alternative solution)
Simply add 1 then multiply it by 3
(3+1) x 3= 12
(12+1) x 3 = 39
(39+1) x 3 = 120
(120+1) x 3= 363
this is logic not math
Yeah
Ioan-Sebastian Sofiean Math is logic
Yaa thts right
Math require logic B R U H
Logic is a branch of mathematics. Math is not just about counting and numbers.
#04 it also could be multiply all the numbers each triangule and divide the add of all of them
For example: (3*4*7)÷(3+4+7)= 6
And the others will be: (2*2*4)÷(2+2+4)= 2
And
(5*4*9)÷(5+4+9)= 10
For the nineth question I just use the 1st question trick and get the ans🤣🤣
I am also
Same
I got 9/10 riddles 😂😂
BRIGHT side just reminded me HOW IT FEELS TO SCRATCH MY HEAD.
1. 0 or 16
2. 2
3. 52
4. So many possibilities... (4-3)-(7-3)+(7-4)=6 -> (4-2)-(2-2)+(4-2)=4 and (9-5)-(5-4)+(9-4)=8
Could also be 4+7-2=3+6 -> 2+4-2 = 2+2 and 4+9-2=5+6.
5. 30
6. 11: 18*4/2=36, 15*6/2=45 -> 8*11/2=44
7. 6
8. 9+2+9*2 = 29.
9. 2. Opposite numbers equal 10.
10. 3^1=3 , 3^1+3²=12, 3^1+3²+3³=39, 3^1+3²+3³+3^4=120 -> 3^1+3²+3³+3^4+3^5=363.
1 solved 8 except 1 and 2 and i used my own trick in last 10 ques of 3,12,39,120 my trick is 3×4=12,after 12 next no. is 13 so 13×3=39,after 39 next no is 40, 40×3=120,after 120 its 121 121×3=363
Prajwal Gond excellent approach bro
You actually used the same formula, just not distributed. (x + 1) * 3 is equivalent to 3x + 3.
Ritik Tanwar thnx bro
Okk bro np
It's actually +1 x3
In #10 I got
3+3squared=12
12+5squared=39
39+9squared=120
120+15squared=345
So the number that gets squared is getting exponentially bigger by 2
Practice practice practice...
Then get tired and sleep😅
And when your dreaming remember to practice while your crush is fighting a teddy bear in a tree house fight club.
Brandon Austin Chandler lol
Aditya Nimgade lol
Aditya Nimgade Totally
1) 16
2) 2
3) 52
4) 4 and 10
5) 30
6) 11
7) Don't know
8) 11
9) 2 (6-5+4 = 5, 9-5+1 = 5, etc so 8-5+2 = 5)
10) 363
I missed #7 and #8. I'm only 80% genius.
Q1 Dosen't Make Sense!
Wow!!!
How Did I... Didn't Know
I Got Tricked In April Fools...
Really.?
Riddle 9: 8 hits 5 and 3 is the out put that can can be seen on the top right (8-5=3), 6-5=1 (the answer cam be seen on the right), 9-5=4 (bottom right), and Finally 7-5=2 (buttom)
I FIGURED OUT THE THUMBNAIL QUESTION!!!!!! IT WAS SOOOOO EASY (for me)
Penny Pennywise's daughter yea it was super simple
Yeahh buddy...it was probably the most eye catching and the easiest question in the list
Well whats the answer then its 2 not 1 if ur thinking 1 sorry sister not the answer
I got 5 out of 10 correct. Number ten can also be solved by adding 1 to the number being multiplied by 3.
12+1=13×3=39
39+1=40×3=120
120+1=121×3=363
for number 4, I multiplied the top by 2 and still got the same answers.
For number 10, I thought this: 3+1=4, 4*3=12. Adding 1 to the number and then multiplying it by 3. 12+1=13; 13*3=39. 39+1=40; 40*3=120. 120+1=121; 121*3=363
THUMBNAIL ANSWER;- 3X3+3=12, 12x3+3=39,39x3+3=120,
120x3+3=363.
For riddle no. 4, other logical answer could be 2 on the vortex of 2nd triangle and 6 on the vortex of 3rd triangle. First multiply the three digits in each triangle and then find their sum. Divide the product with the sum. The result is the number on the vortex of that triangle
👍🏼👌🏻👍🏼👌🏻Your Channel is very entertaining & Good, Knowledgebel👍🏼🙏🏻I Always Enjoy 😊. PRACTICE❗️PRACTICE
God bless you From 🇩🇰
(5.3.14)
I watched a video from Slavo,he said Bright Side is bad,but he's wrong. It's the BEST!
Lol no
9/10
In riddle 6 we can apply another logic..
2,6,8
36,45,54
18,15,12
So 12 should also be accepted.
If it was multiple choice the if option 12 was missing understandable but its not multiple choice so every answer with a reasonable logic should be accepted
I don't have to do this test because I already know I am terrible at maths.
Kakashi Hatake you’re smart
Kakashi Hatake not always
4:17
Me being lazy and just did this:
2x2=4
5x2=10
It's correct tho
In the 4th riddle, I thought that multiplying the number below the question mark with 2 is the answer, and what a coinsidence, it is😜😜😜
Shubham Khamaru me too! I commented that a minute ago! I was looking for someone who agreed with me and found you😂
is this an example of recreational provblem using math?
I got all the CORRECT ANSWERS
HOW BRAINY IS ME😎
I did not count how many I got right - but it was most of them. However, I discovered one thing - I almost always arrived at the right answer by a method other than the one given. Therefore, it means that there is definitely more than one way of arriving at the correct answer.
when I first saw the title I said _"bad"_ anyone else?
Number 10: 39(3rd number)devided by 3(1st number)=13;120:12=10;with this logic the missing number is 39x7(why 7?because 13-10=3 and to keep this difference between the factors we have to do 10-3,that's equal to 7),and 39x7=273. And with this I'm not saying that I think correctly and who made this video does not, I'm just saying that I think you should consider this way to solve it. If you got to this point thank you for your attention and tell me what you think
thumbnail: answer 363
Puzzle 4 can be solved with numerous other answers because there is only one completed series. The question in puzzle 4 does not limit the answer in any way.
In puzzle 2, you needn't use the word "rhombus" because the figures are squares. They are set on point, but still are squares.
1st
Cool
In Riddle 9, @ 9:05,
First Diagonally, 6 -5 =1, and 5-4 = 1.
Again, diagonally, 3+2 = 5, and 5+2 = 7.
In middle, 9-4 = 5, 5-4 = 1.
This way, 8-5 = 3. So, 5-3 = 2.
Thus, 2 should be the answer.
52nd viewer
For 8, I multiplied the first number (top left) by the right number (top right) added by 1 then added the right number again to get the solution. So basically L x (R+1) + R, an example is 6 x (4 + 1) + 4 = 34, or 8 x (5 + 1) + 5 = 53.
Number 9 was pretty easy, you can either look at it and tell 2 is missing, or add the top and bottom numbers, then divided by 2 to get 5. This can be done for the other directions like diagonal or horizontal.
Hi Mr Bright Side 3 12 39 120 1st 3X12=36+3=39 2nd 3X39=117+3=120 3rd 3X120=360+3=360+3=363 Ans is 363.
Another possibility:
1st. triangle: 7-3=4+2=6
2nd. triangle: 4-24-2=2+2=4
3rd triangle: 9-5=4+2=6
I got number 4 correct, although for the wrong reason. I saw that 7 - 3 = 4 , 4 - 2 = 2 , 9 - 4 = 5 , so basically the bottom numbers always equaled the top numbers. And since there was a 6 over the 3 I came to the conclusion that the top numbers of each triangle double every time.
Answer this:
You have 10 boxes with rabbits inside. The number of rabbits inside each box depends on the number of their box. They also give birth to the same number each as the box number. The boxes are numbered 1-10. How many rabbits are there in total?
The equation could either be:n+(n×n) or n+(n^2). So,1+(1*1)+2+(2*2)+3+(3*3)+4+(4*4)+5+(5*5)+6+(6*6)+7+(7*7)+8+(8*8)+9+(9*9)+10+(10*10). Also,try n+(n^2) or n×(n+1)
I actually got 7/10 correct
4:22 I get 3 and 8 because in the correct triangle the answer is (4+3=7)-1=6 so (2+2=4)-1=3 and (4+5=9)-1=8
I got 4 out 10 but i was thinking more than 15 seconds. The true mathematicians need more time to solve any case;)
#1 has a pattern. Column 2 = one's digit from columns 3 & 4 added together. Missing info doesn't mean not a duplicate. #2 didn't follow that logic. And I was never told I had to use the first column. The missing number is 3.
I got 6 from 10. Number 10 is wrong. 2 scenarios. One is that you added one the multiplied 3(which I did to get 363). That scenario suggests keeping 363 as the correct answer. The second one which uses your pattern would end up as 369 not 363. 123 multiplied by 3 is 369
This is just for people who want to say they are good at maths through puzzles that are only vaguely related.
For you geniuses then, whats n^x^y only one exponent, or ax+by relative to c
Last one 10:30: 3 times 4*3=12, then 3*13=39,3*40=120, there's a hidden pattern as well all these answers (3,4,39) if you add 1 to all of them gives us the exact multiplying numbers (12+1=13, 39+1=40...) as you can see they all gets added by 1 therefore back to first scenario 3(3+1), 3(12+1)=36, 3(120+1)=363
I got 7 correct in maths. I hope you can do a video of more difficult maths riddles
The last one I solved but not in the way you said , I solved it as
3 × 4 = 12
12+1 = 13, 13×3 = 39
39+1 = 40, 40×3 = 120
120+1 = 121, 121×3 = 363
wow in #09 6+8+3=15 and also 7+2+4=15 what a great addition👏
The correct logic is that 5is the arithmetic mean of any row, column or diagonal and still the answer is 2 .
For No.10
I went like:
3*3) + 3 = 12
12*3) + 3 = 39
39*3) + 3 = 120
120*3) + 3 = 363
#9 u can add opposite sides(line connected) and then divide by 2 to get 5 so the answer would be 2--> (8+2)÷2=5
In no.9 i don't think that 6+8+3 equals 15
Yeah! Right me too!
I was very close on the thumbnail question 3 12 39 120 my guess was 390 my logic was that 3 is 1 + 2 so 12 12 is 3 + 9 so 39 although I guess that's where my logic fell apart I was just assuming it would continue to scale like that basically however I was still pretty close because 363 is 3 + 6 + 3 which is 12
In question no. 4 there is another pattern for getting 6, 4, 10. just multiply the top number by 2. 3*2=6, 2*2=4, 5*2=10
363 is the next number
4:04 For this question I did this instead:
6 = (7*2)- (4*2)
and then 4*2 - 2*2 = 8 - 4 = 4
and then 9*2 - 4*2 = 18 - 8 = 10
In #4, the bottom left number + the top number in the triangles = the bottom right number.
In #5, both 20 + 30 and 40 + 10 = the top number, 50.
For the last question, I calculated in another way.
3 12 39 120
3 + 1x3 = 12
12 + 1x3 = 39
120 + 1x3 = 363
I think in #10 there’s another answer calculating the differences between numbers:
12-3=9
39-12=27
120-39=81
If you see is the same if you write:
3^2=9
3^3=27
3^4=81
3^5=243
3^6=729
.
.
.
3^x=to infinite
So if we return to the original formula with the differences it’s supposed...
3 , 12 , 39 , 120 , x
\/. \/. \/. \/
9. 27. 81. 243
So, x = 120 + difference
= 120 + 243
= 363
And this is another way to solve it
09) 9 is left and 1 is right and 9+1=10.And 3 and 7 are opposite and they both make 10.Same goes to 6 and 4. 5 is in the middle (5+5=10) and 8 is on top and the bottom is......2!
Look 8:40
Last qustion
12-3=9=3*3
39-12=27=3*9
120-39=81=3*27
Answer
3*81=243
Add 120+243=363
3,12,39,120,363
1. In the grid
2. Rhombuses
3. Doubles
4. The Three Triangles
5. 90 In The Middle
6. Arrows
7. Where is the question mark?
8. Hopstotch pieces
9. Sum is 15
10. Neeeeeeeeeeeeeext!
For #06 number 11 can be the answer for another reason:
Multiply the number on the top and number on the bottom and you get the doubled middle number. It works for every given example
riddle #9 another solution
Numbers 1-9 ( 2 was missing)
or use the line
6-5-4 ( 1 interval)
3-5-7 (2 interval)
8-5- ? (3 interval) so answer is 2
9-5-1 (4 interval)