It base on the you use the spectrum scan by photon different imagine the distance as small as 3.3×10^-43 in an in of cc'd array then you can enlarge it to the able to see even 1×10^-10 m from a distance l /d= sine 45 and d = c × 2t = (64600 km/ s ) ×2t
100... since it is 10m resolution. A 100*100 m2 football ground can be divided into 10 rows and columns of 10m length. So 10*10 = 100 pixels will be the answer.
Thank you very much, from South Africa 💯🌍🤗
Great to see you here sir!! :) One of the best profs in Xaviers !
Thank you sir. Sending love from Sri Lanka
Great! Thank you for this clear explanation.
thanks you master from dominican republic
simple, clear explanation.
Clean and clear explanation, thankyou very much sir
Crystal clear knowledge ✌️.
very good Sir... so pleased by your way of explaining
Thankyou so much professor, please give insights also on spectral and radiometric resolution
th-cam.com/video/61jLqkITogk/w-d-xo.html
Very nice explanation sir ... thank you
It's very simple and clear👏
Please continue uploading videos of thisss
that was best description
nice and clear..thank you sir!
Thank you sir, wonderful explanation
Thank you. It's clear.
Very clearly explained.
Thank you
Really great video!
It base on the you use the spectrum scan by photon different imagine the distance as small as 3.3×10^-43 in an in of cc'd array then you can enlarge it to the able to see even 1×10^-10 m from a distance l /d= sine 45 and d = c × 2t = (64600 km/ s ) ×2t
i did not understand how a can you see a field wild big if your remote sensor is 10 meter above the ground
GOD BLESS You
Thank you for this information sir
Thanks
thank you sm sir,this helped a lot
Thank you sir
Awesomeness.
Thank uu sir
10 pixels or hundred? 1:27
100... since it is 10m resolution. A 100*100 m2 football ground can be divided into 10 rows and columns of 10m length. So 10*10 = 100 pixels will be the answer.
@@mandeepashiya2229 thank you