3:36 is the answer 7ma^2/75 ? As the MI of any axis passing through center of square = ma²/12 and i took the given axis as 3y=4x and it's distance from centre (a/2,a/2) = a/10 So final MI = ma²/12 + ma²/100= 7ma²/75
I have not seen anyone take as much effort as you do for each and every upload. It is truly impressive. Thank you for showing us the intricacies and beauty of physics instead of trying to make it into an 'easy' washed-down version, compressing information to be consumed in one shot.
Sir in the challenge that u posted is it true that the orientation of the ring will also change as it rotates if so then it will also contribute to the angular momentum
For the last q, Is the answer 7ma^2/75? I took a big square of side 2a by reproducing squares of side a such that the given axis passes through the centre of the big constructed square. Is the approach correct?
sir in your video of rolling of charged ring in magnetic field you just considered lorentz force dqvB due to just velocity which it has due to centre of mass but sir due to its wr velocity w r t centre of mass also lorentz force should act but you did not consider that why sir? sorry i am posting here th-cam.com/video/QlAJi4qeQ1I/w-d-xo.html this video
@@PHYSICSSIRJEE sir i read that (i am replying from other account) sir but w r t CM wr to velocity hai hi to uspe bhi to lorentz force dqwrB lagega hi na vo yatharth gupta ne vo mvr add kyu nahi kiya vo puccha raha tha vo to abvious hai coz tourque apan ne w r t CM nikaala tha
@@PHYSICSSIRJEE sir i read that sir but w r t CM wr to velocity hai hi to uspe bhi to lorentz force dqwrB lagega hi na vo yatharth gupta ne vo mvr add kyu nahi kiya vo puccha raha tha vo to abvious hai coz tourque apan ne w r t CM nikaala tha sir plz clear my doubt i am still confused 🙏🙏
@@dishakayande3997 it would be good if you can post the comment below that video with the timestamp of your doubt pointing clearly in which step the doubt is there👍
Ans is 7/75 Ma^2? Constructed axis passing through CM, parallel to given axis, say axis A1. MOI about A1 = 1/12 Ma^2. Then parallel axis to reach required axis
Sir in the year 2020 I have passed my class 12th as a medical student with additional subject as mathematics but due to some reason I was not able to pass my maths and got compartment .Now I will be writing maths paper in 2021 and I will also give jee main (march).Sir please guide me that should I write class 12 th passed or appearing in the jee form .Sir please guide me 🙏🙏🙏🙏
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Best physics teacher in india for jee 😍😍
3:36 is the answer 7ma^2/75 ?
As the MI of any axis passing through center of square = ma²/12 and i took the given axis as 3y=4x and it's distance from centre (a/2,a/2) = a/10
So final MI = ma²/12 + ma²/100= 7ma²/75
Amazing sir please continue we need you ❤❤❤❤
What a beautiful representation in 3D sir. Your videos are always special. ❤️❤️
I have not seen anyone take as much effort as you do for each and every upload. It is truly impressive. Thank you for showing us the intricacies and beauty of physics instead of trying to make it into an 'easy' washed-down version, compressing information to be consumed in one shot.
Amazing explaination guruji
Thanks sir!!☺️👍👍
Fantastic explanation
Thank you sir 🙌🙌
Certainly it is one of the fast food that is harmless
Awesome
Thank you sirji☺ ❤
Tysm sir....
Thanks 😋😃
Thnk u sir...
Thank you very much sir
Thanks sir
Thanks sir☺️
thanku guruji
Awesome video 🔥sir❤️👍
Thank you sir 🙏😊
Sir in the challenge that u posted is it true that the orientation of the ring will also change as it rotates if so then it will also contribute to the angular momentum
Ring has only one spin axis in that Problem
nice question👍. 3:50 i am getting the answer 7ma^2/75. Am i correct?
(revised 10/1/2022)
Sir.. What is the answer of question you posted(about angular momentum of the system of bicycle wheel and rod)??
The answer posted by students below the post is wrong.
Sir.. Then what is its answer?? Is it 6?
@@PHYSICSSIRJEE Sir I did it it is 7. I did by principal axes
@@PHYSICSSIRJEE Sir I did it it is 7. I did by principal axes
For the last q, Is the answer 7ma^2/75? I took a big square of side 2a by reproducing squares of side a such that the given axis passes through the centre of the big constructed square. Is the approach correct?
Nicely done 👍✅☺️
Then what is the moment of inertia about center of mass
Use parallel axes theorem as mentioned in the video
@@PHYSICSSIRJEE thank u sir
Sir can u solve fiit jee aits papers on your channel plz sir till jee advanced
I will include them in AITS select series 👍
🥺🙏
Sir daily upload nhi krte aap 😢
Yes . It's sad . I can understand 😐
Plz come to unacademy
Sir I am getting the answer aa 14ma^2/75 ...is it correct
75 is correct , I don't remember the numerator. Please kindly wait for my Solution
23/300ma² ?
My answer is different. I need to check my Calculation 😉
7ma²/75 for square lamina ?
@janardhan sir
OP sir
sir in your video of rolling of charged ring in magnetic field you just considered lorentz force dqvB due to just velocity which it has due to centre of mass but sir due to its wr velocity w r t centre of mass also lorentz force should act but you did not consider that why sir? sorry i am posting here th-cam.com/video/QlAJi4qeQ1I/w-d-xo.html this video
Please read the response to "yatharth gupta's comment" below that video
@@PHYSICSSIRJEE sir i read that (i am replying from other account) sir but w r t CM wr to velocity hai hi to uspe bhi to lorentz force dqwrB lagega hi na vo yatharth gupta ne vo mvr add kyu nahi kiya vo puccha raha tha vo to abvious hai coz tourque apan ne w r t CM nikaala tha
@@PHYSICSSIRJEE sir i read that sir but w r t CM wr to velocity hai hi to uspe bhi to lorentz force dqwrB lagega hi na vo yatharth gupta ne vo mvr add kyu nahi kiya vo puccha raha tha vo to abvious hai coz tourque apan ne w r t CM nikaala tha sir plz clear my doubt i am still confused 🙏🙏
@@dishakayande3997 it would be good if you can post the comment below that video with the timestamp of your doubt pointing clearly in which step the doubt is there👍
@@PHYSICSSIRJEE sir i posted plz check🙏
Ans is 7/75 Ma^2? Constructed axis passing through CM, parallel to given axis, say axis A1. MOI about A1 = 1/12 Ma^2. Then parallel axis to reach required axis
Nice👌👏
Op
Sir in the year 2020 I have passed my class 12th as a medical student with additional subject as mathematics but due to some reason I was not able to pass my maths and got compartment .Now I will be writing maths paper in 2021 and I will also give jee main (march).Sir please guide me that should I write class 12 th passed or appearing in the jee form .Sir please guide me 🙏🙏🙏🙏