C_114 Unions in C | C Language Tutorials
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if we dont initialize c value then the last entered value char b as 97.
this means the combined memory allocation for union will store the last entered value 97 which int a also can access
so the output will be
a value is 97
b value is a
Start from 2:24
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11:39 It should be struct demo *ptr = &s
17:07
#include
union abc
{
int a;char b; float c;
};
int main()
{
union abc u;
union abc *ptr=&u;
u.a=1;
u.b=97;
printf("a=%d",ptr->a);
printf("
b=%c",ptr->b);
return 0;
}
OUTPUT:
a=97
b=a
Mam pls also cover enum and malloc,calloc,realloc inC before going on file handling pls mam plssss 🥺
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Mam explain structure padding and structure packing
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12bytes allocated in struct mam, because there is no #pragma pack(1).
At 6.19 memory will be 12 bytes not 9 bytes as structure padding. If char is last var of structure then 9 bytes will be allocated
Structure padding means!?
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The answer to your assignment is
--For u.a is some garbage value,and
--for u.b is 97;
it gives lowercase a as output because 97 is its ascii value and u declared b as charecter
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ma'am it will print a as the ASCII value of 97 is a
Madam int size is 2bytes
Nice explanation
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Please teach me this program program.
Write a C function to evaluate the series
sin(x)= x - (x**3 / 3!)+(x**5 / 5!) - (x**7 / 7!) + .... to five significant digits.
a value will become the b values if we enter any integers(1 byte integers) b will be any garbage value
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No mam size of the structure is not directly calculated. Its wrong data padding will there in structure for processors optimization and also how you are declearing.
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a= garbage value, b = 97.(last value)
Bro.... That's a char data type but the initialized value is of int
Mam Please make a tutorial on "Enumeration"
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Mam int is 2 byte of memory location.
in some compilers its 4bytes
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mam a small correction at 9;15 - u.a is not garbage value it is 9.2
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Size of the structure is 12 not 9
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print a= garvag value and b = 97
No it prints a=97 and b=a.
Tmare padhaane ke tarikhe se pyaar hogya h mjhe or tumse bhi
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Mam we can use methametical expressions in union
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1st it will print a=97 and b = garbage value or Nothing ........!!
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In the struct memory allocation, why did you not take the padding into account. I am a bit confused.
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