12:10. Checking 1 and 2 a transition. 12:39. Checking 1 and 2 b transition. 13:00. Checking 1 and 4 a transition. 13:12. Checking 1 and 4 b transition. 13:28. Checking 2 and 4 a transition. 13:40. Checking 2 and 4 b transition. 14:10. Checking 1 and 6 a transition. 14:18. Checking 1 and 6 b transition. 14:28. Checking 2 and 6 a transition. 14:34. Checking 2 and 6 b transition. 14:43. Checking 4 and 6 a transition. 14:49. Checking 4 and 6 b transition. 14:58. Going through chart again, checking all empty spaces. 15:04. Checking 2 and 4 a transition. 15:09. Checking 2 and 4 b transition. 15:18. Checking 4 and 6 a transition. Checking 4 and 6 b transition is unnecessary; the a transition is already marked as distinguishable. Algorithm is now complete, and it turns out this is the minimized DFA anyways. XD
My teacher didn't really explain why the equivalent states work, I had a slight grasp of why the algorithm works but it never clicks. Thanks to this explation I can fully understand it, thank you sir
This took me a while too - 3 and 5 are defined as final states when he made the state machine (he just didn't say it out loud). They are indicated by the double circle symbols.
The state merging step, using the complete lower triangular matrix involves finding cycles? Thank you /so/much/ for working through these examples! You sir, are going to have a large audience in time. I'm going to try working through some larger examples to discover the groupings needed at the end.
thanks for saving my life. i found it very difficult to motivate myself to get to know this subject, as it is quite theoretical and seems quite useless at first.
Best CS channel on youtube.
this is really well explained. i cant thank enough
12:10. Checking 1 and 2 a transition.
12:39. Checking 1 and 2 b transition.
13:00. Checking 1 and 4 a transition.
13:12. Checking 1 and 4 b transition.
13:28. Checking 2 and 4 a transition.
13:40. Checking 2 and 4 b transition.
14:10. Checking 1 and 6 a transition.
14:18. Checking 1 and 6 b transition.
14:28. Checking 2 and 6 a transition.
14:34. Checking 2 and 6 b transition.
14:43. Checking 4 and 6 a transition.
14:49. Checking 4 and 6 b transition.
14:58. Going through chart again, checking all empty spaces.
15:04. Checking 2 and 4 a transition.
15:09. Checking 2 and 4 b transition.
15:18. Checking 4 and 6 a transition.
Checking 4 and 6 b transition is unnecessary; the a transition is already marked as distinguishable.
Algorithm is now complete, and it turns out this is the minimized DFA anyways. XD
I have a very important quiz in just one hour
Thanks for this video
My teacher didn't really explain why the equivalent states work, I had a slight grasp of why the algorithm works but it never clicks. Thanks to this explation I can fully understand it, thank you sir
saved my homework assignment, thanks man
15:15, how come 2 and 4 are distinguished, they go to the same state on an a transition, and accepting on b?
Oh because the accepting states are distinguished
Extremely helpful video. Thanks for making it.
Thanks so much for this video! I was able to trace through the example and figure out how to the use the algorithm and the distinction table!
this would be whole lot easier if scientists back then didn't call "distinguishable"s "not indistinguishable"...
18:50 Why couldn't array[3, 5] be marked during the process?
This took me a while too - 3 and 5 are defined as final states when he made the state machine (he just didn't say it out loud). They are indicated by the double circle symbols.
Excelent and very helpful explanation, thank you very much.
Thank you sir. It was easy.
very helpful man thanks!
Thanks for the great explanation
The state merging step, using the complete lower triangular matrix involves finding cycles? Thank you /so/much/ for working through these examples! You sir, are going to have a large audience in time. I'm going to try working through some larger examples to discover the groupings needed at the end.
thanks for saving my life. i found it very difficult to motivate myself to get to know this subject, as it is quite theoretical and seems quite useless at first.
Thanks for the video!
You are a lifesaver
What does this have to do with the minimum circuit size problem?
Amazing!
Great video, thanks :)
🔥
Thanks a lot
This is the Myhill Nerode theorem