Buoyancy for Fluid Mechanics in 8 Minutes!

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  • เผยแพร่เมื่อ 2 พ.ย. 2024

ความคิดเห็น • 16

  • @xavierchen4162
    @xavierchen4162 3 ปีที่แล้ว +7

    Wow your drawings are great! Looking forward to more of these videos in the fluid mechanics series!

    • @avram131
      @avram131 2 ปีที่แล้ว +1

      do you know wich software he uses?

  • @sashikumarreddy9081
    @sashikumarreddy9081 ปีที่แล้ว +1

    you worth million subscribers sir. love from India. life saver for exams.

  • @Pain-95
    @Pain-95 2 ปีที่แล้ว

    I have watched all mechanics of material, statics, and fluid now i am at solid work thank you for your hard work. I wish there was thermodynamics and heat transfer series.

    • @LessBoringLectures
      @LessBoringLectures  2 ปีที่แล้ว +5

      Thermo will be coming this semester, and heat transfer right after that (summer time)!

    • @Pain-95
      @Pain-95 2 ปีที่แล้ว

      @@LessBoringLectures thank you sir. Appreciate you work

  • @IGJTHOMAS
    @IGJTHOMAS 2 ปีที่แล้ว

    These are amazing, cut the fat out and are straight to it. Looking forward to the example problems to come.

  • @97yezi
    @97yezi 3 ปีที่แล้ว

    I enjoy all your videos. Very helpful

  • @ryanfoster7320
    @ryanfoster7320 ปีที่แล้ว

    Amazing content. Thank you!

  • @LINDOMagnoDisoarcido-h3e
    @LINDOMagnoDisoarcido-h3e หลายเดือนก่อน

    Thanks sir

  • @rede_neural
    @rede_neural 2 ปีที่แล้ว

    If a body is submerged inside a liquid, why is it that its weight doesn't participate in the pressure equation?

    • @santipedreira
      @santipedreira 6 หลายเดือนก่อน

      It does, W=ρ.V.g

  • @Zar4thustr4
    @Zar4thustr4 2 ปีที่แล้ว +1

    I have an issue understanding the internal stresses in an object due to buoyancy - if I would put a long steel rod in water -> if it was thin and long enough would it buckle due to buoancy? If I think about this according to the Archimedes principle, it would clearly not, it is just as if the steel rod would have somewhat lower density, but no reason to buckle ... but if I use the piston force principle (where buoyancy is added as an external force B=Crosssection of the rod *p), the answer would be yes, the rod would be under compression at the bottom.
    So now one could just say: ok the piston force principle is just wrong ... but then it offers a good explanation of why there is no buoyancy force if e.g. a cylinder sits at the bottom of a water filled beaker (with no water between the lower area of the cylinder and the bottom of the beaker) ... so I can't just throw the piston force principle out of the window ... there is something I do not understand about the internal stresses caused by buoyancy ... can anyone point me to what it is?

    • @conraddiaz2274
      @conraddiaz2274 ปีที่แล้ว

      Hmmm. Your question seems valid -- Must admit I'm a bit confused right now! Thanks, lol :)

    • @Zar4thustr4
      @Zar4thustr4 ปีที่แล้ว

      @@conraddiaz2274 I found the answer in the meantime - google "Understanding of Buoyancy in Drill Pipe and Risers" by Morton Reve - in chapter 4 he shows a series of experiments which are fun to go through ...
      And then in chapter 7 he discusses the Bridgman experiment; which made it clear for me - > you have to view the piston force buoyancy in 3-D basically ... (in my original question the pressure on the side of the cylinder supports the rods stability) ... but in any case that paper is a good read ...
      It is really surprising how often I do not fully understand the things I considered "simple" during my studies ... : D

    • @conraddiaz2274
      @conraddiaz2274 ปีที่แล้ว +1

      @@Zar4thustr4 thank you so much, I'll look into it!
      Yes, me too, sometimes I do a double-take on some things.
      Take care.