Thank you very much, I spend so much time trying to understand our professor's crappy presentation. You are the first one to explain this stuff properly..
@@TaylorSparks Thank you professor for such a vivid explanation. I have one question which is confusing me. The maximum interplanar spacing will correspond to minimum value of h2 + k2+ l2? So it means it will be the plane having least integer sum?
@@waqasmuneer7951 Not necessarily!! That is only the case for the cubic system. In other systems the lattice parameters could make this untrue. For example, Consider tetragonal. The d spacing formula is 1/d^2=(h^2+k^2)/a^2+l^2/b^2. Here you see that depending on the values of a and b, it might not be right. For example, (001) will have a larger spacing than (100), even though these both have the same minimum value of h^2+k^2+l^2.
At 8:01 you said the lattice parameter was 0.329nm -- did you pick that because it was a3 or should we do some average of a1 a2 a3 to calculate atomic radius?
Thanks..Is metal oxide have FCC or BCC structure.. if so far, how we calculate a from planes and spacing. If along with a how will you interpret for b and c in different crystal structure like tetragonal or orthorhomobic. I this you have calculated keeping in view for cubic system..kindly tell about any calculation to calculate R, a and b, volume of lattice which made easy for metal oxides like tin oxide. Please specify
This video covers that ;) th-cam.com/video/Tsj63DQ4yY0/w-d-xo.html It has to do with the type of structure, how the atoms close pack together and where they touch in the structure.
hi taylor, I was given a question which asked for interplanar spacing in FCC Aluminum expected slip systems, wouldnt it just be the calculation for d110? as [110] is the slip direction in FCC due to highest linear density. hope you can reply, thank you so much!
@@TaylorSparks dang.. however, from William D Callister's 7th Ed textbook chapter 3 Problem 3.57, it asked us to calculate interplanar spacing for Aluminum (110) set of planes. so how do we know when to do calculations for d110 or d111? would it be only when it's specified?
I think that's exactly what I answer in this video. What exactly did you not understand? FCC versus BCC have different allowed hkl reflections so we went one by one and figured out which ones match the observed reflections.
@@TaylorSparks I think he is confused how you drew the conclusion as to what Miller indices are to be used for FCC and BCC. They should already be known for ease of operation.
At 6:27 you started with part B in your problem and you used a table with atomic Radii and Crystal structure to determine the metal. I searched atomic Radii of more metals and there are Emperical Atomic Radii and Metallic Atomic Radii ---> And you see with the table you provided at 6:27 I couldn't find accurate results as I found an element with a BCC structure and an atomic Radii of 0,1521nm and according to that table my best bet is Tantalum with a BCC structure and a atomic Radii of 0.1430nm, but I already used Tantalum in another example where I found the crystal structure BCC and an Atomic Radii of 0,1429nm. Source where I found the different types of atomic Radii ---> en.m.wikipedia.org/wiki/Atomic_radii_of_the_elements_(data_page)
I don't know how ,your plugging your numbers because you dont show it, I'm getting different results like .098357056 nm for the first value using 38.6., I used 38.6 degrees and I also, in case excel was treating 38.6 as radians did a conversion and my number are still way different. This is what I'm doing: .1542/(2sin(38.6)=dhkl =0.12358153785, I got it, you have to half the values because they are 2 theta,
@@TaylorSparks Thank you Mr. Sparks, I figured that out after I wrote to you, but I figured I'd leave the comment up in case someone else made the same error. I love your teaching style, thank you.
I'm not sure that I understand. The two theta values are given in the problem. Are you trying to say that in your problem you are starting with different two theta values?
Thank you very much, I spend so much time trying to understand our professor's crappy presentation. You are the first one to explain this stuff properly..
I'm so glad to hear it! Let me know if I can clarify other concepts. Also, like, subscribe, and share to help me grow my channel!
@@TaylorSparks Thank you professor for such a vivid explanation. I have one question which is confusing me. The maximum interplanar spacing will correspond to minimum value of h2 + k2+ l2? So it means it will be the plane having least integer sum?
@@waqasmuneer7951 Not necessarily!! That is only the case for the cubic system. In other systems the lattice parameters could make this untrue. For example, Consider tetragonal. The d spacing formula is 1/d^2=(h^2+k^2)/a^2+l^2/b^2. Here you see that depending on the values of a and b, it might not be right. For example, (001) will have a larger spacing than (100), even though these both have the same minimum value of h^2+k^2+l^2.
@@TaylorSparks pppp
Thank you taylor for explaining me this
Our professor is waste before you
You're the best, nice explanation
so glad to help!!
Thank you so much for this tutorial. I was stuck for a long time until found this to rescue.
Regards.
Glad to see your response.
Would this work same way for mixed metals? Let me know if I can reach out to you someway on this subject.
Great explanation🔥 i'm from sri Lanka.Thank you
explanation of which peak come first is good ! Thank You !!
I'm glad to help.
Thank you so much. You save my life!!
thansk for your great video!
Superb explanation
very very good, your presentation is clear and helpful, thank you!
super glad to help!
Great explanation
At 8:01 you said the lattice parameter was 0.329nm -- did you pick that because it was a3 or should we do some average of a1 a2 a3 to calculate atomic radius?
one of those videos that save your ass before an assignment
I gotchu covered ;)
Oh my god, me too 😅.
@@TaylorSparks thanks bro, we love and appreciate you.
@@SerweeFitness ha! Love it. Do me a favor and check out our podcast "Materialism" on itunes and leave us a review!
You are far better then my professor😍
Thank you!!
Beautiful!
!Taylor , thank you so much brother !!!!
thank you sir simply amazing!!!
Very happy to help!
Thank you!
thank you so much...this helped me a lot
thank you so much. you cleared it all up.
Glad to help!
sorry , but hoe you get the plane for FCC? I still wondering about it... please help
Thanks..Is metal oxide have FCC or BCC structure.. if so far, how we calculate a from planes and spacing. If along with a how will you interpret for b and c in different crystal structure like tetragonal or orthorhomobic. I this you have calculated keeping in view for cubic system..kindly tell about any calculation to calculate R, a and b, volume of lattice which made easy for metal oxides like tin oxide. Please specify
Prof how to approach if our structure is HCP or orthorhombic?
May I inquire which tables you are referring to get the atomic radius
Here is the table I use. It is compiled from Shannon and Prewitt's classic paper www.mrl.ucsb.edu/~seshadri/Periodic/index.html
Thank you so much. You've been very helpful
how can we learn peak order from a xrd graph ? how can we trust if no information about peak order about xrd graph ?
tq for this! but where did u get the miller indices plane value? where is it came from?
can you be more specific?
@@TaylorSparks its ok! Got it already hehehehe tqsm for replying!
sir how to calculate lattice parameter of composite film with different concentrations of doping
Thank you for this information
How to calculate Miller index in monoclinic system..like copper oxide
You can look up d spacing formula for monoclinic. It's pretty long.
how do you know that the long diagonal of the cube covers 4 times the radius of the atom?
This video covers that ;) th-cam.com/video/Tsj63DQ4yY0/w-d-xo.html
It has to do with the type of structure, how the atoms close pack together and where they touch in the structure.
Thank you, sir
hi taylor, I was given a question which asked for interplanar spacing in FCC Aluminum expected slip systems, wouldnt it just be the calculation for d110? as [110] is the slip direction in FCC due to highest linear density.
hope you can reply, thank you so much!
No. The slip direction is 110, but the slip plane is 111 so you need to calculate d_111
@@TaylorSparks dang.. however, from William D Callister's 7th Ed textbook chapter 3 Problem 3.57, it asked us to calculate interplanar spacing for Aluminum (110) set of planes. so how do we know when to do calculations for d110 or d111? would it be only when it's specified?
where do you get the values of BCC AND fcc pLANES
at about 2 minutes in I go through how to generate BCC and FCC planes.
how did u figure out the first three peaks (miller indices) for FCC and for BCC?
I think that's exactly what I answer in this video. What exactly did you not understand? FCC versus BCC have different allowed hkl reflections so we went one by one and figured out which ones match the observed reflections.
@@TaylorSparks I think he is confused how you drew the conclusion as to what Miller indices are to be used for FCC and BCC. They should already be known for ease of operation.
At 6:27 you started with part B in your problem and you used a table with atomic Radii and Crystal structure to determine the metal. I searched atomic Radii of more metals and there are Emperical Atomic Radii and Metallic Atomic Radii --->
And you see with the table you provided at 6:27 I couldn't find accurate results as I found an element with a BCC structure and an atomic Radii of 0,1521nm and according to that table my best bet is Tantalum with a BCC structure and a atomic Radii of 0.1430nm, but I already used Tantalum in another example where I found the crystal structure BCC and an Atomic Radii of 0,1429nm.
Source where I found the different types of atomic Radii --->
en.m.wikipedia.org/wiki/Atomic_radii_of_the_elements_(data_page)
Do you have a reference for I learn this xrd?
I like this book www.amazon.com/Microstructural-Characterization-Materials-David-Brandon/dp/0470027851
another really great book is pubs.rsc.org/en/content/ebook/978-0-85404-231-9. It has many chapters in much greater detail
I don't know how ,your plugging your numbers because you dont show it, I'm getting different results like .098357056 nm for the first value using 38.6., I used 38.6 degrees and I also, in case excel was treating 38.6 as radians did a conversion and my number are still way different. This is what I'm doing: .1542/(2sin(38.6)=dhkl =0.12358153785, I got it, you have to half the values because they are 2 theta,
Hi Stephen. The problem is that 38.6 degrees is the value of TWO theta, not theta. So you need to divide theta by two in your sin function.
@@TaylorSparks Thank you Mr. Sparks, I figured that out after I wrote to you, but I figured I'd leave the comment up in case someone else made the same error. I love your teaching style, thank you.
@@stephenrose1902 thanks man!!
@@stephenrose1902 your comment really helped me.
thanks for leaving it on..!
Sir I tried this process but I didn't get ans
I have 2 theta values of 44.3863 &98.3483
I'm not sure that I understand. The two theta values are given in the problem. Are you trying to say that in your problem you are starting with different two theta values?
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