☑️16 - Mesh Analysis with Current Sources (Supermesh) 2
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- เผยแพร่เมื่อ 19 ม.ค. 2023
- In this lesson, we shall learn how to solve circuits problem using mesh analysis considering circuits with current sources and discuss the concept of supermesh.
When a circuit has a current, the approach to solving such circuits using mesh analysis is quite different.
When the circuit has a current source there are two important cases you need to consider.
Case 1
When a current source exist in only one mesh, you simply set the mesh current equal to the value of the current source or its negative.
Case 2
When a current source exist between two or more meshes, we create a supermesh by eliminating the source current and any element is series with it.
00:00 - Example 2
Playlists on various Course
1. Applied Electricity
• APPLIED ELECTRICITY
2. Linear Algebra / Math 151
• LINEAR ALGEBRA
3. Basic Mechanics
• BASIC MECHANICS / STATICS
4. Calculus with Analysis / Calculus 1 / Math 152
• CALCULUS WITH ANALYSIS...
5. Differential Equations / Math 251
• DIFFERENTIAL EQUATIONS
6. Electric Circuit Theory / Circuit Design
• ELECTRIC CIRCUIT THEOR...
Make sure to watch till the end.
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Thank you.
thank you for easy understand.
You are most welcome. May God bless you for watching.
thank you so much🙏this was so helpful God bless you
Amen, thanks so much for watching.
Hi, can i ask at 5:11 why is the equation of V0=2(I1-I2) and not 2(I2-I1) since it is from mesh 2s persepctive?
The resistor 2 ohms, is between mesh 1 and 2, whose current has already been defined as (i1 - i2), hence to find the voltage vo, it's simply 2 times the current in it.
You are the best
thanks so so much
hi, for 3 equation, can i use cramers' rule instead of subsitution method?
You can use Cramer's rule to solve the system of equations you have.
please what book do you take your problems from?
Fundamentals of electric circuit, Alexander and Sadiku
Please, What if I want to use matrix?
That's great, you can ask well use matrix
I'm getting opposite answers. My 6 I is negative, 2i2 is positive and 4i3 is positive also and my voltage source is negative. For the first loop
I guess you are taking the anti-clockwise direction .
may i ask how do i do it if i don't do it with supermesh
The unfortunate thing is if you don't realize that there is a super mesh, your solution will be incorrect. So try to understand the super mesh concept. I know you will be fine with series of examples. Stay bless
@@SkanCityAcademy_SirJohn okay thank you so much
@17miah33 much welcome
Is i1=5 and i2=1 and i3=4 correct or not
No please, the right answers are
3.5, -0.5, and 2.5 for i1-3 respectively
I 1 = 4.5 can check it
Please double check, i2 = -0.5A.
And i1 = 4 + i2
Therefore i1 = 4 + (-0.5) = 3.5A.
Thanks
Please what if we have a circuit that has a current sources at the left and right of the circuit
If they are in different meshes, they will be equal to the mesh current assigned... Check out v15 to see if the example in there describes what you mean.
@@SkanCityAcademy_SirJohn Please can I get your number so I can send you the question via WhatsApp
The equation 3 should be i3=-3+i2
That is incorrect.
Sum of current entering the node is 3 + i2.
Sum of current leaving the node is i3
Hence
3 + i2 = i3
Horrible teachings
Can you explain how horrible this is?
And in your own mind, you think you are making sense??.
That you don't understand it doesn't make him a bad teacher... Rather you are the poor student