Please note that at time 33.09 I didn't solve the problem, now I am clearing a mistake, peak at 120 is due to the McLafferty rearrangement and fragment 120 undergoes further undergoes alpha cleavage to give base peak at 105 due to the formation of phenylacylium ion.
Sir but base peak might not be due to mc Lafferty rearrangement.. so how can we say that m/z=72 would be the base peak due to mc Lafferty...(csir net question explained at the end)
I can't understand the formation of M-28 peak from molecular ion, in what way molecular ion loss CO radical? I mean in what way alpha hydrogen rearrange? if it is possible plz explain it,
Please note that at time 33.09 I didn't solve the problem, now I am clearing a mistake, peak at 120 is due to the McLafferty rearrangement and fragment 120 undergoes further undergoes alpha cleavage to give base peak at 105 due to the formation of phenylacylium ion.
@@TETRAHEDRONCHEMISTRYCLASSES can the peak at 105 be directly due to alpha cleavage also? And is direct carbonyl removal possible or first the molecule breaks and then terminal carbonyl should leave?
At 8:35 How do we get to know which one will remove as a radical or as a cation ? Sometime you do homolytic clevage and sometime hetrolytic. Very very perplexed now
m/z 51 peak is due to the formation of cyclobutadiene cation C4H3+ cation, it is generally there in case of aromatic carbonyl compounds. PLEASE Share TETRAHEDRON CHEMISTRY CLASSES with your friends.
Best lecture
great way of explaining, thanks sir.
u r always great sir
Thank you very much for your effort sir...
Nice Sir 👍
Sir how 105 will be base peak in 33:09 question
Please note that at time 33.09 I didn't solve the problem, now I am clearing a mistake, peak at 120 is due to the McLafferty rearrangement and fragment 120 undergoes further undergoes alpha cleavage to give base peak at 105 due to the formation of phenylacylium ion.
What about the peak at 106 in the same molecule , how does it come? Is it carbene removal?
There are various peaks in the spectrum which are not easy to explain neither they are necessary specially if intensity is low.
@@TETRAHEDRONCHEMISTRYCLASSES thank you for your response sir. May I have your mail id for asking particular questions/ doubts sometimes?
Plz use my channel ID.
Sir but base peak might not be due to mc Lafferty rearrangement.. so how can we say that m/z=72 would be the base peak due to mc Lafferty...(csir net question explained at the end)
Generally given in the question, predicting base peak is difficult theoretically.
Sir can u please explain the fragmentation pattern of alcohols.
Sure Will be uploaded on Saturday evening
Thanks a lot sir
I can't understand the formation of M-28 peak from molecular ion, in what way molecular ion loss CO radical? I mean in what way alpha hydrogen rearrange? if it is possible plz explain it,
Plz mention time.
@@TETRAHEDRONCHEMISTRYCLASSES @ at 9:11
Not 105 it is 120 which is due to McLafferty rearrangement
Please note that at time 33.09 I didn't solve the problem, now I am clearing a mistake, peak at 120 is due to the McLafferty rearrangement and fragment 120 undergoes further undergoes alpha cleavage to give base peak at 105 due to the formation of phenylacylium ion.
@@TETRAHEDRONCHEMISTRYCLASSES ok thanks
@@TETRAHEDRONCHEMISTRYCLASSES can the peak at 105 be directly due to alpha cleavage also? And is direct carbonyl removal possible or first the molecule breaks and then terminal carbonyl should leave?
Straight removal of CO is not possible.
Sir which aromatic aldehyde show maclafferty rearrangement?
Please reply.
Nice video
Various aromatic aldehydess can show McLafferty rearrangement, you can see the possibility in meta meta ethyl benzaldehyde.
Nice lecture thank you
How to find Base peak?
Sry sir in got it... 👆
I'm got it
Thanku sir
At 8:35
How do we get to know which one will remove as a radical or as a cation ?
Sometime you do homolytic clevage and sometime hetrolytic. Very very perplexed now
Plz refer spectroscopy by Pavia Lampman & spectroscopy by Jagmohan & then let me know.
Sir how the peak m/z 51 is obtained in butyrophenone ?
m/z 51 peak is due to the formation of cyclobutadiene cation C4H3+ cation, it is generally there in case of aromatic carbonyl compounds.
PLEASE Share TETRAHEDRON CHEMISTRY CLASSES with your friends.
Thank you sir
With out help of spectrum
Ethers ko koi explain nai karta
Will explain ethers too, 3 din ruko
You talking too fast man
Strange, my subscribers says that they run my videos on 2X speed.
U going wrong somewhere or i think u r not able to explain clearly
Plz mention time.. at which you think explanation is wrong.
Sir how the peak m/z 55 value is obtained in pentanol?
Peak at m/z 55 is probably due to the loss of methyl radical from m/z 70 (70-55=15). Reference: Silverstein.