Sir.. in case of positive bending moment you didn't consider point load 100kn ..only you are consider horizontal and vertical reactions..please clarify my doubt sir..
@@naidurongali8732 You have to check which vertical reaction is high. You have to make a section on the half where reaction is high. Then find the distance and moment
For finding y we can also use Y=(√R^2 - X^2)-R+H
Please make more video on this topic..
Sir also explain semi circular arch with udl
Thanks sir for making this video ,it helps me a lot
Thnku so much sir
Sir.. in case of positive bending moment you didn't consider point load 100kn ..only you are consider horizontal and vertical reactions..please clarify my doubt sir..
The distance for the point load is zero. So no need to consider that
@@Stanacademy ok sir. Then If UDL is given then how will I consider distance x
@@Stanacademy please reply sir
@@naidurongali8732 You have to check which vertical reaction is high. You have to make a section on the half where reaction is high. Then find the distance and moment
We are considering upto the cross section only ,so we neglect the loads at that cross section
Hello Sir
I have small doubt
Maximum BM negative
X^2=29
2x=29
X=29/2=14.5
"But how to calculate"
X= 5.38
Please your valuable reply
I don't think you are very good at maths
X^2=29
X=√29
=5.38