Three Hinged Circular Arch - Problem No 1

A circular arched rib of 20 m span with central rise of 4 m is hinged at the crown and springings. It carries a point load of 100 KN at 5m from the left hand hinge. Calculate
The horizontal thrust of the arch
The reactions at the supports
Bending Moment, Normal Thrust and Radial Shear at 7m from the left hinge
The maximum positive and negative bending moment. Also draw the bending Moment Diagram

[@its_me0002]

For finding y we can also use Y=(√R^2 - X^2)-R+H

[@shaikshahida5464]

Thanks sir for making this video ,it helps me a lot

[@abhishekmugalakhod8762]

Please make more video on this topic..

[@NagarajuB-pz2fz]

Sir also explain semi circular arch with udl

[@Unknownrider124]

Thnku so much sir

[@naidurongali8732]

Sir.. in case of positive bending moment you didn't consider point load 100kn ..only you are consider horizontal and vertical reactions..please clarify my doubt sir..

[@Stanacademy]

The distance for the point load is zero. So no need to consider that

[@naidurongali8732]

@@Stanacademy ok sir. Then If UDL is given then how will I consider distance x

[@naidurongali8732]

@@Stanacademy please reply sir

[@Stanacademy]

@@naidurongali8732 You have to check which vertical reaction is high. You have to make a section on the half where reaction is high. Then find the distance and moment

[@shaikshahida5464]

We are considering upto the cross section only ,so we neglect the loads at that cross section

[@AnilNuthakki]

Hello Sir
I have small doubt
Maximum BM negative
X^2=29
2x=29
X=29/2=14.5
"But how to calculate"
X= 5.38
Please your valuable reply

[@unknownlad_]

I don't think you are very good at maths