5.2 Calorimetry | General Chemistry

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  • เผยแพร่เมื่อ 6 ก.พ. 2025

ความคิดเห็น • 38

  • @denisdeery5865
    @denisdeery5865 2 ปีที่แล้ว +36

    It's actually nuts that your channel isn't bigger chief. Everything I've had to cover this semester, you've conveniently got a concise video in a consistent format for. Gonna be binging your videos over summer to get ready for next semester.

    • @ChadsPrep
      @ChadsPrep  2 ปีที่แล้ว +5

      Thanks for saying so, D D - glad the channel is helping!

  • @Stee-Z
    @Stee-Z ปีที่แล้ว +10

    Chad, you are an incredible teacher. You explain things so well; I constantly have "eureka" moments when I watch your videos. Thank you so much.

    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว

      You're welcome - and Thank You.

  • @courtneyjohnson5529
    @courtneyjohnson5529 ปีที่แล้ว +3

    I'm in organic chem now and tutoring for general chem. YOU ARE A LIFESAVER CHAD!
    24 The Lord bless thee, and keep thee: 25 The Lord make his face shine upon thee, and be gracious unto thee: 26 The Lord lift up his countenance upon thee, and give thee peace. Numbers 6:24-26

    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว +1

      Thank you and To You as Well!

  • @thebutterflower
    @thebutterflower ปีที่แล้ว +8

    best calorimetry lesson i watched and it has been two days i was trying to learn this

    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว

      Thank you - glad it helped out!

  • @maishabinteyrahman1300
    @maishabinteyrahman1300 3 หลายเดือนก่อน

    No words, Just wanna say THANK YOU. YOU ARE AN AMAZING TEACHER CHAD!

    • @ChadsPrep
      @ChadsPrep  3 หลายเดือนก่อน +1

      You're welcome and Thank You!

  • @paarmyida
    @paarmyida ปีที่แล้ว +1

    Amazing lesson!
    I have exam in 4 days and now i can easily do the problems so a win for me
    Also i wanted to know if you have any plans on making playlists for subjects like inorganic or analytical chemistry? Because i definitely wouldn't want to lose any of that

  • @verano.violet
    @verano.violet ปีที่แล้ว +1

    Dude! You’re an amazing teacher. These videos are helping a TON in my engineering degree. How can I ever repay you?

    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว +7

      Study hard and succeed - or give me your first born. Either one will do. :-P

  • @Shaneliffin
    @Shaneliffin ปีที่แล้ว

    Bud is getting me through AP Chem- thank you so much 🙏🏿

    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว

      Glad the channel is helping you.

  • @Olric-c
    @Olric-c หลายเดือนก่อน

    hey Chad, i am wondering about 8:41 answer , i think we have to multiply by mole not divide to it.

  • @astrobiological7058
    @astrobiological7058 ปีที่แล้ว +2

    Great stuff Chad, you saved my life. Do you have scholarships/discounts for students who want to have access in your test bank and other resources? Thanks a lot.

    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว +1

      Send me an email: chad@chadsprep.com 😊

  • @allenhile4272
    @allenhile4272 ปีที่แล้ว +2

    Super super good video. Thanx!

    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว

      You're welcome and Thank You.

  • @michailtimanov1841
    @michailtimanov1841 6 หลายเดือนก่อน

    Great video on the topic!

    • @ChadsPrep
      @ChadsPrep  6 หลายเดือนก่อน

      Thank you!

  • @ashantimolebatsi2164
    @ashantimolebatsi2164 ปีที่แล้ว +1

    WOW this is really good

  • @duha_alkhaldi
    @duha_alkhaldi ปีที่แล้ว +1

    thank you so much for saving us

    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว

      You're welcome.

  • @paigethompson2890
    @paigethompson2890 6 หลายเดือนก่อน

    Do you know by change if qsurrounding and qsystem are proportional? I have been seeing qsys= -qsurrounding. I was wondering if it's the same as saying -qsys = -qsurrounding.
    I was doing a problem asking to solve for the enthalpy change of the system given information of everything about the solution. I solved it and got a positive answer but switched it to negative since I was assuming they were proportional.

  • @adlertelekom9359
    @adlertelekom9359 4 หลายเดือนก่อน

    One thing I find confusing. I was taught that a rise from 5°C to 8°C is a rise by 3 K (Kelvin). Because °C is absolute. A temperature of 0°C doesn't mean there is no temperature at all. In fact 0°C is 273.15 K. And a rise of 3°C means a rise of 276.15K resulting in a very high temperature.
    Also in my Chem books the specific energy for heating matter is given in J/(kg•K) 🤯

    • @ChadsPrep
      @ChadsPrep  4 หลายเดือนก่อน

      The important difference here is to make the distinction between the temperature and a change in temperature (such as a temperature rise). 5°C ~ 278K and 8°C ~ 281K. These are temperatures and to convert from Celsius to Kelvin we have to add 273.15.
      But when you look at the change in temperature. A change from 5°C to 8°C is a change of 3°C. On the Kelvin scale this is a change from 278K to 281K which is a change of 3K.
      The mistake that is easy to make is to take a temperature change of 3°C and add 273 and wrongly state that it corresponds to a change of 278 on the Kelvin scale. A change of 3 on the Celsius scale will still be a change of 3 on the Kelvin scale. This is why the specific heat has the same value whether we use units of J/(kg•K) or J/(kg•°C) as specific heat is defined as the amount of energy to CHANGE the temperature of 1g of a substance by 1 degree. Note that this is for a temperature CHANGE of 1 degree which is why it doesn't matter whether we use Kelvin or Celsius as the span between degrees is the same on both scales.
      Hope this helps!

  • @omerdemirkiranofficial
    @omerdemirkiranofficial หลายเดือนก่อน

    Hi Chat! I couldn't find final exam (general chemistry) preps on your website, can you help me on that?
    Thankss

    • @ChadsPrep
      @ChadsPrep  หลายเดือนก่อน

      They are in my premium General Chemistry Master Course after chapter 13 (for Gen Chem 1) and after chapter 21 (for Gen Chem 2). Hope this helps!

    • @omerdemirkiranofficial
      @omerdemirkiranofficial หลายเดือนก่อน

      @ChadsPrep oh I see thank you for replying quickly :) and your work helps a lot, praying for your health 🫶

  • @temidayooke6270
    @temidayooke6270 2 ปีที่แล้ว +1

    Awesome

  • @ceazerilukena
    @ceazerilukena ปีที่แล้ว

    Sir can you please share some worksheets if possible

    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว +1

      we don't have worksheets for the channel but they are available on our courses on chadsprep.com

  • @Moose2498
    @Moose2498 7 หลายเดือนก่อน

    Nature wants to demonstrate calorimetry!! 😅

    • @ChadsPrep
      @ChadsPrep  7 หลายเดือนก่อน

      Indeed!