No. We will get right half of a circle for above said limits ( which you are saying). But we want left half of circle. So we should take limits which are said in the video.
When we have a circle, it is always better to solve the integration using polar coordinates. To make the solution more simple we converted it in to polar coordinates.
Amazing lecture 🎉
sir, u made this topic very easy for me.thanks a lot for this wonderful explianation.
I think solving more examples will help my doubts because i think i understood you but i feel like you should solve more examples to clear my doubts😊
Good teaching and beautiful handwriting 🙏
Thank you
Sir you explained well ❤
thank you for clearing my doubt
Thank you sooo much sir ❤
Useful❤
Thank you sir 🙏
Sir if the limit ranges for -1 to 1 the what will be the area
super sir
VERY HELPFUL
Thank you
Why did you get a negative result for area?
Here region lies between x= -1 and x=0. So it lies in left hand side of y axis.
@@ranjankhatu can we get area negative ?
@@ranjankhatusir aapne limits bottom to top and left to right nahi likhi isliye answer negative aaya h
thanks brooooo hi from turkey muğla sıtkı koçman university
Thank you!
at 6:01 it was integral of r not r^2
Yes I was too confused
Shi kya h ??
Sir how to find limit of a parabola in double integral
Thank you sir 🙇🏻♂️🙏🏻
Most welcome
sir, how to know how to integrate r^2 from pi/2 to 3pi/2 or from 0 to 1?
Limits of theta will be in terms of pi and limits of r will be like 0 to 1 or in terms of theta.
Sir can we take limit from -π÷2 to π÷2 ????
No. We will get right half of a circle for above said limits ( which you are saying). But we want left half of circle. So we should take limits which are said in the video.
Why we converted
When we have a circle, it is always better to solve the integration using polar coordinates. To make the solution more simple we converted it in to polar coordinates.
@@ranjankhatu thank you so much ❤️
Hindi nhi ati hai kya sir
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Sir hindi me boliye plzzz😖