Anode kaise Hoga Jabki use bettery ke negative terminal se joda gya h Aur grid electron ko accelerated kaise karega ...grid me aisa kya h Jo electron ko accelerate Kar de
Election attained the higher energy level so they are stable at that moment. When they were stable then atom stops to emit electron. So current fall down...
Kyunki discrete amount ma hi energy absorb ya emit Kar Sakta h isliye. Aur jyada jaanna chahte h toh spectroscopy playlist ma absorption and emission spectrum wala video dekhe
@@sushma8080 Discrete in the sense..... an integral multiple of 4.9 (here if you notice in the graph the current drops at 4.9 and then again at 4.9 x 2 = 9.8 so current can drop only at integral multiple of 4.9 that is 4.9, 9. 8, 14.4,19.2 etc and not like 1.2 X 4.9 or 2.3 X 4.9) an electron can stay in integral values of fixed energy levels( which is 4.9 in this case)
Sir aapne kaha ki electron jb excited state me jata h to or enery absorb nhi krta, esa kyu? Ek or chij yadi e- 1st excited state se 2nd excited state me pahuchana hai to enery to deni paregi or jbtk o enery absorb nhi krega tbtk 2nd excited state me pahuchega hi nhi, lekin esa to hota nhi. Please explain i am confusing
All the peaks is corresponding to 1st excited state, not other higher state. Because the difference between two successive peaks is 4.9ev(i.e, 9.8-4.9=4.9,,, 14.7-9.8=4.9) which is the value of 1st excited state of Hg. The concept is that if at 4.9ev , one atom of Hg is excited in 1st excited state , then at 9.8ev , two atom of Hg is excited in 1st excited state (4.9+4.9=9.8) ( not one atom in 2nd Or higher energy state) and so on.
@@ranjithvurs1086 what is your problem.I said my sir to solve my problem, don't u , , if you don't know any thing then keep silent, don't disturbed me . I hope you don,t know which subject belongs to this topic
Franck and Hertz noted in their first paper that the 4.9 eV characteristic energy of their experiment corresponded well to one of the wavelengths of light emitted by mercury atoms in gas discharges. They were using a quantum relationship between the energy of excitation and the corresponding wavelength of light, which they broadly attributed to Johannes Stark and to Arnold Sommerfeld; it predicts that 4.9 eV corresponds to light with a 254 nm wavelength.[2] The same relationship was also incorporated in Einstein's 1905 photon theory of the photoelectric effect.[12]
Mai aapko easy language ma samjhata ho Jaise atom ko Humne energy diya woh energy gain karke excited state ma aaega phir collision k baad energy lose kar dega jitna usne gain kiya tha ( same amount ) . Isse ye pata chalta h ki atom k discrete level ma energy hoti h
I got 4 out of 5 in my viva because of this man. A million thanks! 🙏
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Tomorrow is physics paper it's helps me a lot in last hour of revision
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Been struggling to find a good channel.. Finally found you thank you so much sir please baki topics laser ke bhi dal dijiye
Sir amazing explanation ...Allah apko iska ajer dy thanks a lot ..from pakistan
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You are a good teacher . Tomorrow is my exam and i am watching your video now 😂
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Anode kaise Hoga
Jabki use bettery ke negative terminal se joda gya h
Aur grid electron ko accelerated kaise karega ...grid me aisa kya h Jo electron ko accelerate Kar de
thanks a lot sir g
mere presentation ka bhi yahi topic h
Main n bohut search Kia
lekin apki video bahut achi thi
dua h Allah apko khush rakha
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Thank u so much sir apki vjh se ye experiment smjh pai hu 🙏
Great Explanation Sir and yes all Clear 😇😇
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JazakAllah...For good teaching
Last moment preperation channel 😅... Tysm sir ☺️ & yes everything is clear 😄
Why we used mercury vapour?
many many thanks for making helpful video for us.
Thanks 😊
1:38 why we cannot fix energy as 3.2 or in ration as such it is also fixed?
Yaha pe quantum mechanics aa jata hai jo classical se nahi samjha ja sakta hai
*8:37* this is not clear sirji ...
Thanks alot sir it's really helping for me ak e bar Agye smagh thanks alot n keep doing box you're are doing great job.
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Well explained big respect from Pakistan
Thanks ❤️😊
Thank you so much sir g buhat achi video hai 💖💖💖
But how it proved the exited state of mercury
Thanks a lot now I can confidently give presentation on this topic
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Why current dropped to zero..... We are increasing voltage.... So how it could possible
Election attained the higher energy level so they are stable at that moment. When they were stable then atom stops to emit electron. So current fall down...
Perfectly explained!!!!!👌👌👌
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Sir g electron 4.9 volts par hi q apni apni energy loose krta ha. Is ka pecha Ka reason btain. Or us waqt inelastic collision hi q hota ha?????
Kyunki discrete amount ma hi energy absorb ya emit Kar Sakta h isliye. Aur jyada jaanna chahte h toh spectroscopy playlist ma absorption and emission spectrum wala video dekhe
@@Eduphile but you said discrete means 1,2,3,4..... not 1.2, 2.3, 3.3 or 4.9 etc so in this case you are saying 4.9v is discrete. how?
@@sushma8080 dekhiye aap Sahi bol rahe h , humne toh bus ek example Diya tha , discrete Ka matlab aisi values jinki beech ma koi value na ho
@@sushma8080 Discrete in the sense..... an integral multiple of 4.9 (here if you notice in the graph the current drops at 4.9 and then again at 4.9 x 2 = 9.8 so current can drop only at integral multiple of 4.9 that is 4.9, 9. 8, 14.4,19.2 etc and not like 1.2 X 4.9 or 2.3 X 4.9) an electron can stay in integral values of fixed energy levels( which is 4.9 in this case)
@@heheyoitsme1590 well explained, thanks :)
Sir aapne kaha ki electron jb excited state me jata h to or enery absorb nhi krta, esa kyu?
Ek or chij yadi e- 1st excited state se 2nd excited state me pahuchana hai to enery to deni paregi or jbtk o enery absorb nhi krega tbtk 2nd excited state me pahuchega hi nhi, lekin esa to hota nhi. Please explain i am confusing
Directed ground se higher state ma jata h electron
Ya toh first , ya second
Depend karta h energy kitna mil raha h
Very well explained sir g💕💕💕💕💕8️⃣
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Nice explain
Really an amazing video sir. Explained very well.
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is that clear is word of repeatition !!
You are so intelligent bro. Love from Bangladesh ♥️🙏
Level ha sir ji kamal ka samjaya ha ye ab nhi bhoole ga
you have
Amazing skills of teaching
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Please make this explanation more clear by taking into account electronic transitions from different levels
Sir aik reason bathain kay elastic collision ma tu electron ki direction change hoti hai tu woh anode tak kiasy jata hai plz sir reply karhain
Is that clear? 😂😂😂Zbrdst bhaiya
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Mercury hi kyu fill krte h Ar b to kr skte h sir
Is that clear 😂
😅😅
😂
It's not the matter of any joke
@@EduDose517 nikal sale..😂
🤣yes! but video is to good
Sir quantized means fixed hota hai kya
Quantised Ka matlab fix level hota h
Very helpful video 👍👍
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Do the all tree peaks in graph belong to first excited state or first,second,third excited state respectively?? Please answer with explaination!
In all excited states
All the peaks is corresponding to 1st excited state, not other higher state. Because the difference between two successive peaks is 4.9ev(i.e, 9.8-4.9=4.9,,, 14.7-9.8=4.9) which is the value of 1st excited state of Hg. The concept is that if at 4.9ev , one atom of Hg is excited in 1st excited state , then at 9.8ev , two atom of Hg is excited in 1st excited state (4.9+4.9=9.8) ( not one atom in 2nd Or higher energy state) and so on.
Excellent explanation sir ji
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Sir u have missed to say one things in graph that if current become zero then why not graph touch the x-axis
Lawde....jyada gamand matth dhikaav
@@ranjithvurs1086 what is your problem.I said my sir to solve my problem, don't u , , if you don't know any thing then keep silent, don't disturbed me . I hope you don,t know which subject belongs to this topic
I think sir mentioned here it almost becomes zero, so maybe sir meant on reaching hat FIXED voltage, current rating falls down eventually !!
Thnkxx sir bht acha apne samjhaya
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Thank you so much.. It was really good !
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sir please black body rediation pe banao video sir
Yes Sir Clear😃😇
Why current drops only at multiples of 4.9
Franck and Hertz noted in their first paper that the 4.9 eV characteristic energy of their experiment corresponded well to one of the wavelengths of light emitted by mercury atoms in gas discharges. They were using a quantum relationship between the energy of excitation and the corresponding wavelength of light, which they broadly attributed to Johannes Stark and to Arnold Sommerfeld; it predicts that 4.9 eV corresponds to light with a 254 nm wavelength.[2] The same relationship was also incorporated in Einstein's 1905 photon theory of the photoelectric effect.[12]
Helpful lecture
Thanks and welcome
Thanks sir is that clear
nice explanation sir. but sir the current draft on 4.5. and then how draf on 9.4
Ek baar me clear 🙌
Thanks 😊
Very helpful sir💐
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BAHPPT ACHA SIR!!!!!!!! SAMAJ AYA
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Is that clear?
Anode pani negative and cathode is also negative but how
8:47 sir g whole atom will go to exited state or only electron of this atom ?
Electron in the atom , so we can say atom
@@Eduphile how sir g? Couldn't got
Electron excited hoga aur Woh atom Ka part h isliye hum kah sakte h atom excited h,
Tnx and tnx
thanks boss
Nice explanation 👍
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Yes sir is that clear
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Sir graph me doubts hai please ashe se explt krdo
Thank you very much sir
Vvvvvvvvv nice explanation ...
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Your voice is so nice
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Bahut acha video है
Perfect explanation... thanks
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Mst mst mst bhaiya samajh aa gya
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JAI GORISHANKAR JI JAI RADHESHYAM JI😍😍😍😍😍
👍👍
Sir elastic Collison may speed change ni hoti but inelastic Collison may speed change hoti h q???
😂🤣
Sr is topic k 20,25 mcqs bna k samjha den,, thanks
I shall try
Thank you sir ❤
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very nice explanation!!
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Sir pahly ap na kha k energy quantized ho 2 3 4 fix ho pher 4.9 ko lay ay ya smjh ni a rha
Woh toh example Diya tha dost , 4.9 h toh iske baad Kuch value hogi
Great information
Confidential to present dis topic 😍
That's Great . Thanks
Hi
Very good explanation
Thanks sir 😊🙏
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was that clear???
Mai aapko easy language ma samjhata ho
Jaise atom ko Humne energy diya woh energy gain karke excited state ma aaega phir collision k baad energy lose kar dega jitna usne gain kiya tha ( same amount ) . Isse ye pata chalta h ki atom k discrete level ma energy hoti h
But also when the voltage is increasing as we see after 4.9 then the current also increase and then decrease why
First decrease and then increase why
Concept of ground state and excited state
4.9 qunatized energy level kese hua
nice explanation
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Very good sir ji
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👌nice video
Thanks❤
You're welcome 😊
Best
No doubt sir .Thanks
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It is clear😊
Thanks ☺️
Clear 👍
Thank you sir
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Thanku soo much sir....
It clears my all doubt.
Thanks alot. ☺
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Thank u so much sir
Very nice
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thank you sir, love from nepal
Bhaiya aap odisha se ho kya
Nhi dost , Lucknow UttarPradesh but pura India mera ghar h ❤️
Before exam🙂
All the best
I got the concept sir.....thanku sir jii
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Thanks sir
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yes that is clear😉😉😉
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Thks sir u have clear the dots
thanks sir.
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Thanks least time me mera kam ho gaya
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Clear for myself sir..
Clear and thank u
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Good sr
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Is that clear? 😑
1 Hour Before Exam 😅