PUSHDOWN AUTOMATA EXAMPLE - 2 (a^n b^m c^n) | PDA EXAMPLE - 2 | TOC
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- เผยแพร่เมื่อ 26 ส.ค. 2024
- Pushdown Automata is a finite automata with extra memory called stack which helps Pushdown automata to recognize Context Free Languages.
A PDA can be formally described as a 7-tuple (Q, ∑, S, δ, q0, I, F) −
Q is the finite number of states
∑ is input alphabet
S is stack symbols
δ is the transition function: Q × (∑ ∪ {ε}) × S × Q × S*
q0 is the initial state (q0 ∈ Q)
I is the initial stack top symbol (I ∈ S)
F is a set of accepting states (F ∈ Q)
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I got placed in TCS your videos helped me a lot Thank you sir🙏
Hi sriram bro please reply me
Easy to learn from your videos Sir .
it was really easy to understand and you tried to tell the idea of solving these questions .thank you very much sir .
(q1,b,q)=(q2,a) is missing sir.
Sir second steplo Z0 enduku pettaledu
how to solve if the question is a^n b^m a^n | m,n >=1
what do we pop in this case?
It's the same thing, man. Just a is replaced by c. You can follow the same procedure.
I'm replying for ur comment after 2 years. HAHAHAH!!!!
easy and comprehensive thanks sir
THANK YOU SIR
Thank you sir 10:39
Sir please explain transition diagram also..
Could u increase the size of the letters pleased.
What will happen when aaabbbccc will give as string
bbb will act as pop. What Abt ccc? Which state act as final state
Your board would not clear all the time, y?
Sir draw the pda diagram,it's the main thing ,I think so