Shortcut: for X to the power of 3 to end with 7, X must end with 3 only. Since evidently 900 < X < 1000, then X = 9a3. The long number being close to 1 billion, start from the top with a = 9. Oh look, 993 to the power of 3 is equal to the long number. But okay :)
Shortcut: for X to the power of 3 to end with 7, X must end with 3 only. Since evidently 900 < X < 1000, then X = 9a3. The long number being close to 1 billion, start from the top with a = 9. Oh look, 993 to the power of 3 is equal to the long number. But okay :)
993
Try: (37,171,755,605,146,553)^(1/3)....