@@centreforengineeringstudies Sir, in forced response question, values of c1 and c2 can't be found. I think this is true for all values of c1 and c2. For this question, the solution will remain as it is with arbitrary constants c1 and c2. As you told to put the values of y[0],y[1], y[2], y[3] in those 2 equations, when we put them, we get nothing out of there. I think this is because we're putting the values of forced response( y[0],y[1], y[2], y[3]) back into the equation, they completely satisfy the equation and c1, c2 don't remain any longer in that equation. Please correct me wherever I'm wrong.
c1 and c2 can be found by writing the final equation for y[n] in terms of natural + forced response and put y[-1] = 1 and y[-2] = 0. y[n] = ( 2 (1)^n - 1/2 (1/2)^n ) + ( c1 (1)^n + c2 (1/2)^n + 8/3 2^n ) where first term ( 2 (1)^n - 1/2 (1/2)^n ) is the natural response and second term ( c1 (1)^n + c2 (1/2)^n + 8/3 2^n ) is the forced response.
How did you get the value of c1 & c2 in forced response....the equation doesn't satisfy the condition.
great content.
But I really like the way of your teaching.
The second guy about which u are forgetting is "tangent".
😂
Sir I've wasted 2 hrs and got to the conclusion that u were teaching wrong😭😭😭
Which topic you found wrong?
@@centreforengineeringstudies Sir, in forced response question, values of c1 and c2 can't be found. I think this is true for all values of c1 and c2. For this question, the solution will remain as it is with arbitrary constants c1 and c2.
As you told to put the values of y[0],y[1], y[2], y[3] in those 2 equations, when we put them, we get nothing out of there. I think this is because we're putting the values of forced response( y[0],y[1], y[2], y[3]) back into the equation, they completely satisfy the equation and c1, c2 don't remain any longer in that equation.
Please correct me wherever I'm wrong.
@@MOHD_JUNAID_19 please proceed in the next lecture I have done it.
@@MOHD_JUNAID_19 please check the next lecture I have corrected it.
c1 and c2 can be found by writing the final equation for y[n] in terms of natural + forced response and put y[-1] = 1 and y[-2] = 0.
y[n] = ( 2 (1)^n - 1/2 (1/2)^n ) + ( c1 (1)^n + c2 (1/2)^n + 8/3 2^n )
where first term ( 2 (1)^n - 1/2 (1/2)^n ) is the natural response and second term ( c1 (1)^n + c2 (1/2)^n + 8/3 2^n ) is the forced response.