(x^2+y^2+2x)dx+2ydy=0

#nonexactequation reducibletoexact
Hello, People!
Here is a video of solving non-exact equation, by reducing the given equation exact form. Have a little patience and watch the video till end.
My hearty thanks to all the subscribers, supporters, viewers and well-wishers❤
With Love,
Chinnaiah Kalpana🍁
Note:
If (1/N)[(partial derivative of M w.r.t. y) - (partial derivative of N w.r.t. x)] = f(x) [i.e., a function of x only] (or) k [real number] ,
then exp(∫f(x)dx) (or) exp(∫kdx) is an integrating factor of Mdx+Ndy=0.
exp(log f(x)) = f(x)
& exp(k logx) = exp[log(x^k)] = x^k
where k is constant.
Working rule to solve Mdx+Ndy=0:
1. General equation is Mdx+Ndy=0 ......(i) Observe (partial derivative of M w.r.t. y) ≠
(partial derivative of N w.r.t. x), then (i) is Non-Exact.
2. Find (1/N)[(partial derivative of M w.r.t y) - (partial derivative of N w.r.t x)] and observe it as a function of x alone = f(x) or a real constant k.
3. Then exp(∫f(x)dx) or exp(∫kdx) is an Integrating factor of (i).
4. Multiplying (i) with I.F. to transform it into an exact equation of (i), M1dx+N1dy=0 ...(ii)
5. Solve (ii) to get the general solution of (i).
For more such videos 👇
• Differential Equations...
Stay tuned to 'Maths Pulse'.
Get rid of 'Maths Phobia'.
Have a happy learning!
#differentialequations #mathspulse #chinnaiahkalpana #nonexactproblems #engineeringmathematics #bscmaths #maths #math