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Awesome thank you so much❤❤
Thank you! Please help me share the video with others 😁👍
Love it ❤
Thank you! Please help me share my video as well! 👍😁
Shouldn't you check all solutions plugging them into the equation to see whether they are extraneous?
We did. That's when we tested points
How would you do it if it were subtraction of absolutes instead of addition
when doing the different cases, why does it have to be an equation (=)? is it not possible to retain the signs and solve it like a regular inequality?
If on R.H.S has > 8 then what will be the cases to solve the question
Good question! The process is similar, but we want the sum of the absolute values to be greater than 8.
If we have 0 instead of 8 and it is just |x+3| + |x-1|
Correct! In that case, we only consider the equation. And no need to test points since |x+3| and |x-1| must be both zero at the same time in order for the equation to be true. Can we get a solution then?
why do we need to draw the number line if u already got x=3,=5? cant u just automatically make the link to [-5,3]
Because the solution could been (-inf, -5] or [3, inf), so we need to test points and check.
does it always work?
Yeah, for this type.
Nice
Thank you!
in VIET NAM , we have x+3+x-1 = 8 and -8 . that enought
Ok!
i love you
Thank you! Please help me share my video 😁👍
try and solve something like |x+1|>|x+3|
If we move |x+3| to the left side, it is similar to the question in this video.
Number line before -5 y isn't it in solution
Abanga
?
劉有吟
我是她女兒 0:02
??
Awesome thank you so much❤❤
Thank you! Please help me share the video with others 😁👍
Love it ❤
Thank you! Please help me share my video as well! 👍😁
Shouldn't you check all solutions plugging them into the equation to see whether they are extraneous?
We did. That's when we tested points
How would you do it if it were subtraction of absolutes instead of addition
when doing the different cases, why does it have to be an equation (=)? is it not possible to retain the signs and solve it like a regular inequality?
If on R.H.S has > 8 then what will be the cases to solve the question
Good question! The process is similar, but we want the sum of the absolute values to be greater than 8.
If we have 0 instead of 8 and it is just |x+3| + |x-1|
Correct! In that case, we only consider the equation. And no need to test points since |x+3| and |x-1| must be both zero at the same time in order for the equation to be true. Can we get a solution then?
why do we need to draw the number line if u already got x=3,=5? cant u just automatically make the link to [-5,3]
Because the solution could been (-inf, -5] or [3, inf), so we need to test points and check.
does it always work?
Yeah, for this type.
Nice
Thank you!
in VIET NAM , we have x+3+x-1 = 8 and -8 . that enought
Ok!
i love you
Thank you! Please help me share my video 😁👍
try and solve something like |x+1|>|x+3|
If we move |x+3| to the left side, it is similar to the question in this video.
Number line before -5 y isn't it in solution
Abanga
?
劉有吟
我是她女兒 0:02
??