Yes gopinath, we do rotation to bring two molecules in similar conformation, and then check whether they are superimposable(identical) or mirror images (enantiomer)
The OH is always left to CHO, if you see from CHO perspective, bond connectivity is the same... But we have just rotated CHO. So the group connected to CHO will also rotate na? Try it on pen paper :) Still if problem in unterstanding, I'll send you further image on telegram group
Thank you so much madam... Very Nice...
Thanks you so much ma'am 🙏
Very halpfull ma'am Thankyou
Thank u so much mam
Maam in first when we consider fischer projection we get R, otherw ise we get S bcz lowest priority gp is not in backward position
Mam I have very simple doubt that why we should do the rotation all the time will you please explain this
Yes gopinath, we do rotation to bring two molecules in similar conformation, and then check whether they are superimposable(identical) or mirror images (enantiomer)
Too good
Thanku MA it very helpful for me and give me some more important practice sheet please
Good morning MA practice sheet open Nhi ho raha h
drive.google.com/file/d/1OB-gEw-_2FMTYdsmeYWs8wZf9H-jOJ8g/view
Thanku ma
Surendra Kumar prajapti
Ma'am I think you did rotation wrong for 5th one , C is the right answer
Please try once again, I think it's a
Ma'am molecule in question after changing to eclipsed form H is left to aldehyde ., But in option a ,H is right to aldehyde
How can both be same ?
The OH is always left to CHO, if you see from CHO perspective, bond connectivity is the same... But we have just rotated CHO. So the group connected to CHO will also rotate na? Try it on pen paper :)
Still if problem in unterstanding, I'll send you further image on telegram group
I love you too mam