Q. 4.1: Consider the combinational circuit shown in Fig. P4.1.(a)* Derive the Boolean expressions fo

[@PathumAddarapathirana]

F2 is A'B + D' (you drew the circuit wrong. There is a NOT before D goes into the OR.

[@engineering5423]

Yes bro

[@sametdemirtop7578]

Where is D' for T5 ?

[@intizarrahim]

I couldnt understand the Truth Table for this question sir.

[@purbadhar2936]

How can u made this truth table?

[@natt5chanel583]

If the question is this drive the boolean expression for T1 through T2 then it is same or any changing

[@mohsinali12145]

Thanks sir 😀😀😀

[@sirichandana605]

Thank you sir

[@lgodlike2324]

Thank you really really much !

[@jayeshroshiya6164]

thank you

[@darrenanderson5710]

Why didn't you factorize the in the F1 "B'C + B'D" to equal B'(C+D)

[@alaa7464]

bcz there is no use of it, i mean nothing gonna be simplifed as for example when it is (A+A')that will equal 1

[@cataclysmicbane9068]

Thank you!

[@klentjosephrojo1328]

Thank you

[@DrDhimanKakati]

You're welcome

[@d.aditya1398]

thotla 😗😗

[@nightbot1458]

F2 Circuit is wrong