Aerodynamic forces and torques with PARAVIEW

แชร์
ฝัง
  • เผยแพร่เมื่อ 8 ก.พ. 2025

ความคิดเห็น • 14

  • @aeronerd22
    @aeronerd22 ปีที่แล้ว

    I have referenced this video multiple times. THANK YOU! :)

  • @KyleDunnIt
    @KyleDunnIt 2 ปีที่แล้ว

    Thank you for sharing, this is very well explained and to-the-point.

  • @cfd-ingenieria6686
    @cfd-ingenieria6686 6 ปีที่แล้ว

    Hello friend, this is a good video, I learned from you. Only one thing, torque is a product of rxf and in your video you put Fxr.

    • @RzogL
      @RzogL 3 ปีที่แล้ว

      Yes, but he was also defined r from the origin to the force application point, which is the wrong way round. Since AxB = - BxA, his Fxr works out the same as RxF, if R is defined as coords-0*iHat-0*jHat-0*kHat.

  • @adrianoscarano2527
    @adrianoscarano2527 2 ปีที่แล้ว

    Thank a lot for the video but I have a question: I have a stirred tank with an emispherical bottom where the origin of axes is a the lowest point of this bottom, to evaluate the torque, should I change the cross product? Or does it remains always "0*iHat+0*jHat+0*kHat-coords"?
    I hope my question is clear. Thank you very much in advance

  • @madhankumar59
    @madhankumar59 7 ปีที่แล้ว +1

    Your video is great, However i have one doubt. To calculate force you are adding (p*normals+wallshearstress). The unit of wallshearstress is N/m2. It is stress, how we can say it as force. Please clarify.

    • @ConselfCompany
      @ConselfCompany  7 ปีที่แล้ว +1

      Remember that after that operation everything there is a surface integrals!

    • @madhankumar59
      @madhankumar59 7 ปีที่แล้ว

      CONSELF Thank you very much

    • @HoaiThanh-wm6ze
      @HoaiThanh-wm6ze 11 หลายเดือนก่อน +1

      @@ConselfCompany I think the force (p*normals-wallshearstress)*rho. ???

  • @gatbik2615
    @gatbik2615 7 ปีที่แล้ว

    thank you for the great video! But i have a additional question: how can i calculate my thrust for a Propeller from my forces?
    thank you very much :)

    • @ConselfCompany
      @ConselfCompany  7 ปีที่แล้ว

      Well .. it's not very difficult ... thrust is the product between mass flow and velocity ... so you can use filters similar to the ones used in here to obtain the result you want!

  • @civilibot
    @civilibot 6 ปีที่แล้ว

    How can I download the file?

  • @hansenkhornelius
    @hansenkhornelius 3 ปีที่แล้ว

    hi, can we calculate where the centre of lift is?
    thank you

    • @Cuneyto12
      @Cuneyto12 ปีที่แล้ว

      Hello , I want to determine the centre of lift either but couldnt find yet. Do you know how to find that, thanks in advance.